11崇明二模(含答案)
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杨浦区(崇明县)2010学年度第二学期基础测试初三英语练习卷2011.4.8(完卷时间:100分钟,答案一律写在答题纸上)Part 2 Vocabulary and GrammarV. Choose the best answer (选择最恰当的答案):(共26分)31. Kitty is such ______honest student that she is often praised by her teachers.A) a B)an C)the D)/32. My wish is to become a scientist when I grow up. What is______, Betty?A) yours B) your C)you D) yourself33. It's getting warmer and warmer. Do you still get up______6:30 every day?A) on B)in C)at D)by34. I'm afraid this pair of trousers is too small. Would you please show me ______ pair?A) the other B) other C) others D) another35.Since I'm very familiar _____this area, they expect me to show them around.A) from B)to C)with D)for36. The foreign visitor could speak only _____ Chinese, but he managed to communicate with us.A) few B) little C)a few D)a little37. ---You look so happy!---Mary says I'm cool. ______has ever told me that before.A) Somebody B) Anybody C) Nobody D) Everybody38.I telephoned Jane just now, but she wasn't in. I had to leave her a(n)______.A) message B) advice C) information D) paper39.______it is! The government is planning to build more low-cost houses for its people.A) How good news B) What good news-C) How good a news D) What a good news40. It is reported that more than people have been killed in this big earthquake.A) two thousands B) thousands of C) thousand of D) two thousand41. Because of nuclear leakage (核泄漏), people and food arriving in China from Japan _______ receive strict checks for radiation (辐射).A) must B)may C)can D)ought42. The pizza they offered us tasted______, and we all wanted to have some more.A) wet!B) awful C)good D) wonderfully43. In winter the ______it snows, the happier the children will feel.A) heavy B) more heavily C) heavily D) heavier44. When I got to the classroom just now. I found that Tom ______on a math problem.A) worked B) works C) will work D) was working45. A record number of people ______Shanghai An Museum since it charged no entrance fee (费) in early March.A) have visited B) will visit C) had visited D) visited46.---Alice, where did you go last night?---I ______to go to Tom's birthday party.A) asked B) have asked C) have been asked D) was asked47. You had better let John ______milk and bread for breakfast himself. He's ten years old now.A) buys B)buy C) to buy D) buying48.Don't go out, ______you'll be caught in the rain.A) and B) since C)or D) until49- Susan finally became a popular singer after she practiced ______ for years.A) sing B) to sing C)sang D) singing50 If you travel around the world, you will be surprised at_______.A) how different the foreign customs are B) how the foreign customs are differentC) how different are