河南省武陟县第一中学(原河朔一中)2015-2016学年高一上学期第二次月考化学试题

河朔一中2015级第二次月考试卷相对原子质量：H 1 C 12 O 16 Na 23 Mg 24 Al 27 S 32 Cl 35.5 K 39 Cu 64 一、选择题（共20小题，每题3分）1、在生产生活中，对于易燃、易爆、有毒的化学物质，按规定会在其包装上面贴上危险警告标签。

下面所列物质，贴错了包装标签的是( )2、下列事故或药品的处理正确的是（ ）A ．少量浓硫酸沾到皮肤上，立即用氢氧化钠溶液冲洗B ．制取并收集氧气结束后，应立即停止加热C ．当出现CO 中毒时，应立即将中毒者抬到室外新鲜空气处D ．将含硫酸的废液倒入水槽，用水冲入下水道3、下列对于“摩尔”的理解正确的是（ ）A ．摩尔是国际科学界建议采用的一种物理量B ．摩尔是物质的量的单位，简称摩，符号为molC ．摩尔可以把物质的宏观数量与微观粒子的数量联系起来D ．国际上规定，0.012 kg 碳原子所含有的碳原子数目为1摩尔4、用托盘天平称取10.1gNaOH 试样，下列操作中，正确的是 ( )A ．将NaOH 放在天平左边托盘中的纸片上B ．用镊子取出标定为10.1g 的砝码放在天平右边的托盘上C ．将NaOH 放入烧杯中（烧杯事先已称重），并放在天平右边托盘上D ．将NaOH 放入烧杯中，若烧杯质量为42.5g ，则应将游码向右移到2.6g 位置上5、下列仪器用酒精灯加热时，需垫石棉网的是( )①烧杯 ②坩埚 ③锥形瓶 ④蒸发皿 ⑤试管 ⑥烧瓶 ⑦表面皿A ．②④⑤ B．①⑥⑦ C．③④⑥ D．①③⑥ 选项A B C D 物质浓硫酸 汽油 酒精 氯酸钾 标签6、选择萃取剂将碘水中的碘萃取出来，这种萃取剂应具备的性质是（）A．不溶于水，且必须易与碘发生化学反应B．不溶于水，且比水更容易使碘溶解C．不溶于水，且必须比水密度大D．不溶于水，且必须比水密度小7、不用其它试剂鉴别(1)K OH (2)NaCl (3)MgSO4(4)Cu(NO3)2四种溶液,正确的鉴别顺序是( ) A．(1)(4)(3)(2) B．(4)(1)(3)(2) C．(4)(2)(1)(3) D．(1)(3)(4)(2)8、用可溶性钡盐检验S O42-离子的存在时，先在待测溶液中加入盐酸，其作用是 ( ) A．形成较多的白色沉淀 B．排除SO42-以外的其它阴离子及Ag+的干扰C．形成的沉淀纯度更高 D．排除Ba2+以外的其它阳离子的干扰9、设N A表示阿伏加德罗常数，下列叙述正确的是（）A．标准状况下，2.24L CCl4所含的原子数为0.5 N AB．0.5 mol O2含氧原子数为0.5N AC．2.4 g金属镁变为镁离子时失去的电子数为0.1N AD. 氧气和臭氧的混合物16 g中约含有N A个氧原子10、相同质量的SO2和SO3它们之间的关系正确的是 ( )A．所含硫原子的物质的量之比为1:1 B．氧原子的物质的量之比为3:2C．氧元素的质量比为5:6 D．硫元素的质量比为4:511、标准状况下，下列物质占体积最大的是（）A. 98g H2SO4B. 1N A个CO2C. 44.8LHClD. 6gH212、下列有关气体体积的叙述中，正确的是（）A．一定温度和压强下，气体体积的大小，由构成气体的分子大小决定B．一定温度和压强下，气体体积的大小，由构成气体的分子数决定C．不同的气体，若体积不同，则它们所含的分子数也不同D．气体摩尔体积指1mol任何气体所占的体积约为22.4L13、下列关于容量瓶及其使用方法的叙述，正确的是（）①是配制一定物质的量的浓度的溶液的专用仪器②容量瓶可以用来加热③使用前要先检查容量瓶是否漏液④不能用容量瓶贮存配制好的溶液⑤可以用500mL容量瓶配制250mL溶液A.①和②B. ①和⑤C. 除了③D. 除了②⑤14、实验室需用480mL0.1mol/L的硫酸铜溶液，以下操作正确的是 ( )A．选用480 mL容量瓶，称取12.0g硫酸铜，配成480mL溶液B．选用250 mL容量瓶，称取12.5g胆矾，配成500mL溶液C．选用500 mL容量瓶，称取12.5g胆矾，加入500mL水D．选用500 mL容量瓶，称取12.5g胆矾，配成500mL溶液15、将40克NaOH溶于水配成1L溶液，则该溶液的物质的量浓度为（）A．0.1mol/L B．0.5mol/L C．4mol/L D．1mol/L16、有K2SO4和Al2(SO4)3的混合溶液，已知其中Al3＋的物质的量浓度为0.4mol·L－1，SO42-的物质的量浓度为0.7mol·L－1，则此溶液中K＋的物质的量浓度（mol·L－1）为（）A．0.1 B．0.15 C．0.2 D．0.2517、配制一定物质的量浓度的某溶液，下列情况会使配置结果偏低的是（）A.未冷却就转移、定容B. 未洗涤烧杯及玻璃棒C. 定容时俯视刻度线观察液面D. 容量瓶原有少量蒸馏水18、实验室使用的浓硫酸的溶质质量分数为98%，密度为1.84g/cm3,则物质的量浓度为（）A. 18.4B. 18.4mol/LC.1.84mol/LD. 无法计算19、下列四样溶液中，c(H+)浓度最大的是（）A. 50mL 1.0mol/L的HClB. 10mL 2.0mol/L 的NaClC. 20mL 1.5mol/L 的HNO3D. 10mL 1.0mol/L的H2SO420、现有A、B、C三种化合物，各取40g相混合，完全反应后，得到18.0g B、49.0g C、还有D生成，已知D的相对分子质量为106。

高中数学学习材料鼎尚图文*整理制作河南武陟二中高一数学第二次月考试题（集合与函数单元测试题）命题人：张进涛一、选择题：（本大题共12小题，每小题5分）1.设全集}7,6,5,4,3,2,1{=U ，集合}5,3,1{=A ，集合}5,3{=B ，则 （ ）A ．B A U ⋃= B ． B AC U U ⋃=)( C ．)(B C A U U ⋃=D ．)()(B C A C U U U ⋃=2.集合{|22},{|13}A x x B x x =-<<=-<≤，那么A B = （ ）A 、{|23}x x -<<B 、{|12}x x <≤C 、{|21}x x -<≤D 、{|23}x x << 3.下列五个写法：①}3,2,1{}0{∈；②}0{⊆φ；③{0，1，2}}0,2,1{⊆；④φ∈0；⑤φφ=⋂0，其中错误．．写法的个数为（ ） A. 1 B. 2 C . 3 D. 44.已知集合{(,)|2},{(,)|4}M x y x y N x y x y =+==-=，那么集合MN 为（ ）A 、3,1x y ==-B 、(3,1)-C 、{3,1}-D 、{(3,1)}-5. 设集合}21|{≤≤=x x A ，}41|{≤≤=y y B ，则5.下述对应法则f 中，不能．．构成A 到B 的映射的是 （ ）A 、2:x y x f =→B 、23:-=→x y x fC 、4:+-=→x y x fD 、24:x y x f -=→ 6. 下列各图形中，不可能是某函数)(x f y =的图象的是（ ）Oxy xy Oxy OxyOA B C D 7.下列各组中的函数)(x f 与)(x g 相等的是（ ）A x x f =)(，2)()(x x g =B 2)(x x f =，x x g =)(C 11)(2+-=x x x f ，1)(-=x x gD 0)(x x f =，xxx g =)(8.已知)1(,1)1(22++=-x f xx xx f 则的表达式为 （ ）A ．22)1(1)1(+++x xB ．22)1(1)11(xx x-+- C ．(x +1)2+2 D ．(x +1)2+1 9.下列四个函数中,在(0,+∞)上为增函数的是（ ） A.f (x )=3-xB.f (x )=x 2-3x C .f (x )= 11+-x D.f (x )=||x -10.若函数y=x 2+(2a －1)x+1在区间（－∞，2]上是减函数，则实数a 的取值范围是（ ） A ．[－23，+∞） B ．（－∞，－23] C ．[23，+∞） D ．（－∞，23]11.若函数3()()f x x x R =∈，则()y f x =-在其定义域上是（ ） A ．单调递减的偶函数 B. 单调递减的奇函数 C ．单调递增的偶函数 D. 单调递增的奇函数12.已知二次函数y=2x 2－1在区间[a ,b]上有最小值－1，是下面关系式一定成立的是（ ） A ．a ≤0<b 或a <0≤b B ．a <0<b C ．a <b<0或a <0<b D ．0<a <b 或a <b<0 二、填空题（每小题5分，共计20分）13满足条件{}{}1,21,2,3A =的所有集合A 的个数是 个14 函数42x y x -=-的定义域为___________________15.设偶函数f （x ）的定义域为R ，当[0,)x ∈+∞时f （x ）是增函数，则(2),(),(3)f f f π--的大小关系是16 已知y=f(x)是定义在R 上的奇函数，当0x ≥时，()2x -x x f 2=, 则()x f 在0<x 时的解析式是 _______________三.解答题17. （共10分）已知全集I=}32,3,2{2-+a a ，若}2,{b A =，}5{=A C I ，求实数b a ,18.（共12分）已知集合，，，求实数的取值范围19.（12分）已知函数f （x ）=xx 1+. （1）判断()f x 在其定义域上的奇偶性；（5分）（2）判断f （x ）在（0，+∞）上的单调性并加以证明.（7分）20.（共12分）已知二次函数()f x 满足(0)1f =及(1)()2f x f x x +-=， （1）求()f x 的解析式；（6分）（2）求()f x 在区间[]1,1-上的最大值和最小值。

武陟一中高三第一次月考语文试卷说明：本试卷分第一卷和第二卷两部分，满分150分，考试时间150分钟。

第一卷（选择题，共30分）一、基础知识（21分，每小题3分）1、下列的字的读音中有两个错误的一项是A．鱼凫（fú）馔（zhuàn）玉声啾(qiū)啾官应(yīng)病休B．猿猱（náo）欢谑（nuè）只旧醅(pēi) 盘飧(xī)市远C．石栈(jiān) 金樽(zūn) 东南坼(chè) 砯(pīng)崖转石D．巉(chán)岩荆杞(qǐ) 请(qīng)进酒扪参(shēn)历井2、下列词语中没有错别字的一组是A．靓丽融洽青砖墁地繁文缛节B．缉捕陷井秀外慧中临摹碑贴C．通谍谩骂莫衷一是明查暗访D．蜇伏拾掇翻云覆雨揭竿而起3、下列加点词（字）意义解释正确的一组是A．奉献．．．．（信奉公平，遵守法令）．．（恭敬地交付）奉公守法信奉．．．．（把某些言论或事物当作准则）．．（相信并奉行）奉为圭臬B．截至．．（停止）斩钉截铁．．．．（形容说话办事坚决果断）截取．．．．（比喻用长处补短处）．．（从中取一段）截长补短C．出．（来到）席井井．．（整齐不乱的样子）有条初．（第一）级浩．（多）如烟海D．苦楚．（痛苦）纨绔．．（细绢做成的裤子）子弟）挡．（遮蔽）风放．（放纵）言高论4、与“可以横绝峨眉颠”的“绝”的意义相同的一项是A．今杀相如，终不能得璧之，而绝秦赵之欢B．夜久语声绝，如闻泣幽咽C．因而化怒为悲，抢呼欲绝D．假舟楫者，非能水也，而绝江河5、依次填入下列各句横线处的词句，最恰当的一组是①在赏读古诗词时，我们耳边常会响起诗人们放达的歌声，“＿＿”就是这种情怀的体现。

②小王设计的文案终于获得通过，他难以＿＿自己喜悦的心情，忽地站起来大呼：“成功啦！”③然而，我＿＿从来没有问过父亲的生日在哪一天，＿＿没有为他庆祝过一次生日，这一切现在都已成为无法弥补的遗憾。

河南武陟二中高一数学第二次月考试题（集合与函数单元测试题） 命题人：张进涛一、选择题：（本大题共12小题，每小题5分）1.设全集}7,6,5,4,3,2,1{=U ，集合}5,3,1{=A ，集合}5,3{=B ，则 （ ） A ．B A U ⋃= B ． B A C U U ⋃=)( C ．)(B C A U U ⋃= D ．)()(B C A C U U U ⋃=2.集合{|22},{|13}A x x B x x =-<<=-<≤，那么A B = （ ）A 、{|23}x x -<<B 、{|12}x x <≤C 、{|21}x x -<≤D 、{|23}x x <<3.下列五个写法：①}3,2,1{}0{∈；②}0{⊆φ；③{0，1，2}}0,2,1{⊆；④φ∈0；⑤φφ=⋂0，其中错误．．写法的个数为（ ） A. 1 B. 2 C . 3 D. 44.已知集合{(,)|2},{(,)|4}M x y x y N x y x y =+==-=，那么集合MN 为（ ）A 、3,1x y ==-B 、(3,1)-C 、{3,1}-D 、{(3,1)}-5. 设集合}21|{≤≤=x x A ，}41|{≤≤=y y B ，则5.下述对应法则f 中，不能．．构成A 到B 的映射的是 （ ）A 、2:x y x f =→B 、23:-=→x y x fC 、4:+-=→x y x fD 、24:x y x f -=→ 6. 下列各图形中，不可能是某函数)(x f y =的图象的是（ ）AB C D 7.下列各组中的函数)(x f 与)(x g 相等的是（ ）A x x f =)(，2)()(x x g =B 2)(x x f =，x x g =)(C 11)(2+-=x x x f ，1)(-=x x gD 0)(x x f =，xxx g =)(8.已知)1(,1)1(22++=-x f x x xx f 则的表达式为 （ ）A ．22)1(1)1(+++x x B ．22)1(1)11(xx x-+- C ．(x +1)2+2D ．(x +1)2+19.下列四个函数中,在(0,+∞)上为增函数的是（ ）A.f (x )=3-xB.f (x )=x 2-3x C .f (x )= 11+-x D.f (x )=||x - 10.若函数y=x 2+(2a －1)x+1在区间（－∞，2]上是减函数，则实数a 的取值范围是（ ）A ．[－23，+∞）B ．（－∞，－23] C ．[23，+∞） D ．（－∞，23]11.若函数3()()f x x x R =∈，则()y f x =-在其定义域上是（ ） A ．单调递减的偶函数 B. 单调递减的奇函数 C ．单调递增的偶函数 D. 单调递增的奇函数12.已知二次函数y=2x 2－1在区间[a ,b]上有最小值－1，是下面关系式一定成立的是（ ） A ．a ≤0<b 或a <0≤b B ．a <0<b C ．a <b<0或a <0<b D ．0<a <b 或a <b<0 二、填空题（每小题5分，共计20分）13满足条件{}{}1,21,2,3A =的所有集合A 的个数是 个14 函数y ___________________15.设偶函数f （x ）的定义域为R ，当[0,)x ∈+∞时f （x ）是增函数，则(2),(),(3)f f f π--的大小关系是16 已知y=f(x)是定义在R 上的奇函数，当0x ≥时，()2x -x x f 2=, 则()x f 在0<x 时的解析式是 _______________三.解答题17. （共10分）已知全集I=}32,3,2{2-+a a ，若}2,{b A =，}5{=A C I ，求实数b a ,18.（共12分）已知集合，，，求实数的取值范围19.（12分）已知函数f （x ）=xx 1+.（1）判断()f x 在其定义域上的奇偶性；（5分） （2）判断f （x ）在（0，+∞）上的单调性并加以证明.（7分）20.（共12分）已知二次函数()f x 满足(0)1f =及(1)()2f x f x x +-=，（1）求()f x 的解析式；（6分）（2）求()f x 在区间[]1,1-上的最大值和最小值。

高一数学试卷一、填空（50分）1、设集合A＝{x||x－1|<2}，B＝{y|y＝2x，x∈[0,2]}，则A∩B＝()A．[0,2] B．(1,3)C．[0,3)D．(1,4)2、下列各组函数表示相等函数的是（）A. B.C. D.3、已知，则从B到A的不同映射的有（）A．8个B．9个C．5个D．6个4、函数的定义域为（）A. B. C. D.5、设函数，则（）A. B. C. D.6、已知=，则的表达式是（）A．B．C．D．7、函数是定义在上的奇函数，且它是减函数，若实数，满足，则与的关系是（ ）A. B. C. D. 不确定8、若函数在区间（－∞，2上是减函数，则实数的取值范围是（ ）A ．32-，+∞）B ．（－∞，32-C ．，+∞）D ．（－∞，9、若将二次函数的图像向下、向右各平移2个单位长度得到图像的解析式为y=-x 2,则原二次函数的解析式为（ ）A.y=-(x-2)2+2B.y=-(x+2)2+2C.y=-(x+2)2-2D.y=-(x-2)2-210、（特班）当-1≤x≤1,函数y=2x -2的值域为（ ）A.[32-，0]B.[0，32] C.[-1,0] D.[32-，1] (普班)函数y=(a-2)x 在R 上为增函数，则a 的取值范围是 （ ）A.a>3B.a>0且a≠1C.a<3D.2<a<3二、填空（共20分） 11、若f(x)的的定义域为(－2，2)，则f （2x －3）的定义域是____________.12、(普班)已知函数是定义在上的奇函数，且，若，则_______.（特班）已知函数是定义在上的偶函数，在区间单调递减，则满足的x 取值范围是________ 13、函数=a x-1+3(a>0且a≠1)的图像必过点P,则点P 的坐标为____________.14、比较大小：0.545⎛⎫ ⎪⎝⎭______13910⎛⎫ ⎪⎝⎭三、计算题17 (1)（6分）化简；(2)（6分）解不等式a x＋5<a4x－1(a>0，且a≠1)18、（12分）已知函数是定义在上的奇函数，当时，，（1）求函数的解析式；（2）若不等式，求实数的取值范围f＝f(x)－f(y)，当x＞1时，有19、（12分）函数f(x)的定义域为(0，＋∞)，且对一切x＞0，y＞0都有()x yf(x)＞0.(1)求f(1)的值；(2)判断f(x)的单调性并加以证明；(3)若f(4)＝2，求f(x)在[1,16]上的值域．20、（14分）(特)求二次函数在［0,1］上的最小值g(a)的解析式.（普）已知函数f(x)＝x2＋2ax＋2，x∈[－5,5]．(1)当a＝－1时，求函数f(x)的最大值和最小值；(2)求实数a的取值范围，使y＝f(x)在[－5,5]上是单调函数．数学第二次月考答案一、 选择题CCADA BBBBA二、 填空11、 ⎪⎭⎫ ⎝⎛25,21 12、（普）-1 （特）1233(,)(,)-∞+∞ 13、(1,4) 14、<三、计算17（1）1（2）解 当a >1时，原不等式可变为x ＋5<4x －1.解得x >2；当0<a <1时，原不等式可变为x ＋5>4x －1.解得x <2.故当a >1时，原不等式的解集为(2，＋∞)；当0<a <1时，原不等式的解集为(－∞，2)．18、19、解：(1)∵当x ＞0，y ＞0时，()x y f ＝f (x )－f (y )，∴令x ＝y ＞0，则f (1)＝f (x )－f (x )＝0. (2)设x 1，x 2∈(0，＋∞)，且x 1＜x 2，则f (x 2)－f (x 1)＝21()xx f ， ∵x 2＞x 1＞0，∴21x x ＞1，∴21()x x f ＞0. ∴f (x 2)＞f (x 1)，即f (x )在(0，＋∞)上是增函数．(3)由(2)知f (x )在[1,16]上是增函数．∴f (x )min ＝f (1)＝0，f (x )max ＝f (16)，∵f (4)＝2，由()xf y ＝f (x )－f (y )，知16()4f ＝f (16)－f (4)， ∴f (16)＝2f (4)＝4，∴f (x )在[1,16]上的值域为[0,4]20、（特）解：二次函数其图象开口向上，对称轴为x =2a -1. 若2a -1<0，即a <时，二次函数f (x )在［0,1］上的最小值-4a +2；若0≤2a -1≤1，即≤a ≤1时，二次函数f (x )在［0,1］上的最小值+1；若2a -1>1,即a>1时，二次函数f (x )在［0,1］上的最小值g(a)=f(1)=-8a+5 综上所述，二次函数f (x )在［0,1］上的最小值为g (a )=（普）解：(1)当a ＝－1时，f (x )＝x 2－2x ＋2＝(x －1)2＋1.又x ∈[－5,5]，故当x ＝1时，f (x )的最小值为1.当x ＝－5时，f (x )的最大值为37.(2)函数f (x )＝(x ＋a )2＋2－a 2图象的对称轴为直线x ＝－a .若f (x )在[－5,5]上是单调的，则－a ≤－5或－a ≥5.故a 的取值范围是(－∞，－5]∪[5，＋∞)．。

河溯一中高一年级第二次月考语文试卷一．单项选择（共14小题，每题2分，共28分）1.下列词语中加点的字，读音全对的一项是( )A．委蛇．(yí) 焦灼．(zhuó) 悖．谬(bèi) 矫．揉造作(jiāo)B．木讷．(nè) 证券．(quàn) 龟．裂(jūn) 悄．然无声(qiǎo) C．龋齿(qǔ) 皈．依(ɡuī) 坍．塌(dān) 顺蔓．摸瓜(wàn) D．狙．击(zǔ) 游说．(shuì) 惬．意(qiè) 一暴．十寒(pù)2.下列词语中，错别字最多的一项是( )A.静侯耸入云天直刺九宵扭转乾坤B.酝酿慢慢征途经济实力反复论证C.苛克连名上报借签经验摘星揽月D.配置最高致意预订轨道辉煌时刻3.依次填入下列文段中的虚词，恰当的一组是（）A.于也矣而虽也B.于矣也而然亦C.之矣也则然亦D.之也矣则虽也4.下列句子中，加点词的意义和用法相同的一项是（）C. 吾其．还也5.下列加点的词语意义与现代汉语相同的一项是（）A.吾不能．．早用子，今急而求子，是寡人之过也B.若舍郑以为东道主．．．C.行李之往来，共其乏困．．D.微夫人．．之力不及此6.下列句子中与其他三句句式不相同的一项是（)A.晋侯、秦伯围郑，以其无礼于晋……B.晋军函陵……C.佚之狐言于郑伯曰……D.若亡郑而有益于君……7.对烛之武劝服秦伯退兵，分析正确的一组是（）①晋国贪得无厌，时时图谋扩张领土。

②晋国经常背信弃义，不足信赖，秦不应与之共事。

③晋、楚两国有相互勾结排挤秦国之势。

④秦晋灭郑，有利于晋，不利于秦。

⑤郑国朝秦暮楚必将亡国只能跟随秦国，郑国才有出路。

⑥秦、郑交好，有利于秦不利于晋。

A.①③⑤B.②④⑤C.①②④D.②③⑥8.对下列各句中加点词语的解释，不正确的一项是（）A.持千金之资．币物币：礼品B.厚遗．秦王宠臣中庶子蒙嘉遗：给予、赠送C.荆轲顾笑武阳，前为谢．曰谢：道谢D.图穷．而匕首见穷：穷尽9.下列各句中无通假字的一项是（）A.图穷而匕首见B.群臣惊愕，卒起不意，尽失其度C.往而不反者，竖子也D.乃引其匕首提秦王10.下列各句中加点字的用法与例句中加点字的用法相同的一项是（）例句：函封，燕王拜送于庭A.荆轲自知事不就，倚柱而笑箕．踞以骂B.又前．而为歌曰C.皆白衣冠．．．以送之D.秦武阳色变振恐，群臣怪．之11.对下列加点词语的解释，不正确的一项是（）A.沛公不先破．关中破：攻破B.故．遣将守关者故：所以C.项王使．都尉陈平召沛公使：派遣D.沛公则置．车骑置：放弃、丢下12.下列句子中加点的词语，古今意义相同的一项是（）A.将军战河北，臣战河南．．B.沛公奉卮酒为寿，约为婚姻．．C.备他盗之出入与非常．．也D.从此道至军中，不过．．二十里耳13.下列各句中加点词与“君为我呼入，吾得兄事之”的“兄”用法相同的一项是（）A.素善．留侯张良B.范增数目．项王C.常以身翼．蔽沛公D.籍．吏民，封府库14.对下列加点词的解释，不正确的一项（）A.且贰．于楚也贰：从属二主B.越国以鄙．远鄙：把……当作边邑C.又欲肆．其西封肆：延伸，扩张D.因人之力而敝．之敝：看不起二．文言文阅读（共21分）阅读下列文言文，完成15至18题。

学必求其心得，业必贵于专精高一9月月考物理试题一、选择题：（每空5分，共50分)1．下列关于质点的说法正确的是（）A．质点一定是很小的物体B．质点是实际存在的有质量的点C．质点是研究物体运动的一种理想模型D．质点就是物体的重心2．（多选）从水平匀速飞行的直升机上向外自由释放一个物体，不计空气阻力，在物体下落过程中，下列说法正确的是A．从飞机上看，物体静止B．从飞机上看，物体始终在飞机的正下方C．从地面上看，物体做曲线运动D．从地面上看，物体做直线运动3、下列情况中的速度，属于平均速度的是A百米赛跑的运动员冲过终点线时的速度为9.5m/sB．由于堵车，汽车在通过隧道过程中的速度仅为1.2m/sC．返回地球的太空舱落到太平洋水面时的速度为8m/sD．子弹射到墙上时的速度为800m/s4、关于电磁打点计时器和电火花计时器，下列说法正确的是：A.电磁打点计时器用的是直流电源，而电火花计时器用的是交流电源B.它们每隔0。

02s打一个点C.它们的工作电压均为220V的交流电源D。

使用它们计时时,必须先拉动纸带，再立即接通电源。

5、以下物理量中是矢量的有a。

位移 b.路程c。

瞬时速度d。

平均速度e。

时间f。

速率A. 只有acdB. 只有adf C。

只有afg D。

只有af6、如图是一质点做直线运动的v-t图像,据此图像可以得到的正确结论是A．质点在第1秒末停止运动B．质点在第1秒末改变运动方向C．质点在第2秒内做减速运动D．质点在前2秒内的位移为零7、根据速度定义式v＝错误!，当Δt极短时，错误!就可以表示物体在t 时刻的瞬时速度，该定义应用了下列哪种物理方法（) A．控制变量法B．极限法C．微元法D．假设法8、用同一张底片对着小球运动的路径每隔1s拍一次照,得到的照30片如图所示，则整个过程中小球运动的平均速度大约是( ）A．0.5 m/s B．0。

2 m/sC．0。

17 m/s D．无法确定9、一质点沿直线Ox方向做变速运动,它离开O点的距离随时间变化的关系为x＝5＋2 t3（m），它的速度随时间t变化关系为v＝6t2（m/s)．该质点在t＝0到t＝2 s间的平均速度、t＝2 s到t＝3 s间的平均速度和第2s末瞬时速度大小分别为( ) A．12 m/s, 39 m/s, 12m/sC．12 m/s, 19。

考试时间：120分钟试卷满分：120分第Ⅰ卷（选择题共85分）一．单项选择（每小题1分，满分15分）21. -----Did you enjoy your trip to the town?-----_________. We had driven more than 3 hours before we found the right way.A. AbsolutelyB. Go aheadC. Quite a lotD. Not at all22.There are over 58000 rocky objects in _______space，about 900 of which couldfall down onto ______earth。