the foreign customs D) how are the foreign customs different51. More and more foreigners are living and working in Shanghai at present. The underlined part means "______".A) at a time ,B) at the moment C) just now D) from time to time52 Father lost temper after he was told her daughter stole a mobile phone from her desk mate. The underlined part means "______”.A) became angry B) held his breath C) went wrong D) ran away53. Many Junior Three students ______their hobbies because of their busy school work.A) stay up B) take up C) give up D) put up54. Mike's parents were worried that he ______too much time chatting online.A) paid B)cost C)took D) spent55. ---Shall I get you some more milk?---______I have had enough.A) No. you needn't B) I'm afraid you can'tC) I'm glad you like it.D) I'm very' happy.56. ---Would you mind my opening the window?---______.A) Never mind.B) Certainly not.C)No. I wouldn't D) Yes. I'd love to.VI. Complete the sentences with the given words in their proper forms (用括号中所给单词的适当形式完成下列句子,每空格限填一词):(共8分)57. It is necessary for everyone to brush his. ________ after each meal. (tooth)58. I have bought a new flat and it's on the ________floor of the building.(eight)59. As middle school students, we should know how to look after________. (us)60. The student missed the ________tour around Sheng Long Agricultural Park. (enjoy)61.We received Peter's _______and went to his birthday party happily, (invite)62. The serious fire _______ destroyed the whole building last November. (complete)63. It was _________for such a little girl to solve this hard problem in ten minutes, (usual)64. Make a plan for your future study, and you will ________in the end. (successful)VII. Rewrite the following sentences as required.(根据所给要求,改写下列句子。
2023年上海市崇明区高考数学二模试卷1. 若不等式,则x的取值范围是______ .2. 设复数z满足是虚数单位,则______ .3. 已知集合,,若,则实数a的值为______.4. 已知函数,的最小正周期为1,则______ .5. 已知正实数a、b满足,则的最小值等于______ .6. 在的展开式中常数项是____________用数字作答7. 以下数据为参加数学竞赛决赛的15人的成绩单位:分,分数从低到高依次:56,70,72,78,79,80,81,83,84,86,88,90,91,94,98,则这15人成绩的第80百分位数是______ .8. 某单位为了了解用电量y度与气温之间的关系,随机统计了某4天的用电量与当天气温.气温141286用电量度22263438由表中数据所得回归直线方程为,据此预测当气温为时,用电量的度数约为______9.已知抛物线上的两个不同的点A,B的横坐标恰好是方程的根,则直线AB的方程为______.10. 在一个十字路口,每次亮绿灯的时长为30秒,那么,每次绿灯亮时,在一条直行道路上能有多少汽车通过?这个问题涉及车长、车距、车速、堵塞的干扰等多种因素,不同型号车的车长是不同的,驾驶员的习惯不同也会使车距、车速不同,行人和非机动车的干扰因素则复杂且不确定.面对这些不同和不确定,需要作出假设.例如小明发现虽然通过路口的车辆各种各样,但多数是小轿车,因此小明给出如下假设:通过路口的车辆长度都相等,请写出一个你认为合理的假设______ .11. 设平面向量满足:,,,,则的取值范围是______ .12. 若函数的图像上点A与点B、点C与点D分别关于原点对称,除此之外,不存在函数图像上的其它两点关于原点对称,则实数a的取值范围是______ .13. 下列函数中,既是定义域内单调递增函数,又是奇函数的为( )A. B. C. D.14. 设两个正态分布和的密度函数图像如图所示.则有( )A. ,B. ,C. ,D. ,15. 《九章算术》中将底面为直角三角形且侧棱垂直于底面的三棱柱称为“堑堵”;底面为矩形,一条侧棱垂直于底面的四棱锥称之为“阳马”;四个面均为直角三角形的四面体称为“鳌臑”.如图,在堑堵中,,且下列说法错误的是( )A. 四棱锥为“阳马”B. 