A. the；theB.不填；不填C. the；不填D. 不填；the23.The cost of buying a house in Beijing is higher than ______in Luoyang。

A. itB. oneC. thatD. this24.It was the second time we _____ in holding such important parties.A. succeedB. succeededC. had succeededD. have succeeded25. He is the most suitable person _______the task.A. to finishB. finishesC. finishedD. finishing26.Whenever he was asked why he was late for class，he would answer carelessly，______ the same thing.A. sayB. saidC. to sayD. saying27. He had to take the medicine 3 times a day to be _______ the pain in the leg.A.away fromB. free fromC. far fromD. apart from28. According to the weather forecast, it will be _____weather that we had betterstay at home.A. such a badB. such badC. so bad aD. so bad29.. While_________in Britain, he made friends with the natives there.A . he is workingB worked C. he works D working30. We’ll never forget the days ______ we spent in the country.A. whenB. whereC. whatD.不填31. Work hard at your lessons, ______ you’ll fail the exams again.A. andB. butC.besidesD. otherwise32. After he retired, Mr. Green _______painting, but soon lost interest.A. made upB. gave upC.took upD. used up33. My sister will get up early tomorrow morning，because the train to London_________at 6:00 a.m.A. will leaveB. is going to leaveC. is to leaveD. leaves34. Sarah，hurry up! I’m afraid you don’t have time to__________.A. get changeB. get changedC. get to changeD.get changing35. Mr. Smith, _______ of the _____ speech, started to read a novel.A. tiring; boredB. tired; boredC. tired; boringD. tiring; boring二．完形填空（共20小题，每小题1.5分，满分30分）I had a bad habit of skipping to the last pages of a book. I just wanted to see how it ended 36 I was still in the middle of it. This habit 37 first my mom, then my friends, and 38 even my own daughter. Often my 39 wouldn’t be limited just to the books I read but also to what others were 40 as well. Then one day my daughter told me in anger, “Dad, please just read a book one 41 at a time like everyone else!”At times I didn’t 42 this bad habit to just books either. I also tried to skip ahead in my own life and 43 out what to do months and even years from now 44 enjoying each day at present. Although I knew that the 45 of my life wasn’t done yet and that I had manypages 46 to go, I still couldn’t control my burning desire to write the 47 of it half-way through. Time and again, I would 48 jump ahead and try to solve every potential(潜在的) problem before it happened. Life, 49 , doesn’t work like that. It loves to 50 us, and you never know what new problems, changes, or opportunities each new day will 51 .Recently when I found myself living in the 52 again, I felt a voice that gently told me I needed to “live one day at a time.”When I heard those words, I 53 , turned the book of my life back to the 54 page, and thanked God for today.Each of us has to 55 the book of life line by line, moment by moment and trust that our story will be brought to its perfect end.36. A. since B. for C. while D. because37. A. confused B. annoyed C. delighted D. embarrassed38. A. usually B. obviously C. accidentally D. finally39. A. impatience B. misunderstanding C. disappointment D. disagreement40. A. saying B. reading C. doing D. watching41. A. page B. copy C. chapter D. edition42. A. contribute B. devote C. apply D. limit43. A. try B. figure C. let D. turn44. A. on the part of B. other than C. instead of D.on thebasis of45. A. book B. river C. picture D. play46. A. forgotten B. left C. kept D. regretted47. A. feelings B. beginning C. ending D. comments48. A. consciously B. strangely C. foolishly D. critically49. A. otherwise B. moreover C. therefore D. however50. A. surprise B. cheat C. satisfy D. frighten51. A. make B. bring C. take D. award52. A. present B. future C. memory D. dream53. A. cheered B. cried C. lost D. smiled54. A. exciting B. hopeful C. favorite D. right55. A. write B. review C. explain D. translate三．阅读理解（共20小题，每小题2分，满分40分）AIt was a quiet village in which there was a military camp(军营).It was far from the towns and cities and there were some high mountains around. Of course it was a good place for training the new soldiers. But it was difficult for the young men to go outside. Mr White, an officer of forty, was strict with them and he hardly let them leave the camp.Once Mr White was ill in bed. He couldn’t work and a young officer, Mr Hunt began to train the new soldiers instead of him. He knew the young men well and let nine soldiers go to the nearest town to have a holiday. But night fell and none came back to the camp. He was worried about it and stood at the gate. It was five to twelve when MrHunt decided to go to the town and see what was happening to the young men. He started the car quickly and set off. At that moment the nine soldiers came back. It seemed they drank wine. Of course they found the officer was angry.“I’m sorry, sir,”said the first soldier. “I left the town on time. But something was wrong with my bus on my way here. I had to buy a horse and made it run fast. Bad luck! It died and I had to run back.”And the other seven soldiers said they were late for the same reasons. It was the last soldier’s turn. He said, “I’m sorry, sir. I got on a bus on time, but…”Having heard this, the officer became even angrier and stopped him at once. He called out, “If you say something was wrong with your bus, I’ll punish you at once!”“No, no, sir,”said the young man. “My bus was all right, but the horse died!”56. The military camp was built in the village to______ .A. stop the soldiers from going to townsB. stop the soldiers from meeting their friendsC. train the new soldiersD. make the young men live quietly57. Mr Hunt let the nine soldiers have a holiday because _____ .A. he was kind to themB. they felt lonelyC. they had something important to doD. they were the best of all58. The young officer was worried because ________ .A. a traffic accident had happenedB. he was afraid something happened to the nine soldiersC. the nine soldiers would come backD. the nine soldiers drank too much in the town59. The nine soldiers returned to the camp late because ________ .A. something was wrong with their busesB. their horses died on the return wayC. it took them much time to run backD. they all drank much in the townBHarry is eighteen now. He studies in a middle school. His parents like him very much and hope he can become a famous man. So they often tell him to study hard and they do all for him. They call him at six in the morning. After breakfast his father takes him to school in a car and in the afternoon, as soon as the young man comes back, the supper is ready. Of course, he never washes his clothes or goes to buy something in the shops.Once Harry’s father was sent to London on business. He would stay there for half a year. Before leaving, he told his wife to take good care of their son. The woman had to get up earlier and did all that her husband did before. And two months later she was so tired that she was ill in bed. Now the young man got into trouble. He couldn’t do any housework. He had to do as his mother told him. Even he didn’t know where to get on the bus!Yesterday Harry’s mother found his shoes were worn out and told him to buy a new pair in the shop. But he didn’t know how to choose. The woman had a sigh(叹息) and gave him a shoe pattern(鞋样) and told him to buy a pair of shoes himself. It’s Saturday today and Harry doesn’t go to school. With a policeman’s help, he found a shop. The shopkeeper was friendly to him. The man brought a lot of shoes and asked him to choose. When he was trying on a pair, suddenly he remembered something and took them off. The man was surprised and asked, “What’s the matter, young man?”“I’m sorry. I’ve left the shoe pattern at home!”60.Harry’s parents do all instead of him because _______.A. he’s too youngB. he has poor healthC. he’s busy with his studiesD. they hope he spends all time on studies61. _______ always does some housework in the morning.A. Harry’s fatherB. Harry’s motherC. HarryD. Nobody62. When the man was in London, _______.A. Harry had to stay at homeB.Harry fell behind in his classC. Harry couldn’t find the bus stopD. Harry wouldn’t go to school63. We can infer from the passage that _______.A. Harry wanted his mother to buy shoes for himB. Harry didn’t believe himselfC. Harry wouldn’t listen to his motherD. Harry was strong enough to buy shoes for himselfCMarch, April and May are months full of festivals and events all over the world. Here are some wonderful festivals around the world that happen in spring.SongKran--ThailandDates: 13th-15th, AprilIn Thailand, it’s time to celebrate the coming monsoon season, which will bring the rain many people have been looking forward to. They celebrate it with a festivalcalled Songkran，when people head out to the streets with water guns to spray(喷，洒）everyone who walks past. If you walk on the streets where the festival is celebrated, prepare to get soaked!Naghol--VanuatuDates: Every Saturday from April to MayEvery year, villagers come together to celebrate the harvest of yams, an important part in the people’s diet in Vanuatu. The festival is most famous for its “land diving ceremony”. During the ceremony men and boys dive to the ground from high wooden towers with only two thin vines(藤条) attached(附于)to their ankles(脚踝）. The divers’heads have to lightly touch the ground when they jump---something very dangerous if the vines are not measured（测量）properly.Cherry Blossom Viewing ---JapanDates: The cherry blossom season is different from year to year depending on the weather forecast.The cherry blossom season has huge importance to the people of Japan, who celebrate the days when the flowers finally blossom. Only a few days later, the petals(花瓣）fall to the ground, like pink snowflakes. This is one of the most beautiful things to see. In Japan, almost everyone has picnics in the parks to view the flowers.Sinhalese New Year--Sri LankaDates: 13th or 14th, AprilJust like in many other countries in South an South East Asia, this is the time when the Sinhalese celebrate the traditional New Year, an ancient celebration which marks the end of the harvest season and is one of two times of the year when the sun is straight above Sri Lanka. There are a lot of delicious foods during the celebration.64. What does the underlined word “soaked”in Paragraph 2 probably mean?A.tiredB. wetC. crazyD. interested65. The writer thinks that the “land diving ceremony”can be dangerous for the divers because ___________.A. the divers may fall onto the ground if the thin vines breakB.the divers may bump into （撞在…上）the wooden tower on the way downC.the divers’ankles may get injured if the vines are tied too tightlyD.the divers may injure their heads if the vines aren’t measured properly66. We can learn from the passage that__________________.A. the Cherry Blossom Celebration usually lasts a long time in JapanB. the Cherry Blossom Celebration is the most important festival in JapanC. the time for the Cherry Blossom Celebration in Japan can be different yearlyD. people usually stay at home for celebration during the cherry blossom seasonDAl Herpin was 90 years old when the doctors came to his home in New Jersey. They thought for sure that he got some sleep of some kind. So they stayed with him and watched every movement he made. But they were surprised. Though they watched him hour after hour and day after day, they never saw Herpin sleeping. In fact, he did not even own a bed. He never needed one.The only rest that Herpin sometimes got was sitting in a comfortable chair and reading newspapers. The doctors were puzzled by this strange continuous sleeplessness. They asked him many questions, hoping to find an answer. They found only one answer that might explain his condition. Herpin remembered some talk about his mother having been injured several days before he was born. But that was all. Was this the real reason? No one could be sure.Herpin died at the age of 94.67. The doctors came to Herpin’s home in order to ______.A. treat him for his illnessB. find the reason why some old people didn’t need any sleepC. get some proof to show his sleeplessness was not really trueD. help him to have a rest in some day68. After watching him closely, the doctors came to believe that Al Herpin ______.A. needed some kind of sleepB. needed no sleep at allC. was too old to need any sleepD. often slept in a chair69. The word “puzzle”in this passage probably refers to “______”.A. make you think a lot because you do not understand itB. make you worry a lot because you cannot sleep wellC. make you sad because something unusual has happenedD. make you fear because something terrible has happened70. The main idea of this passage is that ______.A. large numbers of people do not need sleepB. everyone needs some sleep to stay aliveC. people can live longer by trying not to sleep at allD. a person was found who actually didn’t need any sleep七选五：根据短文内容，从短文后的七个选项中选出能填入空白处的最佳选项。

2015年10月地理月考试题一、单项选择题：(本部分共35题，每题2分，共70分)。

月球围绕地球运行，地球在距离太阳较近的轨道上运行，这使得地球处于得天独厚的位置。

据此完成1～2题。

1、材料中提到的天体系统包含的级别有 A．一个 B．两个 C．三个 D．四个2、材料中提到的“得天独厚的位置”指A.日地距离适中B.地球自转周期适中C.地球质量体积适中D.大气成分适合读“太阳系的局部示意图”，回答3～4题。

3．图中代表地球的数字是A. ①B. ②C. ③D. ⑤4．地球有生命物质存在，其条件说法正确的是A．月地距离适中，使地球上有适当的温度B．地球的体积和质量适中，有适合生物呼吸的大气C．太阳光热稳定，绝大部分到达了地球D．地球有厚厚的大气层，从而有液态水的存在5. 太阳的大气层由外向里依次是A．光球层、色球层、日冕层 B．日冕层、色球层、光球层C．光球层、日冕层、色球层 D．色球层、日冕层、光球层2014年9月22日至9月28日，国家天文台在日面上观测到10个太阳活动区，发生过4次M级耀斑，其中最大的一次为M5．1级。

据此完成6～7题。

6．下列有关太阳活动的叙述，正确的是A．有规律可循，但尚无法预报B．发生在太阳内部C．以黑子和耀斑为主要标志D．对人类生产、生活影响不大7．这次太阳活动所产生的带电粒子流到达地球后，可能造成的影响有①地球各地出现极光现象②磁针不能正确指示方向③地面无线电短波通讯短暂中断④我国北方出现极昼现象A．①② B．②③C．①④D．③④8．下列现象，可以证明地球自转的是A．日月升落B．极昼极夜 C．极光现象D．四季转换9.下列示意图中正确表示地球自转方向的是10．下图所示，两条河流下游各有一个小岛，最终小岛可能连接的岸堤是A．①③ B．②③ C．①④D．③④11．下列几个地点中，地球自转线速度最大的是A．哈尔滨B．北京C．广州D．上海读右图，回答12题。

12．关于甲乙丙丁四地的叙述，正确的是A.丁的地方时最早B.甲的角速度最大C.乙的线速度大于丙D.甲的昼夜变化幅度最大13．某地的当地时间为正午12点，此时北京时间为12时24分，则该地的经度是Ａ．114°ＥＢ．120°ＥＣ．126°ＥＤ．104°Ｅ14．一般来说，在北京人们8点上班，在乌鲁木齐人们10点上班，这是因为A．北京对工作时间的要求比乌鲁木齐长 B．北京比乌鲁木齐天亮得晚C．北京时间比乌鲁木齐早2个小时 D．北京在乌鲁木齐的西边15．某地水平运动的物体运动方向向左偏，且在一年中有一次太阳直射，该地所处的纬度是A．北纬20度B．南纬20度 C．北纬23度26分 D．南纬23度26分16．地球上有昼夜现象的原因主要是A．地球公转B．地球自转C．地球是个不发光不透明的行星D．地球是个不规则的椭球体2014年9月28日13时13分，我国在酒泉卫星发射中心成功发射实践十一号07星，该星主要用于开展空间科学与技术试验。

河朔一中高一年级10月月考（历史试题）1．通过宗法制的实行，西周形成一个庞大的宗族网。

“大宗能率小宗，小宗能率群弟”，按宗法制的规定，下列在相关范围内不一定能成为大宗的是( )A．周王室—周王正妻所生之子B．周王室—周王嫡长子、嫡长孙C．诸侯国—诸侯国嫡长子、嫡长孙D．卿大夫封地—卿大夫嫡长子、嫡长孙2．下列是《史记》中西周时期重要诸侯国受封情况的记载，其中属于同一类受封对象的是( )①“吴太伯，太伯弟仲雍，皆太王之子，丽王季历之兄也。

”②“于是武王已平商而王天下，封师尚父于齐营丘。

”③“召公爽与周同姓，姓姬氏。

周武王之灭纣，封召公于北燕”④“陈胡公满者，虞帝舜之后也。

……周武王克殷纣，乃复求舜后……封之于陈”A．①②B．②④C．①③D．③④3．在秦朝，采取丞相、御史大夫与诸卿“朝议”的方式讨论国家军政要务，这对于政治决策的重大意义是( )A．集思广益，减少决策失误B．安抚群臣，为君主效力C．展现民主，体现君主关怀D．进行廷辩，显示大臣才能4．《晋书·段灼传》曰：“据上品者非公侯之子孙，则当涂之昆弟(注：当权者的亲属)也。

”这一说法表现的是古代哪一种制度( )A．世卿世禄制B．分封制C．九品中正制D．科举制5．阅读下列根据《中国古代职官》编制的表格，这一表格反映了科举制度( )A.B．扭转了传统等级和门第的观念C．促进部分社会阶层变动D．完全实现了官员选拔的公平、公正6．明朝内阁大学士权力变化表A．内阁的权力变化并不稳定B．内阁权力总体呈上升趋势C．内阁权力总体呈下降趋势D．内阁的权位仰赖皇权支持7．下图文字节选自一则清代档案史料。

其撰拟者应是( )C．军机处D．礼部8．“胡惟庸绝不是朱元璋的真正目标，朱元璋要毁灭的是胡惟庸背后的那个庞然大物。

”“那个庞然大物”是指( )A．内阁制度B．宰相制度C．宦官集团D．胡惟庸集团9．春秋政治家管仲说：“利出于一孔(源于铜钱的小孔，后喻为途径)者，其国无敌；出二孔者，其兵不(半)诎；出三孔者，不可以举兵；出四孔者，其国必亡。

武陟一中上学期复习班第二次月考英语试题第一局部: 单项选择〔共15小题；每一小题1分，总分为15分〕从A、B、C、D四个选项中，选出可以填入空白处的最优选项，并在答题卡上将该项涂黑。

21. —Each of the students, working hard at their lessons,the book.—So have I.A. is readingB. has readC. readingD. reads22. In order to improve my spoken English, I readEnglish.A. everyday; every dayB. every day; everydayC. everyday; everydayD. every day; every day23. It wasback home after the experiment.A. not until midnight did he goB. until midnight that he didn’t goC. until midnight when he didn’t goD. not until midnight that he went24. —To tell you the truth, I wouldn’t be happy living in such a small room.—.I do prefer a small room.A. I agree with you.B. It’s OK with me.C. It just dependsD. I’d rather not.25. Whatpleasant surprise! I’ll t ell Richard about itminute he comes home.A. a, theB. a, aC. a, /D. /, the26. They were completelyby the story he.A. taken up, madeB. taken off, made notesC. taken in, made upD. taken out, made use of27. —Mr. Lee never said that he hated school when he was a child,?—But he actually missed school.A. did he, now and thenB. didn’t he, in timeC. was he, for onceD. wasn’t he, at times28. —It’s cloudy outside. Please take an umbrella.—.A. Yes, take it easyB. OK, just in caseC. Well, it just dependsD. All right. You’re welcome29. All he was thinking about washe would do with the big sum of money hisfather gave him.A. howB. whatC. thatD. whether30. Though he wasout of breath when he got there, he thought it wasworth theeffort.A. quite; wellB. well; quiteC. quite; quiteD. well; well31. Allan’s new MP4 is only about 10cm8cm125grams.A. with; weightsB. by; weighingC. of; weightsD. between; weighing32. All the thingsmust be done well.A. worth to doB. worthy of being doneC. worthy doingD. worth of doing.33. We had the picture takenstood a leaning tower.A. in the placeB. in whichC. whichD. where34. They suggested that the professorjust nowchairman of the meeting.A. refer to, was madeB. referring to, be madeC. referred to, be madeD. referred to, was made35. In no countryBritain, as has been mentioned,experience the drastic changes oftemperature.A. other than, one canB. apart from, one canC. rather than, can oneD. other than, can one第二局部: 完型填空〔共20小题；每一小题1.5分，总分为30分〕阅读下面短文，掌握其大意，然后从各题所给的四个选项〔A、B、C和D〕中，选出最优选项，并在答题卡上将该项涂黑Once upon a time, a well-known painter was finishing his painting while standing on the roof of a tall building. It was an incredibly〔难以置信的〕36painting to be shown during Princess Diana’s wedding.The painter was consumed〔吸引住了〕by, and37with his own painting that he unconsciously took a few steps backward while38it. He didn’t39and kept on stepping until he was a step away from the40of the tall building. Just one more step41and he would have fallen to his death.42, a man who was standing nearby saw what the painter was doing and was about to43him to warn him but he44that his shout might surprise the painter and thus45him to accidentally take one step backward and fall down. The man tooka46and began to paint on the beautiful painting47it was completely damaged.48realizing what was happening to his painting, the painter got very49and moved forward to50the man.51,some other people who were also present52him and showed him that he was about to fall over the edge of the building.53, we have painted our54with such beauty and become too engrossed〔全神贯注的〕in our own fantasies, but then something seems to destroy our beautiful image. This often happens to55us from unseen dangers that lie ahead of us.36. A. lovely B. beautiful C. small D. great37. A. excited B. surprised C. crazy D. pleased38. A. looking at B. enjoying C. admiring D. watching39. A. look down B. look around C. look up D. look back40. A. edge B. line C. side D. end41. A. backward B. forward C. upward D. downward42. A. Surprisingly B. Suddenly C. Quickly D. Hopefully43. A. shout at B. point at C. shoot at D. laugh at44. A. recognized B. understood C. knew D. realized45. A. let B. have C. make D. cause46. A. paper B. brush C. knife D. stick47. A. when B. before C. until D. as48. A. Upon B. In C. To D. With49. A. surprised B. mad C. angry D. disappointed50. A. cheer B. please C. greet D. stop51. A. So B. Therefore C. Thus D. However52. A. fetched B. held C. told D. saved53. A. Always B. Sometimes C. Usually D. Often54. A. future B. past C. today D. yesterday55. A. make B. keep C. prevent D. save第三局部：阅读理解〔共20小题，每一小题2分, 总分为40分〕阅读如下短文，从每题所给的四个选项〔A、B、C、D〕中，选出最优选项，并在答题卡上将该项涂黑。

一、单项选择题（每小题2分，共50分）1.2012年云南省昭通市彝良县、贵州省毕节市威宁县交界连发两次5级以上地震，彝良县城震感强烈，部分房屋出现倒塌。

社会各界援助了大量的救灾物资。

这些救灾物资（）A．不是商品，因为它们不是劳动产品B．是商品，因为它们具有使用价值C．不是商品，因为它们没有用于交换D．是商品，因为它们满足了灾民的需要2.在某地粮油批发市场，2009年4月份的色拉油价格为6．95元/500克。

这里货币执行的职能与下列选项中货币执行的职能一致的是（）A．李某缴纳税款400元B．小楼用68元买了一件衬衣C．某企业付给小张2000元薪金D．某款手机的价格是1880元3.商品的价值量是指商品价值的大小，它是由( )决定的A．劳动时间 B．个别劳动时间C．产品质量 D．社会必要劳动时间4.海南的荔枝比主产区广东的荔枝提早15～20天成熟，但在价格上早熟品种的荔枝比迟熟品种的荔枝要高出5～6倍，导致这种价位差的主要原因是( )A．商品的价格主要是受供求关系的影响 B．商品价格由其价值决定C．海南的荔枝要比广东的荔枝消耗更多的劳动投入 D．海南的荔枝比广东的荔枝营养价值更高厦高铁2011年底通车，从龙岩至厦门仅需1小时，票价约为60元。

在这种情况下，原本打算坐大巴的人改乘动车。

面对这种新选择，有乘客表示“应该会坐动车，便宜还省时间，主要是性价比吧”回答第5题:5.有人选择坐动车而不选择坐大巴，“性价比”会影响乘客的选择，分别说明（）A．在相互替代的两种商品中，一种商品价格下降导致对另一种商品的需求量增加从众心理引发的消费B．在相互替代的两种商品中，一种商品价格下降导致对另一种商品的需求量减少求实心理引发的消费C．在互补关系的两种商品中，一种商品价格下降引起对另一种商品的需求量减少求异心理引发的消费D．在互补关系的两种商品中，一种商品价格下降引起对另一种商品的需求量增加攀比心理引发的消费6．美国居民过感恩节时有食用完整火鸡的习惯。

武陟一中2015—2016学年高一上学期物理试卷考前寄语：亲爱的同学们，这是你进入高中的第二次物理考试，题目不难，不要怕！考试时注意：姓名班级考号填好，交卷时只交答题卷，卷面整洁字迹清晰，细心审题规范解答。

只要你用心去做，一定能发挥最佳水平，老师们相信你！一、选择题(本题共22小题，每小题3分，共66分．每小题至少有一个选项正确，全选对得3分，选不全得2分，错选不得分)1．一个做初速度为零的匀加速直线运动的物体，它在第1 s末，第2 s末，第3 s末的瞬时速度之比是()A．1∶1∶1B．1∶3∶5C．12∶22∶32D．1∶2∶32．a、b两个物体从同一地点同时出发，沿同一方向做匀变速直线运动．若两物体初速度不同而加速度相同，则在运动过程中()A．a、b的速度之差与时间成正比B．a、b的速度之差保持不变C．a、b的速度之和与时间成正比D．a、b的速度之差与时间的平方成正比3．甲、乙两个物体沿同一直线向同一方向运动时，取物体的初速度方向为正方向，甲的加速度恒为2 m/s2，乙的加速度恒为－3 m/s2，则下列说法正确的是() A．两物体都做匀加速直线运动，乙的速度变化快B．甲做匀加速直线运动，它的速度变化慢C．乙做匀减速直线运动，它的速度变化率大D．甲的加速度比乙的加速度小4．一辆车由静止开始做匀变速直线运动，在第8 s末开始刹车，经4 s停下来，汽车刹车过程也在做匀变速运动，那么前后两段加速度的大小之比是()A．1∶4 B．2∶1C．1∶2 D．4∶15.我国在西昌卫星发射中心用“长征三号丙”运载火箭，将第三颗北斗导航卫星送入预定轨道，这标志着北斗卫星导航系统工程建设又迈出了重要一步，卫星组网正按计划稳步推进．如图所示，发射过程中某段时间内火箭速度的变化规律为v＝(2t＋4) m/s，由此可知这段时间内()A．火箭的初速度为4 m/sB．火箭的加速度为2 m/s2C．在3 s末，火箭的瞬时速度为12 m/sD．火箭做匀减速直线运动6．一物体做匀变速直线运动，当t＝0时，物体的速度大小为12 m/s，方向向东；当t ＝2 s时，物体的速度大小为8 m/s，方向仍向东．当t为多少时，物体的速度大小变为2 m/s？()A．3 s B．5 sC．7 s D．9 s7．物体做匀加速直线运动，已知第1 s末的速度是6 m/s，第2 s末的速度是8 m/s，则下列结论正确的是()A．物体零时刻的速度是3 m/sB．物体的加速度是2 m/s2C．任何1 s内的速度变化都是2 m/sD．第1 s内的平均速度是6 m/s8.一物体做直线运动，其加速度随时间变化的a－t图象如图所示．下列v－t图象中，可能正确描述此物体运动的是()9．列车出站时能在150 s 内匀加速到180 km/h ，然后正常行驶．某次因意外列车以加速时的加速度大小将车速减至108 km/h.以初速度方向为正方向，则下列说法不正确的是( )A ．列车加速时的加速度大小为13m/s 2B ．列车减速时，若运用v ＝v 0＋at 计算瞬时速度，其中a ＝－13m/s 2C ．若用x －t 图象描述列车的运动，减速时的图线在时间轴t 轴的下方D ．列车由静止加速，1 min 内速度可达20 m/s10.甲、乙两辆汽车在平直公路上的同一地点，同时出发，分别向相反方向做如图所示的运动，则下列关于汽车运动的描述正确的是( )A ．前80 s ，乙车平均速度是甲车平均速度的4倍B ．70 s 末，甲、乙两车的加速度大小相等、方向相同C ．60 s 末，两车相距最远D ．80 s 末，两车相距最远11．对于一个做单向匀减速运动的物体，在其静止前，下列说法正确的是( )A．速度越来越小，位移越来越大B．速度越来越小，位移也越来越小C．加速度越来越小，位移越来越大D．加速度越来越小，位移也越来越小12．某质点做直线运动的速度v和时间t的关系如图，那么该质点在3 s内通过的位移是()A．0.5 m B．3 mC．1 m D．4.5 m13．某质点的位移随时间变化规律的关系是x＝4t＋2t2，x与t的单位分别为m和s，则质点的初速度与加速度分别为()A．4 m/s与2 m/s2B．4 m/s与4 m/s2C．0与4 m/s2D．4 m/s与014．物体做匀变速直线运动，初速度为v0＝2 m/s，加速度a＝－2 m/s2，则经过2 s后，物体的速度和位移为()A．－2 m/s,1 m B．－2 m/s,0 mC．2 m/s,0 m D．2 m/s，－1 m15.龟兔赛跑的故事流传至今，按照龟兔赛跑的故事情节，兔子和乌龟的x-t图象如图所示，下列关于兔子和乌龟运动的说法正确的是()A．乌龟一直做匀加速运动，兔子先加速后匀速再加速B．兔子和乌龟是从同一地点出发的C．骄傲的兔子在T4时刻发现落后奋力追赶，但由于跑得比乌龟慢，还是让乌龟先到达预定位置x3D．在T2～T4，兔子比乌龟运动得快16．右图是某质点运动的x－t图象，对应的v－t图象应是()17．以20 m/s速度行驶的汽车，制动后以5 m/s2的加速度做匀减速运动，则汽车在制动后的5 s内的位移是()A．45 m B．37.5 mC．40 m D．50 m18．右图均能正确反映物体在直线上的运动，则在t＝2 s内物体位移最大的是()19．汽车以20 m/s的速度做匀速直线运动，刹车后的加速度大小为5 m/s2，那么开始刹车后2 s内与开始刹车后6 s内汽车通过的位移之比为()A．1∶1 B．1∶3C．4∶3 D．3∶420．如图所示是物体做直线运动的v-t图象，由图象可得到的正确结论是()A．t＝1 s时物体的加速度大小为1.0 m/s2B．t＝5 s时物体的加速度大小为0.75 m/s2C．第3 s内物体的位移为3 mD．物体在加速过程的位移比减速过程的位移小21．质点做直线运动的v－t图象如图所示，规定向右为正方向，则该质点在前8 s内平均速度的大小和方向分别为()A．0.25 m/s向左B．0.25 m/s向右C．1 m/s向右D．1 m/s向左22.右图为一质点运动的位移随时间变化的图象，图象是一条抛物线，方程为x＝－5t2＋40t.下列说法错误的是()A．质点做匀减速直线运动，最大位移是80 mB．质点的初速度是20 m/sC．质点的加速度大小是5 m/s2D．t＝4 s时，质点的速度为零二、实验题23．(4分)在练习使用打点计时器的实验中，记录的纸带如图所示，图中前几个点模糊，从A点开始每5个点取1个计数点，则小车通过D点时速度是________m/s，小车运动的加速度是________m/s2.(打点计时器的电源频率是50 Hz)二、计算题(本题共2小题，共30分)24．（15分）质点从静止开始做匀加速直线运动，经4 s后速度达到20 m/s，然后匀速运动了10 s，接着经4 s匀减速运动后静止．求：(1)质点在加速运动阶段的加速度为多大？(2)质点在16 s末的速度为多大？25．（15分）一个质点从静止开始做匀加速直线运动，已知它在第4 s内的位移是14 m，求：(1)质点运动的加速度；(2)它前进72 m所用的时间．物理参考答案1．解析： 由v ＝at 得v 1∶v 2∶v 3＝at 1∶at 2∶at 3＝1∶2∶3，故选D 正确．2．解析： v a －v b ＝v a 0＋at －(v b 0＋at )＝v a 0－v b 0，可见(v a －v b )为一定值，选项B 正确． 3．解析： 当a 的方向与v 0方向相同时，物体一定做加速直线运动．若a 一定，则为匀加速直线运动；当a 的方向与v 0的方向相反时，物体一定做减速直线运动．若a 一定，则为匀减速直线运动．4．解析： 设前后两段的加速度分别为a 1、a 2，开始刹车时汽车速度为v ，则a 1＝vt 1，a 2＝vt 2，所以a 1∶a 2＝t 2∶t 1＝1∶2.5.解析： 在这段时间内，由速度的表达式可知，火箭的速度均匀增大，故火箭做匀加速直线运动，选项D 错误；由匀变速直线运动的速度公式v ＝v 0＋at 知，在这段时间内火箭的初速度v 0＝4 m/s ，加速度a ＝2 m/s 2，选项A 、B 正确；将时间t ＝3 s 代入得v 3＝10 m/s ，选项C 错误．6．答案： BC7．解析： 由题意知t 1＝1 s 时，v 1＝6 m/s ；t 2＝2 s 时，v 2＝8 m/s.由v 2＝v 1＋a (t 2－t 1)知，物体的加速度a ＝8－62－1 m/s 2＝2 m/s 2.因为物体做匀加速运动，所以任何1 s 内速度的变化量都为Δv ＝a Δt ＝2×1 m/s ＝2 m/s.故B 、C 正确．由v 1＝v 0＋at 得，零时刻的速度v 0＝v 1－at ＝6 m/s －2×1 m/s ＝4 m/s ，故A 不正确．第1 s 内的平均速度大于4 m/s ，小于6 m/s ，故D 不正确．8.解析： 解答本题的突破口是T ～2T 时间内的加速度跟0～T2时间内的加速度大小相等，方向相反，从而排除选项A 、B 、C ，本题选D.9．解析： 列车的加速度大小a ＝Δv Δt ＝50150 m/s 2＝13 m/s 2，减速时，加速度方向与速度方向相反，a ′＝－13 m/s 2，故A 、B 两项都正确．列车减速时，v －t 图象中图线依然在时间轴t 轴的上方，C 项错．由v ＝at 可得v ＝13×60 m/s ＝20 m/s ，D 项对．10.解析： 前80 s 内，乙车的位移大小是甲车位移大小的2倍，故乙车平均速度是甲车平均速度的2倍，A 项错；由图象知，70 s 末甲、乙两车的加速度大小相等、方向相反，B 项错；80 s 末两车相距最远，C 项错、D 项正确．11．解析： 物体朝一个方向运动，故x 不断增大，只有B 对． 12．解析： 图线与坐标轴围成图形的“面积”，即为位移大小．13．解析： 匀变速直线运动的位移与时间关系式为x ＝v 0t ＋12at 2，对比x ＝4t ＋2t 2，得出v 0＝4 m/s ，a ＝4 m/s 2，B 正确．14．解析： 用v ＝v 0＋at ，x ＝v 0t ＋12at 2求解，注意矢量的方向．15.解析： 乌龟一直做匀速运动，兔子先是没动，T 1时刻开始匀速前，T 2到T 4时间内又停止，T 4后又开始前进，A 错；兔子和乌龟都是从原点出发，B 对；兔子虽在T 4时刻发现落后奋力追赶，跑得比乌龟快，但由于时间太晚，还是让乌龟先到达预定位置x 3，C 错；在T 2～T 4，兔子停止不动，乌龟一直前进，D 错．16． 解析：17． 解析： 汽车运动时间t ＝v a ＝4 s ＜5 s ，则x ＝12at 2＝12×5×42 m ＝40 m ，故C 对．18． 解析： 根据x -t 图象的物理意义可以判断选项A 在t ＝2 s 内物体的位移是0，根据v －t 图象与时间轴所围图形的面积在数值上等于物体的位移可以判断，选项C 、D 在t ＝2 s 内物体的位移是0，而B 选项在t ＝2 s 内物体的位移大于0，所以t ＝2 s 内物体位移最大的是B 选项．19．解析： 汽车从刹车到静止用时t 刹＝v 0a ＝205 s ＝4 s ，故刹车后2 s 和6 s 内汽车的位移分别为x 1＝x 0t －12at 2＝⎝⎛⎭⎫20×2－12×5×22 m ＝30 m ，x 2＝v 0t 刹－12at 2刹＝⎝⎛⎭⎫20×4－12×5×42m ＝40 m ，x 1∶x 2＝3∶4，D 选项正确．20．解析： 由图象可知0～2 s 时间内物体做匀加速直线运动，其加速度大小等于图线斜率大小即a ＝ΔvΔt ＝1.5 m/s 2，A 错误；3～7 s 时间内物体做匀减速直线运动．其加速度大小为a ＝ΔvΔt ＝0.75 m/s 2，B 正确；图线与t 轴围成的面积等于物体所发生的位移，故第3 s内的位移x ＝3.0×1 m ＝3.0 m ，C 正确；加速过程的位移x ＝12×2×3.0 m ＝3.0 m ，减速过程的位移x ＝12×4×3.0 m ＝6.0 m ，故D 正确．21．解析： 由v －t 图象知前8 s 内位移为Δx ＝x 1＋x 2＝12×3×2 m －12×(8－3)×2 m ＝－2m 负号表示位移方向与正方向相反，即水平向左．由平均速度公式得v ＝Δx Δt ＝－2 m8 s＝－0.25 m/s 负号表示平均速度方向与正方向相反，即水平向左．故答案为A.22.解析： 由x ＝－5t 2＋40t 变形得x ＝40t ＋12×(－10)t 2，故v 0＝40 m/s ，a ＝－10 m/s 2，质点做匀减速直线运动，由数学知识知，当t 0＝4 s 时，位移最大为x 0＝80 m ，A 正确，B 、C 错误．t ＝4 s 时，v ＝40 m/s －10 m/s 2×4 s ＝0，D 正确．答案： AD23.解析： 由题意知相邻两计数点的时间间隔T ＝0.1 s v D ＝CE2T＝－－22×0.1m/s≈1.44 m/s同理v B ＝AC2T ≈1.03 m/s由a ＝Δv Δt得a ＝v D －v B2T＝2.05 m/s 2答案： 1.44 2.0524．解析： (1)设加速阶段的加速度为a 1，则v 1＝a 1t 1 a 1＝v 1t 1＝204m/s 2＝5 m/s 2(2)设减速运动阶段的加速度为a 2，由于v 2＝v 1＋a 2t 2，v 2＝0，v 1＝20 m/s ，得a 2＝v 2－v 1t 2＝0－204m/s 2＝－5 m/s 2当t ＝16 s 时，质点已减速运动了t 3＝2 s ，此时质点的速度 v 3＝v 1＋a 2t 3＝20 m/s －5×2 m/s ＝10 m/s. 25．解析： (1)由位移公式x ＝12at 2得质点在4 s 内的位移x 4＝12at 24①质点在3 s 内的位移x 3＝12at 23②质点在第4 s 内的位移x ＝x 4－x 3③解①②③式得a ＝2x t 24－t 23＝2×1442－32 m/s 2＝4 m/s 2(2)由x ′＝12at ′2得t ＝2x ′a＝2×724s ＝6 s。