四面体为“鳖臑”C. 四棱锥体积的最大值为D. 过A点作于点E,过E点作于点F,则面AEF16. 已知数列是各项为正数的等比数列,公比为q,在,之间插入1个数,使这3个数成等差数列,记公差为,在,之间插入2个数,使这4个数成等差数列,公差为,⋯,在,之间插入n个数,使这个数成等差数列,公差为,则( )A. 当时,数列单调递减B. 当时,数列单调递增C. 当时,数列单调递减D. 当时,数列单调递增17. 如图,已知点P在圆柱的底面圆O的圆周上,AB为圆O的直径,圆柱的表面积为,,求直线与平面ABP所成角的大小;求点A到平面的距离.18. 在中,a,b,c分别是内角A,B,C的对边,,,求角B大小;设,当时,求的最小值及相应的19. 某校工会开展健步走活动,要求教职工上传3月1日至3月7日微信记步数信息,下图是职工甲和职工乙微信记步数情况:从3月1日至3月7日中任选一天,求这一天职工甲和职工乙微信记步数都不低于10000的概率;从3月1日至3月7日中任选两天,记职工乙在这两天中微信记步数不低于10000的天数为X,求X的分布列及数学期望;如图是校工会根据3月1日至3月7日某一天的数据,制作的全校200名教职工微信记步数的频率分布直方图.已知这一天甲和乙微信记步数在单位200名教职工中排名分别为第68和第142,请指出这是根据哪一天的数据制作的频率分布直方图不用说明理由20. 已知椭圆:,点A,B分别是椭圆与y轴的交点点A在点B的上方,过点且斜率为k的直线l交椭圆于E,G两点.若椭圆焦点在x轴上,且其离心率是,求实数m的值;若,求的面积;设直线AE与直线交于点H,证明:B,G,H三点共线.21. 已知定义域为D的函数,其导函数为,满足对任意的都有若,,求实数a的取值范围;证明:方程至多只有一个实根;若,是周期为2的周期函数,证明:对任意的实数,,都有答案和解析1.【答案】【解析】解:,则,解得,的取值范围是故答案为:根据绝对值的几何意义解不等式.本题考查绝对值不等式的解法,考查运算求解能力,属于基础题.2.【答案】【解析】解:,故答案为:把给出的等式变形后直接利用复数代数形式的乘除运算化简求值.本题考查了复数代数形式的乘除运算,是基础题.3.【答案】0【解析】解:集合,,,或,当时,,,不成立;当时,,,,成立.故实数a的值为故答案为:由集合,,,得或,由此能出实数a的值.本题考查实数值的求法,是基础题,解题时要认真审题,注意交集定义的合理运用.4.【答案】【解析】解:,依题意,;故答案为:根据三角函数周期与角频率的关系求解.本题主要考查三角函数的周期性,属于基础题.5.【答案】4【解析】解:,当,即,时等号成立,故的最小值为故答案为:直接利用基本不等式计算得到答案.本题主要考查基本不等式及其应用,属于基础题.6.【答案】45【解析】解:要求常数项,即,可得代入通项公式可得故答案为:利用二项式的通项公式让次数为0,求出就可求出答案.二项展开式的通项公式是解决二项展开式的特定项问题的工具.7.【答案】【解析】解:因为,故这15人成绩的第80百分位数为故答案为:计算,即可确定这15人成绩的第80百分位数为第12和第13个数据的平均数,由此可得答案.本题主要考查百分位数的定义,属于基础题.8.【答案】40【解析】解:根据表格数据可得,,,则样本中心点为根据回归直线性质,经过样本点中心,则有,得,故回归直线为,当,故答案为:利用回归直线经过样本点的中心,先算出,然后令代入回归直线进行求解.本题主要考查线性回归方程,考查运算求解能力,属于基础题.9.【答案】【解析】解:由题意,直线AB的斜率存在,设直线AB的方程为,,,因为点A,B的横坐标恰好是方程的根,所以,,联立,消y得,则,,所以,,所以,,经检验,符合题意,所以直线AB的方程为故答案为:设直线AB的方程为,,,根据题意结合韦达定理可得,,联立方程,再次里由韦达定理求得,,从而可求出k,b,即可得解.本题考查直线与抛物线的综合运用,考查运算求解能力,属于中档题.10.【答案】等待时,前后相邻两辆车的车距都相等答案不唯一【解析】解:根据题意和相关因素的分析,可以作出有利于建立模型、基本符合实际情况的假设,例如①等待时,前后相邻两辆车的车距都相等;②绿灯亮后,汽车都是在静止状态下匀加速启动;③前一辆车启动后,下一辆车启动的延时时间相等;④车辆行驶秩序良好,不会发生堵塞,等等.故答案为:等待时,前后相邻两辆车的车距都相等答案不唯一利用数学建模,根据题意这次建模就只考虑小轿车的情况,根据小轿车的长度差距不大,对相关因素进行分析,从而可以作出有利于建立模型、基本符合实际情况的假设即可.本题主要考查简单的合情推理,属于基础题.11.【答案】【解析】解:依题意,设,,根据,即,即,整理得显然,否则,,与已知矛盾,故,可得由,即,则有,故,解得故故答案为:根据题设条件,设出的坐标,利用坐标运算进行求解.本题考查平面向量的综合运用,考查运算求解能力,属于中档题.12.【答案】【解析】解:若有两组点关于原点对称,则在的图像关于原点对称后与的图像有两个交点,由时,;得其关于原点对称后的解析式为,问题转化为与在上有两个交点,即方程有两根,化简得,即与在上有两个交点.对于,求导,令,解得,即:当时,单调递增;令,解得:即:当时,单调递减,为其极大值点,,时,;画出其大致图像:欲使与在时有两个交点,则,即故答案为:由题意将问题转化为在的图像关于原点对称后与的图像有两个交点,即转化为方程在上有两根,孤立参数为在上有两根,求导确定函数的单调性与取值情况,作出大致图象,即可求得实数a的取值范围.本题主要考查分段函数的应用,考查转化能力,属于中档题.13.【答案】D【解析】解:A项中,,则是奇函数,但在定义域内不单调,不符合;B项中,,是奇函数,但在定义域内不单调,不符合;C项中,,则为非奇非偶函数,不符合;D项中,,是奇函数,又在上单调递增,在上单调递减,则在上单调递增,符合.故选:根据奇函数定义判断奇偶性,根据函数的图象判断单调性,但要注意单调区间是定义域的子集.本题考查函数的奇偶性,单调性,属于基础题.14.【答案】A【解析】解:根据正态分布函数的性质:是正态分布曲线的对称轴;反应的正态分布的离散程度,越大,越分散,曲线越“矮胖”,越小,越集中,曲线越“瘦高”,由图象可得,故选:根据正态分布的性质即可得解.本题主要考查正态分布曲线的特点,属于基础题.15.