11月30号一、单项选择题（本题共30小题，每小题2分，共60分）1．2013年正值太阳活动高峰期，下列叙述中正确的是①太阳黑子和耀斑都产生在太阳色球层上②前一次太阳活动的极大年到再次活动极大年的平均周期约为11年③太阳活动发出的高能带电离子在世界各地产生极光现象④太阳日冕层的高温使高能带电粒子向外高速运动，形成了“太阳风”A．①②B．②④ C．①④D．②③2．下列关于太阳辐射的说法正确的是A．促进地球上水、大气运动、生物活动和变化的主要动力B．是产生“磁暴”现象的原动力C．纬度越高，到达大气上界的太阳辐射量越多D．是地球上具有生命物质的唯一条件3．下列四图中（空白部分表示白昼，斜线部分表示黑夜，小圆表示极圈），太阳直射点纬度位置大致相同的是4.地球自转产生的地理意义有：A.昼夜长短的变化B.正午太阳高度的变化C.太阳直射点的南北移动D.地球上不同经度的地方，地方时不同。

5.某地水平运动物体向左偏，且一年中只有一次太阳直射，该地位于（）A.北回归线上B.北极圈上C.南回归线上D.南极圈上6.下图中，虚线箭头表示水平运动物体的原始运动方向，实线箭头表示受地转偏向力影响后实际的运动方向，图中所示四种情况，正确的是A．①② B．②③C．③④D．①④7.若黄赤交角从23026/变为300时，则地表各温度带面积：A.温带缩小，寒带、热带面积扩大。

B.温带增大，寒带、热带面积缩小。

C.温带缩小，寒带、热带面积缩小。

D.温带、热带面积增大，寒带面积缩小。

8.下列节日中，北半球白昼最长的是（）A.建军节B.春节C.教师节D.国庆节读近地面气压带、风带示意图，回答9～10题。

9．图中气压带代表( )。

A．赤道低气压带B．副极地低气压带C．极地高气压带D．副热带高气压带10．下列四种局部环流形式示意图，不正确的是( )。

读甲、乙两地等压面分布示意图，回答11～12题。

11．关于甲、乙、①、②四地气压值的关系正确的是( )。

2015-2016学年河南省焦作市武陟一中高三（上）第一次月考数学试卷（文科）一、选择题（本大题共12小题，每小题5分，共60分．在每小题给出的四个选项中，只有一个选项是符合题目要求的）1．若U={1，2，3，4，5，6}，M={1，2，4}，N={2，3，6}，则∁U（M∪N）=（）A．{1，2，3} B．{5} C．{1，3，4} D．{2}2．已知t∈R，i为虚数单位，复数z1=3+4i，z2=t+i，且z1•z2是实数，则t等于（）A．B．C．﹣D．﹣3．已知a∈R，则“a2＜a”是“a＜1”的（）A．充分而不必要条件 B．必要而不充分条件C．充要条件 D．既不充分也不必要条件4．执行如图所示的程序框图，如果输入a=2，b=2，那么输出的a值为（）A．4 B．16 C．256 D．655365．如图，在△ABC中，AB=BC=4，∠ABC=30°，AD是边BC上的高，则•的值等于（）A．0 B．4 C．8 D．﹣46．若lg2，lg（2x﹣1），lg（2x+3）成等差数列，则x的值等于（）A．1 B．0或32 C．32 D．log257．点A，B，C，D在同一个球面上，AB=BC=，AC=2，若球的表面积为，则四面体ABCD体积最大值为（）A．B．C．D．28．已知函数f（x）=x2+cosx，f′（x）是函数f（x）的导函数，则f′（x）的图象大致是（）A．B．C．D．9．已知定义域为R的奇函数y=f（x）的导函数为y=f′（x），当x≠0时，f′（x）+＞0，若a=f（），b=﹣2f（﹣2），c=（ln）f（ln），则a，b，c的大小关系正确的是（）A．a＜b＜c B．b＜c＜a C．a＜c＜b D．c＜a＜b10．已知F1，F2分别是双曲线﹣=1（a＞b＞0）的两个焦点，A和B是以O（O为坐标原点）为圆心，|OF1|为半径的圆与该双曲线左支的两个交点，且△F2AB是等边三角形，则双曲线的离心率为（）A．B．C．D．+111．若函数f（x）=sin（3x+φ），满足f（a+x）=f（a﹣x），则的值为（）A．B．±1 C．0 D．12．已知f（x）、g（x）都是定义在R上的函数，g（x）≠0，f′（x）g（x）＜f（x）g′（x），f（x）=a x g（x），，在有穷数列（n=1，2，…，10）中，任意取前k项相加，则前k项和大于的概率是（）A．B．C．D．二、填空题（本大题共4小题，每小题5分，共20分）13．对大于1的自然数m的三次幂可用奇数进行以下方式的“分裂”：23，33，43，…仿此，若m3的“分裂”数中有一个是73，则m的值为．14．设α为锐角，若cos（α+）=，则sin（α﹣）=．15．设x，y满足约束条件，则x2+y2的最大值为．16．已知偶函数f（x）满足f（x+1）=﹣，且当x∈[﹣1，0]时，f（x）=x2，若在区间[﹣1，3]内，函数g（x）=f（x）﹣log a（x+2）有4个零点，则实数a的取值范围是．三、解答题（本大题共5小题，每题12分，共60分）17．已知函数f（x）=2sinxcosx﹣2cos2x+1．（I）求函数f（x）的最小正周期；（Ⅱ）将函数f（x）的图象向左平移个单位，得到函数g（x）的图象．在△ABC中，角A，B，C的对边分别为a，b，c，若g（）=1，a=2，b+c=4，求△ABC的面积．18．如图，已知四边形ABCD是正方形，PD⊥平面ABCD，CD=PD=2EA，PD∥EA，F，G，H分别为PB，BE，PC的中点．（I）求证：GH∥平面PDAE；（II）求证：平面FGH⊥平面PCD．19．某校学习小组开展“学生数学成绩与化学成绩的关系”的课题研究，对该校高二年级800名学生上学期期数学和化学成绩，按优秀和不优秀分类得结果：数学和化学都优秀的有60人，数学成绩优秀但化学不优秀的有140人，化学成绩优秀但数学不优秀的有100人．（Ⅰ）补充完整表格并判断能否在犯错概率不超过0.001前提下认为该校学生的数学成绩与化学成绩有关系？数学优秀数学不优秀总计化学优秀化学不优秀总计（Ⅱ）现有4名成员甲、乙、丙、丁随机分成两组，每组2人，一组负责收集成绩，另一组负责数据处理．求学生甲分到负责收集成绩组，学生乙分到负责数据处理组的概率．p（K2＞k0）0.010 0.005 0.001k0 6.635 7.879 10.828附：K2=．20．已知椭圆+=1（a＞b＞0）的离心率e=，直线y=x+1经过椭圆C的左焦点．（I）求椭圆C的方程；（Ⅱ）若过点M（2，0）的直线与椭圆C交于A，B两点，设P为椭圆上一点，且满足+=t（其中O为坐标原点），求实数t的取值范围．21．已知函数f（x）=e x+3x2﹣ax．（1）若f（x）在x=0处取得极值，求曲线y=f（x）在点（1，f（1））处的切线方程；（2）若关于x的不等式f（x）≥+ax+1在x≥时恒成立，试求实数a的取值范围．四.选做题，选择22、23、24中一题写在答题卡上．22．如图，圆O的直径AB=d，P是AB延长线上一点，BP=a，割线PCD交圆O于点C、D，过点P作AP的垂线，交直线AC于点E，交直线AD于点F．（Ⅰ）求证：∠PEC=∠PDF；（Ⅱ）求PE•PF的值．23．选修4﹣4：坐标系与参数方程已知在直角坐标系xOy中，圆锥曲线C的参数方程为（θ为参数），直线l经过定点P（2，3），倾斜角为．（1）写出直线l的参数方程和圆的标准方程；（2）设直线l与圆相交于A，B两点，求|PA|•|PB|的值．24．选修4﹣5：不等式选讲设f（x）=|x+1|+|x﹣3|．（1）解不等式f（x）≤3x+4；（2）若不等式f（x）≥m的解集为R，求实数m的取值范围．2015-2016学年河南省焦作市武陟一中高三（上）第一次月考数学试卷（文科）参考答案与试题解析一、选择题（本大题共12小题，每小题5分，共60分．在每小题给出的四个选项中，只有一个选项是符合题目要求的）1．若U={1，2，3，4，5，6}，M={1，2，4}，N={2，3，6}，则∁U（M∪N）=（）A．{1，2，3} B．{5} C．{1，3，4} D．{2}【考点】并集及其运算．【专题】计算题．【分析】由M与N求出两集合的并集，根据全集U求出并集的补集即可．【解答】解：∵M={1，2，4}，N={2，3，6}，∴M∪N={1，2，3，4，6}，∵U={1，2，3，4，5，6}，∴∁U（M∪N）={5}．故选B【点评】此题考查了并集及其运算，熟练掌握并集的定义是解本题的关键．2．已知t∈R，i为虚数单位，复数z1=3+4i，z2=t+i，且z1•z2是实数，则t等于（）A．B．C．﹣D．﹣【考点】复数代数形式的混合运算．【专题】数系的扩充和复数．【分析】直接利用复数的乘法运算法则，复数是实数，虚部为0求解即可．【解答】解：t∈R，i为虚数单位，复数z1=3+4i，z2=t+i，且z1•z2是实数，可得（3+4i）（t+i）=3t﹣4+（4t+3）i，4t+3=0则t=．故选：D．【点评】本题考查复数的基本知识，复数的概念的应用，考查计算能力．3．已知a∈R，则“a2＜a”是“a＜1”的（）A．充分而不必要条件 B．必要而不充分条件C．充要条件 D．既不充分也不必要条件【考点】必要条件、充分条件与充要条件的判断．【专题】简易逻辑．【分析】根据充分条件和必要条件的定义结合不等式的性质，进行判断即可．【解答】解：由a2＜a得0＜a＜1，则“a2＜a”是“a＜1”的充分不必要条件，故选：A【点评】本题主要考查充分条件和必要条件的判断，根据不等式的性质是解决本题的关键．4．执行如图所示的程序框图，如果输入a=2，b=2，那么输出的a值为（）A．4 B．16 C．256 D．65536【考点】程序框图．【专题】算法和程序框图．【分析】执行程序框图，写出每次循环得到的a的值，当a=256时，满足条件log3a＞4，输出a的值为256．【解答】解：执行程序框图，有a=2，b=2不满足条件log3a＞4，有a=4；不满足条件log3a＞4，有a=16不满足条件log3a＞4，有a=256此时，满足条件log3a＞4，输出a的值为256．故选：C．【点评】本题主要考察了程序框图和算法，属于基本知识的考查．5．如图，在△ABC中，AB=BC=4，∠ABC=30°，AD是边BC上的高，则•的值等于（）A．0 B．4 C．8 D．﹣4【考点】平面向量数量积的运算．【专题】数形结合．【分析】通过解直角三角形求出边AD，利用向量的运算法则、向量垂直的充要条件、向量的数量积公式求出．【解答】解：因为AB=BC=4，∠ABC=30°，AD是边BC上的高，所以AD=4sin30°=2．所以•=•（+）=•+•==2×4×=4，故选B【点评】本题考查向量的运算法则、向量垂直的充要条件、向量的数量积公式．6．若lg2，lg（2x﹣1），lg（2x+3）成等差数列，则x的值等于（）A．1 B．0或32 C．32 D．log25【考点】等差数列的性质．【专题】计算题．【分析】根据题意，可得lg2+lg（2x+3）=2lg（2x﹣1），由对数的运算性质可得lg[2•（2x+3）]=lg（2x﹣1）2，解可得2x的值，由指数的运算性质可得答案．【解答】解：若lg2，lg（2x﹣1），lg（2x+3）成等差数列，则lg2+lg（2x+3）=2lg（2x﹣1），由对数的运算性质可得lg[2•（2x+3）]=lg（2x﹣1）2，解得2x=5或2x=﹣1（不符合指数函数的性质，舍去）则x=log25故选D．【点评】本题考查指数、对数的运算性质以及等差数列的性质，解题时注意结合指数函数的性质，否则容易产生增根．7．点A，B，C，D在同一个球面上，AB=BC=，AC=2，若球的表面积为，则四面体ABCD体积最大值为（）A．B．C．D．2【考点】球的体积和表面积．【专题】球．【分析】根据几何体的特征，判定外接球的球心，求出球的半径，即可求出球的表面积．【解答】解：根据题意知，△ABC是一个直角三角形，其面积为1．其所在球的小圆的圆心在斜边AC的中点上，设小圆的圆心为Q，球的表面积为，球的半径为r，，r=，四面体ABCD的体积的最大值，底面积S△ABC不变，高最大时体积最大，就是D到底面ABC距离最大值时，h=r+=2．四面体ABCD体积的最大值为×S△ABC×h==，故选：C．【点评】本题考查的知识点是球内接多面体，球的表面积，其中分析出何时四面体ABCD的体积的最大值，是解答的关键．8．已知函数f（x）=x2+cosx，f′（x）是函数f（x）的导函数，则f′（x）的图象大致是（）A．B．C．D．【考点】函数的图象．【专题】函数的性质及应用．【分析】由于f （x ）=x+cosx ，得f ′（x ）=x ﹣sinx ，由奇函数的定义得函数f ′（x ）为奇函数，其图象关于原点对称，排除BD ，取x=代入f ′（）=﹣sin=﹣1＜0，排除C ，只有A 适合．【解答】解：由于f （x ）=x+cosx ，∴f ′（x ）=x ﹣sinx ，∴f ′（﹣x ）=﹣f ′（x ），故f ′（x ）为奇函数，其图象关于原点对称，排除BD ，又当x=时，f ′（）=﹣sin=﹣1＜0，排除C ，只有A 适合，故选：A ．【点评】本题考查函数的图象，考查同学们对函数基础知识的把握程度以及数形结合的思维能力，同时考查导数的计算，属于中档题．9．已知定义域为R 的奇函数y=f （x ）的导函数为y=f ′（x ），当x ≠0时，f ′（x ）+＞0，若a=f（），b=﹣2f （﹣2），c=（ln ）f （ln ），则a ，b ，c 的大小关系正确的是（ ） A ．a ＜b ＜c B ．b ＜c ＜a C ．a ＜c ＜b D ．c ＜a ＜b 【考点】利用导数研究函数的单调性． 【专题】导数的概念及应用．【分析】利用条件构造函数h （x ）=xf （x ），然后利用导数研究函数h （x ）的单调性，利用函数的单调性比较大小．【解答】解：设h （x ）=xf （x ）， ∴h ′（x ）=f （x ）+x •f ′（x ），∵y=f （x ）是定义在实数集R 上的奇函数， ∴h （x ）是定义在实数集R 上的偶函数， 当x ＞0时，h'（x ）=f （x ）+x •f ′（x ）＞0， ∴此时函数h （x ）单调递增．∵a=f （）=h （），b=﹣2f （﹣2）=2f （2）=h （2），c=（ln ）f （ln ）=h （ln ）=h （﹣ln2）=h （ln2），又2＞ln2＞， ∴b ＞c ＞a ．故选：C．【点评】本题考查如何构造新的函数，利用单调性比较大小，是常见的题目．本题属于中档题．10．已知F1，F2分别是双曲线﹣=1（a＞b＞0）的两个焦点，A和B是以O（O为坐标原点）为圆心，|OF1|为半径的圆与该双曲线左支的两个交点，且△F2AB是等边三角形，则双曲线的离心率为（）A．B．C．D．+1【考点】双曲线的简单性质．【专题】计算题；数形结合．【分析】先设F1F2=2c，根据△F2AB是等边三角形，判断出∠AF2F1=30°，进而在RT△AF1F2中求得AF1和AF2，进而根据栓曲线的简单性质求得a，则双曲线的离心率可得．【解答】解：如图，设F1F2=2c，∵△F2AB是等边三角形，∴∠AF2F1=30°，∴AF1=c，AF2=C，∴a=e==+1，故选D【点评】本题主要考查了双曲线的简单性质．考查了学生综合分析问题和数形结合的思想的运用．属基础题．11．若函数f（x）=sin（3x+φ），满足f（a+x）=f（a﹣x），则的值为（）A．B．±1 C．0 D．【考点】正弦函数的对称性；三角函数的化简求值．【专题】计算题；三角函数的图像与性质．【分析】由题意求出函数的对称轴，函数的周期，利用正弦函数的基本性质即可求出的值．【解答】解：对于任意的x∈R，函数f（x）=sin（3x+φ），满足条件f（a+x）=f（a﹣x），∴函数关于x=a对称，x=a时函数取得最值，∴3a+φ=k，k∈Z，∴=sin（3a++φ）=sin（+）=0；故选：C．【点评】本题是中档题，考查三角函数的基本性质，函数的周期对称性的应用，三角函数的最值是解题的关键，考查计算能力．12．已知f（x）、g（x）都是定义在R上的函数，g（x）≠0，f′（x）g（x）＜f（x）g′（x），f（x）=a x g（x），，在有穷数列（n=1，2，…，10）中，任意取前k项相加，则前k项和大于的概率是（）A．B．C．D．【考点】数列的应用；抽象函数及其应用；等可能事件的概率．【专题】计算题；压轴题．【分析】令，由题意可知0＜a＜1，由，可知，由此可知S n的表达式，由得n＞6，由此能够求出前k项和大于的概率．【解答】解：令，则，故h（x）=a x单调递减，所以0＜a＜1，又，解得，则，其前n项和，由得n＞6，故所求概率．故选B．【点评】本题考查概率的求法和导数的性质，解题时要注意公式的灵活运用．二、填空题（本大题共4小题，每小题5分，共20分）13．对大于1的自然数m的三次幂可用奇数进行以下方式的“分裂”：23，33，43，…仿此，若m3的“分裂”数中有一个是73，则m的值为9．【考点】等差数列的通项公式；数列的函数特性．【专题】等差数列与等比数列．=2（m﹣1），累加由等差数【分析】由题意可得a3﹣a2=7﹣3=4=2×2，a4﹣a3=13﹣7=6=2×3，…a m﹣a m﹣1列的求和公式可得a m，验证可得．【解答】解：由题意可得m3的“分裂”数为m个连续奇数，设m3的“分裂”数中第一个数为a m，则由题意可得a3﹣a2=7﹣3=4=2×2，a4﹣a3=13﹣7=6=2×3，=2（m﹣1），…a m﹣a m﹣1以上m﹣2个式子相加可得a m﹣a2==（m+1）（m﹣2），∴a m=a2+（m+1）（m﹣2）=m2﹣m+1，∴当m=9时，a m=73，即73是93的“分裂”数中的第一个故答案为：9【点评】本题考查等差数列的通项公式和求和公式，涉及累加法求数列的通项公式，属中档题．14．设α为锐角，若cos（α+）=，则sin（α﹣）=﹣．【考点】两角和与差的正弦函数．【专题】三角函数的求值．【分析】先求出sin（α+）=，再sin（α﹣）=sin（（α+）﹣），利用两角和与差的正弦函数展开即可由特殊角的三角函数值求解．【解答】解：∵α为锐角，cos（α+）=，则sin（α+）=，∴sin（α﹣）=sin（（α+）﹣）=sin（α+）cos﹣cos（α+）sin=﹣，故答案为：﹣．【点评】本题主要考查了两角和与差的正弦公式的应用，考查了特殊角的三角函数值的应用，属于基本知识的考查．15．设x，y满足约束条件，则x2+y2的最大值为29．【考点】简单线性规划的应用．【专题】不等式的解法及应用．【分析】先根据约束条件画出可行域，再利用几何意义求最值，z=x2+y2表示（0，0）到可行域的距离的平方，只需求出（0，0）到可行域的距离的最大值即可．【解答】解：根据约束条件画出可行域z=x2+y2表示（0，0）到可行域的距离的平方，当在区域内点A时，距离最大，，可得A（2，5）最大距离为，x2+y2的最大值为：29．故答案为：29．【点评】本题主要考查了简单的线性规划的应用，以及利用几何意义求最值，属于中档题．16．已知偶函数f（x）满足f（x+1）=﹣，且当x∈[﹣1，0]时，f（x）=x2，若在区间[﹣1，3]内，函数g（x）=f（x）﹣log a（x+2）有4个零点，则实数a的取值范围是[5，+∞）．【考点】抽象函数及其应用；函数的零点与方程根的关系．【专题】综合题；函数的性质及应用．【分析】根据f（x+1）=﹣，可得f（x）是周期为2的周期函数．再由f（x）是偶函数，当x∈[﹣1，0]时，f（x）=x2，可得函数在[﹣1，3]上的解析式．根据题意可得函数y=f（x）的图象与y=log a（x+2有4个交点，即可得实数a的取值范围．【解答】解：函数f（x）满足f（x+1）=﹣，故有f（x+2）=f（x），故f（x）是周期为2的周期函数．再由f（x）是偶函数，当x∈[﹣1，0]时，f（x）=x2，可得当x∈[0，1]时，f（x）=x2，故当x∈[﹣1，1]时，f（x）=x2 ，当x∈[1，3]时，f（x）=（x﹣2）2．由于函数g（x）=f（x）﹣log a（x+2）有4个零点，故函数y=f（x）的图象与y=log a（x+2）有4个交点，所以可得1≥log a（3+2），∴实数a的取值范围是[5，+∞）．故答案为：[5，+∞）．【点评】本题主要考查函数的周期性的应用，函数的零点与方程的根的关系，体现了转化的数学思想，属于基础题．三、解答题（本大题共5小题，每题12分，共60分）17．已知函数f（x）=2sinxcosx﹣2cos2x+1．（I）求函数f（x）的最小正周期；（Ⅱ）将函数f（x）的图象向左平移个单位，得到函数g（x）的图象．在△ABC中，角A，B，C的对边分别为a，b，c，若g（）=1，a=2，b+c=4，求△ABC的面积．【考点】三角函数中的恒等变换应用；函数y=Asin（ωx+φ）的图象变换．【专题】三角函数的图像与性质．【分析】（I）首先，利用降幂公式、辅助角公式化简函数解析式，然后，根据三角函数的周期公式进行求解即可；（Ⅱ）借助于三角函数的图象变换，得到函数g（x）的解析式，然后，结合余弦定理，确定其三角形的面积．【解答】解：（Ⅰ）f（x）=2sinxcosx﹣2cos2x+1=sin2x﹣cos2x=2sin（2x﹣）…所以，函数f（x）的最小正周期为T==π．…（Ⅱ）g（x）=f（x+）=2sin[2（x+）﹣]=2sin（2x+）=2cos2x﹣﹣﹣﹣﹣﹣﹣﹣﹣g（）=2cosA=1，∴cosA=，∵0＜A＜π，∴A=，﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣在△ABC中，利用余弦定理，得a2=b2+c2﹣2bccosA，∴4=b2+c2﹣2bc=（b+c）2﹣2bc，∴bc=4，∴S△ABC=bcsinA=×4×=．…【点评】本题属于综合题，综合考查了三角公式、二倍角公式、辅助角公式、三角函数的图象与性质等知识，属于中档题．18．如图，已知四边形ABCD是正方形，PD⊥平面ABCD，CD=PD=2EA，PD∥EA，F，G，H分别为PB，BE，PC的中点．（I）求证：GH∥平面PDAE；（II）求证：平面FGH⊥平面PCD．【考点】直线与平面平行的判定；平面与平面垂直的判定．【专题】空间位置关系与距离．【分析】（Ⅰ）分别取PD的中点M，EA的中点N，连结MH、NG、MN，由已知得四边形CHMN是平行四边形，由此能证明GH∥平面PDAE．（Ⅱ）由线面垂直得PD⊥BC，由已知得BC⊥CD，从而BC⊥平面PCD，由三角形中位线定理得FH∥BC，从而FH⊥平面PCD，由此能证明平面FGH⊥平面PCD．【解答】证明：（Ⅰ）分别取PD的中点M，EA的中点N，连结MH、NG、MN，∵G，H分别是BE，PC的中点，∴MH，NG，∵AB CD，∴MH NG，∴四边形CHMN是平行四边形，∴GH∥MN，又∵GH⊄平面PDAE，MN⊂平面PDAE，∴GH∥平面PDAE．（Ⅱ）∵PD⊥平面ABCD，BC⊂平面ABCD，∴PD⊥BC，∵BC⊥CD，PD∩CD=D，∴BC⊥平面PCD，∵F，H分别为PB、PC的中点，∴FH∥BC，∴FH⊥平面PCD，∵FH⊂平面FGH，∴平面FGH⊥平面PCD．【点评】本题考查线面平行的证明，考查面面垂直的证明，考查空间向量在立体几何中的应用，意在考查方程思想、等价转化思想等数学思想方法和学生的空间想象能力、逻辑推理能力和运算求解能力．19．某校学习小组开展“学生数学成绩与化学成绩的关系”的课题研究，对该校高二年级800名学生上学期期数学和化学成绩，按优秀和不优秀分类得结果：数学和化学都优秀的有60人，数学成绩优秀但化学不优秀的有140人，化学成绩优秀但数学不优秀的有100人．（Ⅰ）补充完整表格并判断能否在犯错概率不超过0.001前提下认为该校学生的数学成绩与化学成绩有关系？数学优秀数学不优秀总计化学优秀60100160化学不优秀140500640总计200600800（Ⅱ）现有4名成员甲、乙、丙、丁随机分成两组，每组2人，一组负责收集成绩，另一组负责数据处理．求学生甲分到负责收集成绩组，学生乙分到负责数据处理组的概率．p（K2＞k0）0.010 0.005 0.001k0 6.635 7.879 10.828附：K2=．【考点】独立性检验．【专题】应用题；数形结合；综合法；概率与统计．【分析】（Ⅰ）先写出列联表，再利用公式求出K2的值，与临界值比较，即可得到结论；（Ⅱ）先列表对称分组的情况，学生甲负责收集成绩且学生乙负责数据处理的情况，利用概率公式，即可求得结论．【解答】解：（Ⅰ）列联表：数学优秀数学不优秀总计化学优秀60 100 160化学不优秀140 500 640总计200 600 800∵∴能在犯错误不超过0.001的前提下认为该校学生的数学与化学成绩有关系（Ⅱ）设其他学生为丙和丁，4人分组的所有情况如下：（甲乙，丙丁），（甲丙，乙丁），（甲丁，乙丙），（乙丙，甲丁），（乙丁，甲丙），（丙丁，甲乙）基本事件共六种，记“学生甲分到负责收集成绩组，学生乙分到负责数据处理”为事件A，则A包含的基本事件为（甲丙，乙丁），（甲丁，乙丙）共两种【点评】本题考查独立性检验知识，考查概率知识的运用，考查学生的计算能力，属于中档题．20．已知椭圆+=1（a＞b＞0）的离心率e=，直线y=x+1经过椭圆C的左焦点．（I）求椭圆C的方程；（Ⅱ）若过点M（2，0）的直线与椭圆C交于A，B两点，设P为椭圆上一点，且满足+=t（其中O为坐标原点），求实数t的取值范围．【考点】椭圆的简单性质．【专题】圆锥曲线中的最值与范围问题．【分析】（I）直线y=x+1与x轴交点为（﹣1，0），即椭圆的左焦点，可得c=1．又=，b2=a2﹣c2．即可得出．（Ⅱ）由题意知直线AB的斜率存在．设直线ABd的方程：y=k（k﹣2），与椭圆方程联立可得：（1+2k2）x2﹣8k2x+8k2﹣2=0．利用△＞0，解得k2．设A（x1，y1），B（x2，y2），P（x，y）．利用根与系数的关系及+=t，可得P坐标，代入椭圆方程即可得出．【解答】解：（I）直线y=x+1与x轴交点为（﹣1，0），即椭圆的左焦点，∴c=1．又=，∴a=，b2=a2﹣c2=1．故椭圆C的方程为=1．（Ⅱ）由题意知直线AB的斜率存在．设直线ABd的方程：y=k（k﹣2），联立，化为：（1+2k2）x2﹣8k2x+8k2﹣2=0．△=64k4﹣4（1+2k2）（8k2﹣2）＞0，解得k2．设A（x1，y1），B（x2，y2），P（x，y），则x1+x2=，x1x2=，∵+=t，∴x1+x2=tx，y1+y2=ty．x==，y===．∵点P在椭圆上，∴+2=2，∴16k2=t2（1+2k2），k2，∴t2===4，解得﹣2＜t＜2．，∴t的取值范围是为（﹣2，2）．【点评】本题考查了椭圆的标准方程及其性质、直线与椭圆相交问题、一元二次方程的根与系数的关系、向量坐标运算、不等式的性质，考查了推理能力与计算能力，属于难题．21．已知函数f（x）=e x+3x2﹣ax．（1）若f（x）在x=0处取得极值，求曲线y=f（x）在点（1，f（1））处的切线方程；（2）若关于x的不等式f（x）≥+ax+1在x≥时恒成立，试求实数a的取值范围．【考点】利用导数研究函数的极值；利用导数研究曲线上某点切线方程；导数在最大值、最小值问题中的应用．【专题】导数的综合应用．【分析】（1）对f（x）求导函数f'（x），由f'（0）=0，求出a的值，从而求得f（1）与f'（1），写出y=f（x）在点（1，f（1））处的切线方程；（2）由f（x）≥+ax+1在x≥时恒成立，得不等式，构造函数，利用导函数求g（x）在上的最小值即可．【解答】解：（Ⅰ）∵f（x）=e x+3x2﹣ax，∴f'（x）=e x+6x﹣a，∵f（x）在x=0处取得极值，∴f'（0）=e0﹣a=0，∴a=1，∴f（x）=e x+3x2﹣x，f'（x）=e x+6x﹣1，∴f（1）=e+2，f'（1）=e+5，∴曲线y=f（x）在点（1，f（1））处的切线方程为：y﹣（e+2）=（e+5）（x﹣1），即y=（e+5）x﹣3．（2）∵f（x）=e x+3x2﹣ax，且，∴，即，∵，∴，令，则．令，则φ'（x）=x（e x﹣1）．∵，∴φ'（x）＞0，∴φ（x）在上单调递增，∴，∴g'（x）＞0，∴g（x）在上单调递增，∴，∴，即a的取值范围是．【点评】本题考查了利用导数判定函数的单调性与求函数最值的问题，也考查了应用导数求曲线的切线方程与不等式恒成立问题，是难题．四.选做题，选择22、23、24中一题写在答题卡上．22．如图，圆O的直径AB=d，P是AB延长线上一点，BP=a，割线PCD交圆O于点C、D，过点P作AP的垂线，交直线AC于点E，交直线AD于点F．（Ⅰ）求证：∠PEC=∠PDF；（Ⅱ）求PE•PF的值．【考点】与圆有关的比例线段；圆周角定理．【专题】综合题．【分析】（Ⅰ）利用AB是圆O的直径，可得∠ACB=∠APE=90°，从而P、B、C、E四点共圆，又A，B，C，D四点共圆，利用四点共圆的性质，可得结论；（Ⅱ）证明D，C，E，F四点共圆，利用割线定理，即可求得结论．【解答】（Ⅰ）证明：连接BC，∵AB是圆O的直径，∴∠ACB=∠APE=90°，即P，B，C，E四点共圆，∴∠PEC=∠CBA．又A，B，C，D四点共圆，∴∠CBA=PDF，∴∠PEC=∠PDF；（Ⅱ）解：∵∠PEC=∠PDF，∴D，C，E，F四点共圆∴PE•PF=PC•PD=PB•PA=a（a+d）．【点评】本题考查圆的性质，考查四点共圆的判定，考查割线的性质，属于中档题．23．选修4﹣4：坐标系与参数方程已知在直角坐标系xOy中，圆锥曲线C的参数方程为（θ为参数），直线l经过定点P（2，3），倾斜角为．（1）写出直线l的参数方程和圆的标准方程；（2）设直线l与圆相交于A，B两点，求|PA|•|PB|的值．【考点】圆的参数方程；直线的参数方程．【专题】直线与圆．【分析】（1）利用平方关系即可得到圆锥曲线C的普通方程，利用直线的参数方程即可得出．（2）把直线的参数方程代入曲线C的方程和利用参数的几何意义即可得出．【解答】解：（1）由圆锥曲线C的参数方程为（θ为参数），消去参数θ化为x2+y2=16．（2）由直线l经过定点P（2，3），倾斜角为．直线上的点可以表示为（2+t×cos，3+t×sin），t为该点到P的距离；可得②把②代入①得，③设t1，t2是方程③的两个实根，则t1t2=﹣3∴|PA|•|PB|=|t1||t2|=|t1t2|=3【点评】熟练掌握三角函数的平方关系、直线参数方程的参数的几何意义是解题的关键．24．选修4﹣5：不等式选讲设f（x）=|x+1|+|x﹣3|．（1）解不等式f（x）≤3x+4；（2）若不等式f（x）≥m的解集为R，求实数m的取值范围．【考点】绝对值不等式的解法．【专题】计算题；不等式的解法及应用．【分析】（1）转化函数的表达式为分段函数的形式，结合x的范围，分别求解不等式的解集，然后求出并集即可．（2）利用绝对值的几何意义，求出函数的最小值，即可求出m的范围．【解答】选修4﹣5：不等式选讲解：（1）因为f（x）=|x+1|+|x﹣3|．所以，所以原不等式f（x）≤3x+4；等价于①或②或③，解得①无解，②0≤x≤3，③x＞3，因此不等式的解集为：{x|x≥0}．（2）由于不等式f（x）≥m的解集为R，所以f（x）min≥m，又f（x）=|x+1|+|x﹣3|≥|x+1+3﹣x|=4，即f（x）min=4，所以m≤4，即m的取值范围为（﹣∞，4]．【点评】本题考查绝对值不等式的解法，分类讨论思想的应用，考查分析问题解决问题的能力．。