【答案】C【解析】解:底面为直角三角形且侧棱垂直于底面的三棱柱称为“堑堵”,在堑堵中,,侧棱平面ABC,A选项,,又,且,则平面,四棱锥为“阳马”,故A正确;B 选项,由,即,又且,,平面,,则为直角三角形,又由平面,得为直角三角形,由“堑堵”的定义可得为直角三角形,为直角三角形,四面体为“鳌臑”,故B正确;C 选项,在底面有,即,当且仅当时取等号,,最大值为,故C错误;D选项,因为,,,所以平面AEF,故D正确;故选:根据“阳马”和“鳌臑”的定义,可判断A,B的正误;当且仅当时,四棱锥体积有最大值,求值可判断C的正误;根据题意可证平面AEF,进而判断D的正误.本题考查了立体几何的综合应用,属于中档题.16.【答案】D【解析】解:数列是各项为正数的等比数列,公比为q,由题意,,,对于,,这个数列是单调递增的数列,最小的一项即第一项为,则是否大于1,不确定,A,B错误,当时,,则此时必有,则数列单调递增,则D 项正确,C项错误.故选:将表示出来,由于数列各项为正数,若,才是递增数列,围绕条件进行讨论是否大于本题考查递推式,考查递增数列需满足的条件,属于中档题.17.【答案】解:由题意知,直线与平面ABP的夹角,即为,易知,,又,故,进而有,,由圆柱的表面积为,可得,故,故直线与平面ABP的夹角为设点A到平面的距离为h,则,,,因为平面ABP,,所以平面,即,在中,,故,所以,即点A到平面的距离为【解析】根据圆柱的特征可得直线与平面ABP的夹角,即为,然后利用圆柱的表面积为求出,求出,进而求解;利用等体积转化法即可求解.本题考查线面角的定义及其求解,考查点到平面的距离以及等体积法的运用,考查运算求解能力,属于中档题.18.【答案】解:由已知条件得,由正弦定理得,即,,则,,,又,;,,,则的最小值,其中,即当时,有最小值【解析】本题考查了三角函数中的恒等变换,正余弦定理以及三角函数的性质,属于中档题.利用向量垂直的充要条件和正弦定理即可求解;先利用两角和的正弦公式及余弦的二倍角公式化简,再用辅助角公式化为,最后利用三角函数的性质求出最小值及其取得最小值时的x值.19.【答案】解:设“职工甲和职工乙微信记步数都不低于10000”为事件A…分从3月1日至3月7日这七天中,3月2日,3月5日,3月7日这三天职工甲和职工乙微信记步数都不低于10000,所以;…分的所有可能取值为0,1,2,…分,,分X的分布列为X012P…分;…分月3日…分由直方图知,微信记步数落在,单位:千步区间内的人数依次为,,,,据折线图知,这只有3月2日、3月3日和3月7日;而由乙微信记步数排名第142,可知当天乙微信记步数在5000---10000之间,根据折线图知,这只有3月3日和3月6日.所以只有3月3日符合要求.【解析】分别根据微信记步数信息计算出甲乙步数都不低于10000的概率,再用分布原理处理.服从超几何分布,确定X的取值为0,1,2,代入超几何分布概率公式即可.由直方图知,微信记步数落在各区间的频率,再根据甲和乙的名次情况分析即可.本题考查了频率分布直方图,折线图等识图能力,考查了古典概率模型的概率计算,超几何分布等的计算,还考查了推理能力.属于中档题.20.【答案】解:若椭圆焦点在x轴上,且其离心率是,则,解得若,则过点且斜率为k的直线l的方程为:,椭圆的方程为:设,,联立,消去y整理得,解得,则,故,于是依题意知,,则点B到的距离为,故证明:设,,联立,得到,由,得到直线AE方程为:,令,解得,即,又,,为说明B,G,H三点共线,只用证,即证:,下用作差法说明它们相等:,而,,,,于是上式变为:,由韦达定理,,于是,故,命题得证.【解析】根据离心率的定义计算即可;联立直线和椭圆方程,根据弦长公式算出,用点到直线的距离公式算出三角形的高后即可;联立直线和椭圆方程,先表示出H坐标,将共线问题转化成证明,结合韦达定理进行化简计算.本题主要考查椭圆的性质,直线与椭圆的综合,考查运算求解能力,属于难题.21.【答案】解:因为,,所以,由题意知,在上恒成立,即在上恒成立,所以,即在上恒成立,令,易知,在上,函数和均单调递增,所以,即实数a 的取值范围是证明:令,故,所以函数是严格减函数,故至多只有一个实根;证明:设的最大值为M ,最小值为m ,在一个周期内,函数值必能取到最大值与最小值,设,,因为函数是周期为2,取一个周期,且,则有,若,则成立,若,设,即,故,且,则,所以成立,综上,对任意实数,都成立,所以原式得证.【解析】根据题意,将问题转化成恒成立问题,即在上恒成立,再利用函数的单调性即可求出结果;构造函数,由题易知在定义域上严格单调,从而得到证明;利用函数是定义域为R 的周期函数,知函数在一个周期上必有最大值和最小值,再利用条件,得到,再对与1的大小关系进行分类讨论,即可得出结论.本题主要考查利用导数研究函数的单调性与最值,考查不等式的证明,考查运算求解能力与逻辑推理能力,属于难题.。
2024年上海市崇明区中考道德与法治二模试卷一、综合理解题(12分)1.(12分)近期,光明中学组织开展了系列主题教育活动。
九(1)班同学围绕时事新闻内容开展探究性学习。
以下是他们收集的相关资料,请你参与其中,完成探究任务。
【完善法律】(1)2023年10月24日,第十四届全国人民代表大会常务委员会第六次会议表决通过《中华人民共和国爱国主义教育法》,该法律自2024年1月1日起施行。
全国人大公布此法律,说明全国人大具有 权,人民代表大会制度是我国的 政治制度。
(2)2024年3月19日,香港特区立法会全票通过《维护国家安全条例》。
这体现了香港特区政府 治国的决心和信心。
从此,特区政府可以全力聚焦发展经济、改善民生,共同创造更繁盛、更美好的家园。
【热词探究】新质生产力【热词聚焦】2024年1月31日,中共中央政治局就扎实推进高质量发展进行第十一次集体学习,习近平总书记对新质生产力作出系统阐述。
2024年3月5日,在今年的政府工作报告中,首次将“大力推进现代化产业体系建设,加快发展新质生产力”列为首项任务。
并做出具体部署——推动产业链供应链优化升级、积极培育新兴产业和未来产业、深入推进数字经济创新发展……,细节愈发充实,路径愈加清晰。
【探究释义】新质生产力是创新起主导作用,摆脱传统经济增长方式、生产力发展路径,具有高科技、高效能、高质量特征,符合新发展理念的先进生产力质态。
它由技术革命新突破、生产要素创新性配置、产业深度转型升级而催生。
以劳动者、劳动资料、劳动对象及其优化组合的跃升为基本内涵。
以全要素生产率大幅提升为核心标志,特点是创新,关键在质优,本质是先进生产力。