考试时间 : 90 分钟总分 :100 分一、选择题（本题共14 小题，每题 4 分，共56 分。

1— 10 题为单项选择；11— 14 为多项选择，全选对的得 4 分，选对未选全的得 2 分）1．物体做匀加快直线运动，其加快度的大小为 2 m/s 2，那么，在任1秒内( )A ．物体的加快度必定等于物体速度的 2 倍B．物体的初速度必定比前 1 秒的末速度大 2 m/sC．物体的末速度必定比初速度大 2 m/sD．物体的末速度必定比前 1 秒的初速度大 2 m/s2．以下说法正确的选项是：（）A．有摩擦力存在的接触面上，必定同时有弹力存在B．有弹力存在的接触面上，必定同时有摩擦力存在C．两个有相对运动的物体，其接触面之间必定有摩擦力存在D．在接触面上，若弹力已确立，则摩擦力将不行能变化3．如下图，木块遇到F1=6N，F2=2N和摩擦力三个水平方向的力作用，静止在水面上，若撤去F1，木块遇到的协力( )A 等于零B ．大小为8N，水平向石C ．大小为6N，水平向右D ．大小为4N，水平向左4. 黄河公路大桥有很长的引桥，引桥的主要目的是( )A．减少汽车与路面的摩擦力B．减少汽车对路面的压力C．减少汽车重力沿桥面向下的分力D增大汽车重力沿桥面向下的分力5.如下图，在一次火警军事演习中，消防战士双手握住竖直的铁杆匀速攀上12m 高的楼台，达成指令后又沿铁杆匀速滑下，消防战士遇到铁杆的摩擦力分别记为 f 1和 f 2，那么()A ．f 1向下， f 2 向上，且f 1=f 2 B． f 1 向上， f 2向下，且 f 1=f 2C ． f 向下， f 向下，且 f =f2 D．f 向上， f 向上，且 f =f21 2 1 1 2 16．如下图，用一根细绳和一根轻直杆构成三角支架，绳的一端绕在手指上，杆的一端顶在手掌心，当 A 处挂上重物时，绳与杆敌手指和手掌均有作用，对这两个作使劲的方向判断完整正确的选项是图中的 ( )7．某欧式建筑物屋顶为半球形，一警卫人员为履行特别任务，一定冒险在半球形屋顶上向上迟缓爬行( 如图 ) ，他在向上爬过程中( )A ．屋顶对他的支持力变大B．屋顶对他的支持力变小C ．屋顶对他的摩擦力变大D．屋顶对他的摩擦力不变8．如下图，人站在自动扶梯的水平踏板上，随扶梯斜向上匀速运动，以下说法正确的是()A．人遇到重力和支持力的作用B．人遇到重力、支持力和摩擦力的作用C．人的重力和人对踏板的压力是一对均衡力D．人对踏板的压力就是人的重力9.如下图，用细线将 A 物体悬挂在顶板上， B 物体放在水平川面上 A、 B 间有一劲度系数为 100 N/m 的轻弹簧，此时弹簧伸长 2 cm。