(3)同学们决定依据材料为“新质生产力”选定一个合适的关键词。
并运用所学内容阐述理由。
二、时政探究题(10分)2.(10分)光明中学九(2)班同学围绕“自然生态宜居环境”主题,开展探究性学习。
以下是他们收集的相关资料。
“十四五”期间,上海各区森林覆盖率比“十三五”都有不同程度提升。
1上海崇明区2023-2024学年第二学期学业质量调研高三数学考生注意:1.本试卷共4页,21道试题,满分150分,考试时间120分钟.2.本试卷分设试卷和答题纸.试卷包括试题与答题要求.作答必须涂(选择题)或写(非选择题)在答题纸上,在试卷上作答一律不得分.3.答卷前,务必用钢笔或圆珠笔在答题纸正面清楚地填写姓名、准考证号码等相关信息.一、填空题(本大题共有12题,满分54分,其中1~6题每题4分,7~12题每题5分)【考生应在答题纸相应编号的空格内直接填写结果.】1.若集合{2,0,1}A =-,{|1B x x =<-或0}x >,则A B = .2.不等式(1)0x x -<的解为.3.已知向量()()2,,1,2,1,4a b λ=-=-,若a b ⊥ ,则λ=.4.若复数z 满足i 1i z =+(i 为虚数单位),则z =.5.若等差数列{}n a 的首项11a =,前5项和525S =,则5a =.6.已知幂函数()y f x =的图像经过点(2,4),则(3)f =.7.若5()x a +的二项式展开式中2x 的系数为10,则a =.8.已知底面半径为1的圆柱,O 是其上底面圆心,A 、B 是下底面圆周上两个不同的点,BC 是母线.若直线OA 与BC 所成角的大小为3π,则BC =.9.已知函数3,0(),0x x x y f x x ⎧-⎪=⎨>⎪⎩≤为奇函数,则(2)f =.10.某学习小组共有10名学生,其中至少有2名学生在同一月份的出生的概率是.(默认每月天数相同,结果精确到0.001)11.已知A 、B 、C 是半径为1的圆上的三个不同的点,且AB = ,则 AB AC ⋅的最小值是.12.已知实数1212,,,x x y y 满足:2222112212121,1,1x y x y x y y x +=+=-=,则112222x y x y +-++-的最大值是.二、选择题(本大题共有4题,满分18分,其中13~14题每题4分,15~16题每题5分)【每题有且只有一个正确答案,考生应在答题纸的相应编号上,将代表答案的小方格涂黑,选对得满分,否则一律得零分.】13.若a b >,0c <,则下列不等式成立的是A .a b c>-B .a bc c>C .a c b c+<+D .22ac bc >2频率得分0.70.60.50.40.30.20.102分3分4分5分A 部门B 部门14.某单位有A 、B 两个部门,1月份进行服务满意度问卷调查,得到两部门服务满意度得分的频率分布条形图如图所示.设A 、B 两部门的服务满意度得分的第75百分位数分别为1n 、2n ,方差分别为21s 、22s ,则下列说法正确的是A .12n n >,2212s s >B .12n n >,2212s s <C .12n n <,2212s s <D .12n n <,2212s s >15.设函数()sin 6f x x π⎛⎫=- ⎪⎝⎭,若对于任意5,62ππα⎡⎤∈--⎢⎥⎣⎦,在区间[0,]m 上总存在唯一确定的β,使得()()0f f αβ+=,则m 的最小值为A .6πB .2πC .76πD .π16.已知函数()y f x =的定义域为12,,D x x D ∈.命题p :若当12()()0f x f x +=时,都有120x x +=,则函数()y f x =是D 上的奇函数.命题q :若当12()()f x f x <时,都有12x x <,则函数()y f x =是D 上的增函数.下列说法正确的是A .p 、q 都是真命题B .p 是真命题,q 是假命题C .p 是假命题,q 是真命题D .p 、q 都是假命题三、解答题(本大题共有5题,满分78分)【解答下列各题必须在答题纸相应编号的规定区域内写出必要的步骤.】17.(本题满分14分,本题共有2个小题,第(1)小题满分7分,第(2)小题满分7分)如图,在三棱锥P ABC -中,AB BC ==,4PA PB PC AC ====,O 为AC 的中点.(1)证明:PO ⊥平面ABC ;(2)若点M 在棱BC 上,且2MC MB =,求点C 到平面POM 的距离.318.(本题满分14分,本题共有2个小题,第(1)小题满分6分,第(2)小题满分8分)在锐角三角形ABC △中,角A ,B ,C 的对边分别为a ,b ,c .若CD 为CA 在CB方向上的投影向量,且满足2sin c B CD =.(1)求cos C 的值;(2)若b =3cos a c B =,求ABC △的周长.19.(本题满分14分,本题共有3个小题,第(1)小题满分4分,第(2)小题满分4分,第(3)小题满分6分)某疾病预防中心随机调查了340名50岁以上的公民,研究吸烟习惯与慢性气管炎患病的关系,调查数据如表所示.不吸烟者吸烟者总计不患慢性气管炎者120160280患慢性气管炎者154560总计135205340(1)是否有95%的把握认为患慢性气管炎与吸烟有关?(2)常用()()()P B A L B A P B A =表示在事件A 发生的条件下事件B 发生的优势,在统计中称为似然比.现从340人中任选一人,A 表示“选到的人是吸烟者”,B 表示“选到的人患慢性气管炎者”请利用样本数据,估计()L B A 的值;(3)现从不患慢性气管炎者的样本中,按分层抽样的方法选出7人,从这7人里再随机选取3人,求这3人中,不吸烟者的人数X 的数学期望.附:22()()()()()n ad bc a b c d a c b d χ-=++++,2( 3.841)0.05P χ≈≥.420.(本题满分18分,本题共有3个小题,第(1)小题满分4分,第(2)小题满分6分,第(3)小题满分8分)已知椭圆22:12x y Γ+=,A 为Γ的上顶点,P 、Q 是Γ上不同于点A 的两点.(1)求椭圆Γ的离心率;(2)若F 是椭圆Γ的右焦点,B 是椭圆下顶点,R 是直线AF 上一点.若△ABR 有一个内角为3π,求点R 的坐标;(3)作AH PQ ⊥,垂足为H .若直线AP 与直线AQ 的斜率之和为2,是否存在x 轴上的点M ,使得MH为定值?若存在,请求出点M 的坐标,若不存在,请说明理由.21.(本题满分18分,本题共有3个小题,第(1)小题满分4分,第(2)小题满分6分,第(3)小题满分8分)已知()ln 1f x a x ax =---.(1)若1a =-,求曲线()y f x =在点(1,2)P 处的切线方程;(2)若函数()y f x =存在两个不同的极值点12,x x ,求证:12()()0f x f x +>;(3)若1a =,()()g x f x x =+,数列{}n a 满足1(0,1)a ∈,1()n n a g a +=.求证:当2n ≥时,212n n n a a a +++>.5参考答案及评分标准一、填空题1.{2,1}-;2.(0,1);3.8-;4.1-i ;5.9;6.9;7.1;8.3;9.199-;10.0.996;11.32;12.6.二、选择题13.D ;14.C ;15.B ;16.C.三、解答题17.解(1)因为AP =CP =AC =4,O 为AC 的中点,所以OP ⊥AC ,且OP=连结OB .因为AB =BC =22AC ,222AB BC AC +=,所以△ABC 为等腰直角三角形,故OB ⊥AC ,OB =12AC =2.因为222OP OB PB +=,所以OP OB ⊥.......................4分因为OP OB OP AC ⊥⊥,,OB AC O = ,所以PO ⊥平面ABC .........................................................7分(2)方法一:作CH ⊥OM ,垂足为H .因为OP ⊥平面ABC ,所以OP ⊥CH ,所以CH ⊥平面POM .故CH 的长为点C 到平面POM 的距离...................4分由题意,OC=12AC =2,CM=3,∠ACB=45°.所以OM =253,CH =sin OC MC ACB OM ⋅⋅∠=5.所以点C 到平面POM 的距离为455........................................7分方法二:设C 到平面POM 的距离为h ,由(1)知PO 即为P 到平面COM 的距离,且PO OM ⊥........................................1分又PO =,在OMC △中,2422,4533OC CM BC ACB ︒===∠=,则由余弦定理得253OM =,.......................................1分因为C POM P COM V V --=,即1133POM COM S h S PO ⋅=⋅△△,6故221232COM POM S PO h S ⨯⨯⋅==△△即点C 到平面POM的距离为5...................................7分18.解(1)由题意,得cos CD b C =,又2sin c B =,所以2sin cos c B C =,由正弦定理sin sin b c B C=,得2sin sin cos C B B C =,又sin 0B ≠,所以2sin C C =,..................................4分因为C为锐角,所以2cos 3C ==...................................6分(2)由3cos a c B =,得cos 3a B c=,由余弦定理得222cos 2a c b B ac +-=,所以22223a c b aac c +-=,得22233a c b +=①..............3分由由余弦定理得2222cos 23a b c C ab +-==,得222333a b c +-=②............................5分联立①②,解得a c ==,故ABC △的周长为a b c ++=................8分19.解(1)假设0H :患慢性气管炎与吸烟无关.22340(1204516015) 6.58128060135205χ⨯⨯-⨯=≈⨯⨯⨯由2( 3.841)0.05P χ≈≥,而6.581 3.481>,从而否定原假设,即有95%的把握认为患慢性气管炎与吸烟有关.....................................................4分(2)()()()||9()()32()()()||()P A B P B A P A B A B P A L B A P B A P A B P A B A B P A =====............................4分(3)按分层抽样,不吸烟者3人,吸烟者4人,....................................................1分X 的可能值为0,1,2,3,其分布是012341812135353535⎛⎫ ⎪ ⎪ ⎪⎝⎭....................................................5分所以4181219[]0123353535357E X =⨯+⨯+⨯+⨯=....................................................6分720.解(1)由题意,1a c ==,所以离心率22c e a ==.....................4分(2)由题意,(1,0)F ,(0,1)A ,所以直线AF 的方程为:1y x =-+,设00(,1)R x x -+显然4BAR π∠=...................................................................................2分①当3ABR π∠=时,00(0,2),(,2)BA BR x x ==-+ ,由1cos 2||||BA BR ABR BA BR ⋅∠==,得:200660x x -+=,解得03x =03x =分②当3ARB π∠=时,0000(,),(,2)RA x x RB x x =-=-- ,由1cos 2||||BA BR ABR BA BR ⋅∠==,得:2003620x x -+=,解得013x =-(舍去)或013x =+综上所述,点R的坐标是(32--+或(1+.....................6分(3)假设存在定点(,0)M