河南省焦作武陟一中高二上学期第一次月考英语第二部分：英语知识运用（共两节，满分45分）第一节：单项选择（每小题1分，共15分）21. We believe that the Chinese astronauts will on the moon sooner or later.A. turn outB. turn upC. send upD. carry out22. —What do you think they are in praise of?—.A.For Tom to win the first prizeB.Tom’s winning the first prizeC.Tom won the first prizeD.Because Tom won the first prize23. Word came to the president at last there was no one injured in the traffic accident.A. thatB. whenC. whichD. who24. Whom does the much money the government spends , the farmers, the workers or the businessmen? None of them, I say.A. encourageB. locateC. benefitD. treat25. —Lucy doesn’t mind lending you her dictionary.—She . I’ve already borrowed one.A. can’tB. mustn’tC. needn’tD. shouldn’t26. —.—I think quite the opposite.A.She must be quite satisfied with the progress that has been madeB.Call me any time if you have any questionC.Can you come over and help me a while? I just can’t manage it.D.Nobody knows what he means. He just keeps his mouth closed all the way.27. We teachers must see to that every student can understand.A. allB. thatC. itD. one28. It was he set foot on the land he felt a warm flow through his whole body.A. immediately; thatB. as soon as, whichC. immediate; thatD. the moment; which29. A new basketball team is and it contains ten players whose ages between 12 and 16.A. found; coverB. created; consistC. built; changeD. formed; range30. China became the 143rd member of WTO on December 11,, thus its 15-year wish to join the global trade body.A. realizedB. to realizeC. having realizedD. realizing31. There is no doubt the price of meat will go up when the Spring Festival is coming.A. whetherB. aboutC. ifD. that32. When she wake up, she realized that things she had dreamed of could not have happened.A. possiblyB. likelyC. hardlyD. usually33. I would love to the concert last night, but I didn’t get the ticket for it.A. to goB. goingC. to be goneD. to have gone34. They will bring in a new project which a lot of money.A. calls forB. calls onC. calls atD. calls up35. He paid for a seat, when he have entered free.A. couldB. wouldC. mustD. need第二节：完形填空（每小题1. 5分，满分30分）Mr Adamson enjoys playing the violin in his spare time. He is often carried away（着迷）by his own 36 . But it is a 37 time for his neighbors when Mr Adamson plays as he 38 so badly.One day Mr. Adamson sat by a 39 and began to play the violin as usual. Mr Adamson seemed to be making 40 instead of music, but he was so 41 that he almost forgot what he was doing. Just 42 , some stones were thrown out of the window under 43 Mr Adamson was sitting, 44 he did not pay any attention to it. The “music” 45 . After a little while, an empty bottle and a worn-out shoe were thrown out of the window, 46 . Only then did Mr Adamson know that this was not the place for him to play in. Mr Adamson was very 47 . He thought, “ 48 no living people can understand my music, I should go to a place where people may appreciate my works. ” So he 49 to go to a graveyard.He came to a graveyard where there is no other 50 except the church toll（钟声）. Mr Adamson sat at a grave and thought 51 ,“I must do my best to 52 that my music is outstanding. ” The more he though, the more inspired he was, and 53 he began to play his violin. Suddenly a bare foot stretched（伸）out from the graveyard and gave Mr Adamson a heavy54 which sent him flying. His violin also dropped from his hand. Mr Adamson felt very sad 55 his worksas not accepted by anyone, not even the dead.36. A. violin B. music C. noise D. sound37. A. terrible B. useless C. wonderful D. long38. A. sings B. shouts C. dances D. does39. A. house B. door C. window D. wall40. A. sound B. something C. noises D. voices41. A. angry B. excited C. comfortable D. disappointed42. A. that B. right C. now D. then43. A. which B. it C. that D. where44. A. and B. but C. so D. for45. A. stopped B. began C. played D. continued46. A. together B. slowly C. too D. again47. A. happy B. sad C. glad D. tearful48. A. Perhaps B. Though C. If D. Even49. A. decided B. said C. thought D. knew50. A. person B. building C. thing D. sound51. A. anything B. his music C. a lot D. hardly52. A. show B. tell C. announce D. mean53. A. first B. again C. finally D. later54. A. kick B. beating C. wing D. shoe55. A. when B. and C. because D. so第三部分：阅读理解（每小题2分，满分40分）AThe faces of the elderly, happily-married people sometimes look like each other. Dr. Aiken studied a number of couples who had been married for at least twenty-five years. Each couple provided four photographs—one photo of each partner at the time of their marriage and another photo to remove any clues. The photos were then displayed in groups: a random（随意的）grouping of the persons at the time of their marriage and another random grouping of the same persons who took photographs later. Some judges were asked to pick out the partners. They failed totally with the first group. Their judgments were no better than chance. But with the photos taken twenty-five or more years after the marriage, the judges were quite successful at deciding who was married to whom. They were particularly successful with the most happily-married couples.Dr. Aiken believes there are several reasons why couples grow alike. One reason has something to do with imitation. One person tends to copy or do the same as someone else without knowing it. He says human beings copy the expressions of the faces of their loved ones. Another possible reason, he says, is the common experience of the couples. There is a tendency for people who have the same life experience to change their faces in similar ways. For example, if a couple suffered a lot of sad experiences, their faces are likely to change in a similar way.56. The main purpose of the passage is to .A.tell how couples look like each otherB.show the life experience of husband and wifeC.explain why couples grow alikeD.describe the study on a number of married people57. The judges failed to .A.tell couples by looking at their photos taken when they got marriedB.tell happily-married couples from sadly-married couplesC.discover the difference of each partnerD.understand Dr. Aiken’s study58. The underlined sentence “Their judgments were .A. quite successfulB. based on factsC. only by luckD. totally wrong59. From the passage we can draw a conclusion that .A.happily-married couples are often richer than other couplesB.couples who look alike can live longerC.the influence between couples can be quite strongD.all couples have been proved to grow alikeBWhen Li Jinyu went back from Brazil after years of hard training, he seemed to see a new starting point in front of him. Li, a key player of Jian Li Bao Football Team, has a round and lovely face. When talking to people, he often says, “I’ve got a lot of dreams, and the biggest one is to help to develop our national football.”Li began to play football 17 years ago. In 1985 a football coach was looking for little players in a school. Li tried to win the coach’s favor. His father, a football fan, asked the coach to give his son another chance to ha ve a test. This time, the coach agreed to take Li as a player. Every day, his father would take him to the training school, and carry him back when the training was over, whether it was raining or shining. With the help of his coach, Liquickly grew into a good young player. He is said to have the sharpest mind on the playground among all Chinese football players.The only child of the family as he is, Li loves his parents as much as they love him. During the spare time of the training course or after a game, he has often called home to ask after his parents.Li also enjoys good relations with his fans. He has received many letters from across the country, but he said he felt sorry because he could not answer every letter. “However, I have taken good care of every letter from my fans. This is perhaps the best way to show my thanks,” he said.Now at the age of 24, Li likes to go shopping after days of hard training on the playground. He is also interested in bowling and tennis. Dreaming of becoming a first-class player, he is now working very hard on the road to success.60. When did Li begin to play football?A. At the ege of 13.B. At the age of 7.C. Before starting school.D. After leaving school.61. We can learn from the passage that Li’s fa ther .A.has been encouraging him to play footballB.taught him to play football in 1985ed to be a football playerD.was his first coach62. It seemed that Li after years of hard training in Brazil.A.had got sharp mind on the playgroundB.had made much greater progressC.was considered as the best playerD.began to play football63. Li has worked hard at football so as to .A.show his thanks to his parentsB.keep good relations with his fansC.develop our national footballD.play abroadCThis is the time of a year when we think about giving and receiving presents. Can you find a little extra to give? On this page we suggest a few organizations you might like to help.Littleton Children’s HomeWe don’t want your money, but children’s toys, books and clothes in good condition would be very welcome.Also we are looking for friendly families who would take our children into their homes for a few hours or days as guests. You have so much—will you share it?Phone Sister Thomas on 55671.Children’s HospiceWe look after a small number of very sick children. This important work needs skill and love. We cannot continue without gifts of money to pay for more nursing staff. We also need storybooks and toys suitable for quiet games.Please contact The Secr etary, Little Children’s Hospice, Newby Road.Street FoodIn the winter weather, it’s no fun being homeless. It’s even worse if you’re hungry. We give hot food to at least fifty people every night. It’s hard work, but necessary. Can you come and help? If not, can you find a little money? We use a very old kitchen, and we urgently need some new saucepans. Money for new ones would be most welcome indeed.Contact Street Food, c/o Mary’s House, Elming Way. Littleton Phone 27713.Littleton Youth ClubHave you got an unwanted chair? —A record player? — A pot of paint?Because we can use them!We want to get to work on our meeting room!Please phone 66231 and we’ll be happy to collect anything you c an give us.Thank you!The Night ShelterWe offer a warm bed for the night to anyone who has nowhere to go. We rent the former Commercial Hotel on Green Street. Although it is not expensive, we never seem to have quite enough money. Can you let us have a few pounds? Any amount, however small, will be such a help.Send it to us at 15, Green St, Littleton. Please make the check payable to The Night Shelter.64. Reading the passage, you might like to help these organizations which work for .A.homeless and sick childrenB.less fortunate members of our societyC.hungry people who have no beds to sleep inD.warm-hearted members of our society65. If you like children and you could offer a happy family to a homeless child, you may go to .A. Street FoodB. The Night ShelterC. Littleton Children’s HomeD. Chi ldren’s Hospice66. We can infer that .A.there are too many social problems in this countryB.people are very poor during the time for givingC.warm-hearted people like to give away moneyD.this passage is taken from a local newspaper67. If you want to help but you have no extra to give, you may dial and offer your help.A. 27713B. 55671C. 62735D. 6623168. If your child has grown up, you may take the child’s things to .A.Littleton Children’s Home and Children’s HospiceB.Littleton Yout h Club and Littleton Children’s HomeC.Children’s Hospice and The Night ShelterD.Littleton Youth Club and The Night ShelterDDog is a popular pet throughout the world. At least 12,000 years ago, dogs became the first animals to be tamed（驯服）. Today, these lovely animals can be found almost anywhere there are people to love and serve. About 49 million dogs live as pets in the United States, and 3 million live in Canada.Dogs vary greatly in size. The smallest dog is the Chihuahua. On the average, Chihuahua weighs only about 4 pounds（1. 8 kilograms）and stands about 5 inches（13 centimeters）high at the shoulders. The tallest dog is the Irish wolfhound, which may grow 34 inches（86 centimeters）in height. The St. Bernard ranks as the heaviest dog. It weighs as much as pounds（90 kilograms）.Dogs belong to a small family of meat-eating animals that also includes wolves, coyotes（北美草原狼）, foxes, and jackals（豺）. Dogs look like these animals in body structure and behavior. The dingo of Australia and certain animals that live in other parts of the world are commonly called wild dogs.Some dogs do important work for people. Dogs are able and willing to learn a wide variety of tasks becausethey are clever and devoted（忠诚的）to their owners. Sharp watchdogs protect houses and businesses from thieves. Collies, sheepdogs, and some other dogs look after cattle. In some countries, dogs help farmers by pulling vegetables and other products to market in small carts.Dogs also use their keen senses to help people. A sharp sense of smell enables beagles and many other hunting dogs to follow wild animals. Police rely on the bloodhound’s sensitive（敏感的）nose to find criminals （罪犯）and lost people. Law enforcement officers also train German shepherds and other dogs. to smell drugs and hidden explosives（炸药）. Guide dogs lead blind people. Other specially trained dogs serve as “ears” for deaf people.Medical researchers use thousands of dogs in experiments every year. In this way, dogs have helped scientists develop new lifesaving drugs and new surgical techniques（外科技术）. However, some people believe that it is cruel to use dogs—as well as other animals—in laboratory experiments.69. The second paragraph mainly talks about the of dogs.A. weightB. heightC. sizeD. growth70. The underlined word “beagles” in the fifth paragraph is dogs’ .A. nameB. familyC. weightD. sense71. According to the passage, in how many ways can dogs help people?A. Six.B. Five.C. Four.D. Eight.72. What’s the main idea of the passage?A.Some dogs do important work for people.B.Dogs can do a lot of good to people.C.Dogs are different in many ways.D.Dog is a popular pet.EThe problem started when the family moved and Chris switched schools. He made friends with a new set of kids, some of whom used drugs. The first time Chris used cocaine（可卡因）was with friends at Larry’s house. Everyone pooled their money to buy a few grams of cocaine. Larry told them, “It’s safe as long as you don’t use it too often. It won’t turn you into an add ict（上瘾者）like other drugs. ”During the following year, the group tried crack along with cocaine. Chris bragged, “I can handle this material!”Larry agreed, “As long as you only take a little bit, you’ll be okay. ” He said he sold it to them “at cost” anddescribed（描述）it as “pure cocaine”.When one friend ended up in the hospital from an overdose（过量）, Chris thought, “That’ll never happen to me. Since I’m mostly sniffing（smelling）the drug, I won’t have any problem. ”At 16, Chris dropped out of school. When his parents tried to change his mind, he left home without telling them where he was going. He lasted two weeks working at a pizza parlor（shop）before getting fired for stealing money. That’s when he started selling cocaine. “I’ll only do this until I get back on my feet,” he told himself.Chris’ family found him living alone in a run-down part of town. A school friend has called the family to tell them where he was. “It probably saved my life,” Chris says. “I was half-dead. ”To pay for Chris to enter a drug treatment center, his dad took a second job. Chris is grateful to getting treatment. Now he’s able to see colors again. In the depths of his addiction he saw everything in black and gray.73. Chris began to use cocaine .A.when his friend, Larry, persuaded him to do soB.because he wanted to try it only on his ownC.when all of his friends taught him how to use itD.because he liked it very much74. Which of the following is TRUE?A.Chris got crack and cocaine from Larry free of charge.rry sold crack and cocaine to Chris and some of his friends.C.It is safe to use a little cocaine.D.Chris used cocaine for half a year.75. From the last paragraph, we can learn that .A.Chris gets free treatmentB.Chris wants to thank his parents for paying for his treatmentC.Chris’ dad works hard in order to be richD.Chris has good eyesight in seeing colors第Ⅱ卷（一部分，共35分）第四部分：写作（共两节，满分35分）第一节：短文改错（共10小题; 每小题1分，满分10分）A family is sailing around the Pacific Ocean. They areon a 48-feet yacht（快艇）. The trip will take them away from home 76. ______for a year. They stay on touch with their family and friends 77. ______by e-mail. The children send e-mail to her grandmother three 78. ______or four times a week. The father sends e-mail to his officeevery day. He also got weather information by e-mail. 79. ______E-mail on the sea takes the more time than on land. 80. ______The family’s computer connects by a piece of equipment81. ______to short-wave radio. The radio sends the message, letter by letter 82. ______to the Internet. The grandmother gets the message from the Internet.The grandmother learned to use the Internet just before leave her job. 83. ______Near 8 million senior citizens use the Internet—that is twice 84. ______as much as a year ago. The most important reason is getting 85. ______information from their families.第二节：书面表达（满分25分）你班最近就“中学生课余时间上网的利弊”召开一次主题班会，同学们各抒已见，畅所欲言，作为班长，请你根据下列信息，作总结性发言。

武陟一中高一数学试卷第Ⅰ卷（选择题，共60分）一、选择题（本大题共12小题，每小题5分，共60分．在每小题给出的四个选项中，只有一项是符合题目要求的）1．将分针拨慢5分钟，则分钟转过的弧度数是 （ ） A ．3πB ．－3π C ．6π D ．－6π2．已知角α的终边过点()m m P 34，-，()0≠m ，则ααcos sin 2+的值是（ ）A ．1或－1B ．52或52- C ．1或52- D ．－1或52 3.抽查10件产品，设事件A ：至少有两件次品，A 的对立事件为 ( )A.至多两件次品B.至多一件次品C.至多两件正品D.至少两件正品4.点(sin cos ,tan )P ααα-在第一象限,则在[0,2)π内α的取值范围（ ）A.35(,)(,)244ππππ B.5(,)(,)424ππππC.353(,)(,)2442ππππD.33(,)(,)244ππππ5.若|2|=a ，2||=b 且（b a -）⊥a ，则a 与b 的夹角是 （ ）A.6π B.4π C.3π D.π1256.已知函数B x A y ++=)sin(ϕϖ的一部分图象如右图所示，如果2||,0,0πϕϖ<>>A ，则（ ）A.4=AB.1=ϖC.6πϕ=D.4=B7．已知直线l 的方向向量为），（5354-e = ，点O （0，0）和A （1，-2）在l 上的射影分别为E ，F ，若等于，则λλe EF=（ ） A ．511B ．511-C ．2D ．2-8.右边的程序框图输出的是，则条件①可为 （ ） A ． B ． C ． D ．9.设i =(1,0),j =(0,1),j i k b j i a 4,32+=+=,若b a ⊥，则实数k 的值为（ ）A ．－6B ．－3C ．3D ．6 10.函数)34cos(3)34sin(3x x y -+-=ππ的最小正周期为（ ）A ．32πB ．3πC ．8D ．411．已知变量a ,b 已被赋值，要交换a, b 的值，应用下面（ ）的算法。