m 满足题意,当PQ 的斜率存在时,设直线PQ 的方程为y kx b =+,1122(,),(,)P x y Q x y ,由2221x y y kx b ⎧+=⎪⎨⎪=+⎩得22212)4220k x kbx b +++-=(,由题意,2222164(12)(22)0k b k b ∆=-+->,即22210k b -+>①.2121222422,1212kb b x x x x k k -+=-=++,122121211212121211()()(1)()2AP AQ y y x kx b x x kx b x b x x k k k x x x x x x --+-++--++=+==+2(1)22222(1)1b kb k k b b -⋅=-==-+,所以1k b =+,代入①,得:2430b b ++>,所以3b <-或1b >-,即存在直线PQ 使得直线AP与直线AQ 的斜率之和为2.....................................................................3分直线PQ 的方程为1y kx k =+-,直线AH 的方程为11y x k=-+由111y kx k y x k =+-⎧⎪⎨=-+⎪⎩,得:22221211k k x k k y k ⎧-=⎪⎪+⎨-⎪=+⎪+⎩,即22222(,1)11k k k H k k --+++.................5分所以2222222222(2)(21)()(1)1111k k k k m k MH m m k k k ---+=-++=+++++8所以当12m =-时,MH...........................................................7分当直线PQ 斜率不存在时,设00(,)P x y ,00(,)Q x y -,则0000112AP AQ y y k k x x ---+=+=,01x =-,此时(1,1)H -,2MH =满足题意.所以存在定点1(0)2,P -,使得MH为定值且定值为2..................8分21.解(1)当1a =-时,1'()1,'(1)3f x f x=+=所以曲线()y f x =在点(1,2)P 处的切线方程为31y x =-.................4分(2)由'()0f x =0aa x--=,令t =0t >原方程可化为:20at t a -+=①,则12t t ==①的两个不同的根所以214010a a⎧∆=->⎪⎨>⎪⎩,解得102a <<.................3分所以121212()()(ln ln )()2f x f x a x x a x x +=-+-+-222212121212()ln()()222t t a t t a t t a a=+--+-=+-因为102a <<,所以12220a a+->>,所以12()()0f x f x +>.......................6分(3)由题意,()ln 1g x x =-,所以1'()x g x x-=当(0,1)x ∈时,'()0g x <,所以函数()y g x =在区间(0,1)上严格减,当(1,)x ∈+∞时,'()0g x >,所以函数()y g x =在区间(1,)+∞上严格增,.................3分因为101a <<,所以21()(1)1a g a g =>=,32()(1)1a g a g =>=,以此类推,当2n ≥时,1()(1)1n n a g a g +=>=,.................4分又213110'(242)21f x x x⎫---⎪⎝⎭⨯--==<,所以函数()y f x =在区间(0,)+∞上严格减,当2n ≥时,()()(1)0n n n f a g a a f =-<=,所以1n n a a +<,.................7分所以1()()n n f a f a +>,即211n n n n a a a a +++->-,故212n n n a a a +++>...................................8分。
崇明县2010学年第二次高考模拟试题英语(考试时间120分钟,满分150分。
请将答案填写在答题纸上)第Ⅰ卷(共105分)I. Listening ComprehensionSection ADirections:In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. Yesterday. B. Three days ago. C. Two days ago. D. Early last week.2. A. At home B. In a restaurant. C. In a car. D. On the street.3. A. A railway porter. B. A bus conductor. C. A taxi driver. D. A postal clerk.4. A. Something went wrong with the bus. B. Something prevented her from catching the bus.C. She took somebody to hospital.D. She came on foot instead of taking a bus.5. A. She was afraid of going out at night. B. She wanted to get ready for a plane trip.C. She had to do some baking.D. She was moving to a new department.6. A. She partially agrees with the man. B. She completely agrees with the man.C. She doesn’t agree with the man.D. She thinks life is worse for young people.7. A. The train is on time. B. The train is empty.C. The train is late.D. The train is crowded.8. A. The woman is seeing a doctor. B. The woman is a close friend of the man’s.C. The woman is tired of her work.D. The woman has been working too hard.9. A. The air was polluted yesterday. B. The man should listen to the weather report.C. She might not go camping tomorrow.D. She wants to book a hotel for tomorrow.10. A. She wants to say hello to the parents. B. She wants to know if everything is OK with her parents.C. She wants to hear her father’s voice.D. She wants to tell her parents she is fine.Section BDirections: In Section B, you will hear two short passages, and you will be asked three questions on each of the passages. The passages will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard. Questions 11 through 13 are based on the following passage.11. A. Old People Talking. B. The Tommy Brain Shoe.C. My Favorite Musician.D. American Country Music Show.12. A. Scotland. B. The Middle East. C. North America. D. The West Asia.13. A. Life Channel. B. A Music Channel. C. A Science Channel. D. The News Channel. Questions 14 through 16 are based on the following passage.14. A. In the region of North Pole. B. In the Pacific Ocean.C. In green forests.D. In dry deserts.15. A. Snakes are used to extra-hot weather. B. Snakes like to stay in the sun.C. Snakes are good swimmers.D. Snakes need warmth.16. A. They are fairly intelligent. B. They are not very intelligent.C. They are intelligent.D. They are very intelligent.Section CDirections: In Section C, you will hear two longer conversations. The conversations will be read twice. After you hear each conversation, you are required to fill in the numbered blanks with the information you have heard. Write your answers on your answer sheet.Complete the form. Write ONE WORD for each answer.Complete the form. Write NO MORE THAN THREE WORDS for each answer.II. Grammar and VocabularySection ADirections: Beneath each of the following sentences there are four choices marked A, B. C and D. Choose the one answer that best completes the sentence.25. Many exceptions _____ the rules of English usage make English difficult to master.A. ofB. offC. toD. on26. —Have you ever seen a tiger in the wild?—Yes. I saw ________ when I visited the national park in southern Nepal.A. itB. oneC. thatD. any27. It is the third time that the president _____ to China for a visit.A. comeB. comesC. will comeD. has come28. To master a foreign language like English requires hard work, so you _____ study too hard.A. ought toB. shouldn’tC. can’tD. mustn’t29. In some countries, _____ is called ―equality‖ does n ot really mean equal rights for all people.A. whichB. whatC. thatD. one30. In making a speech, the number of listeners is also an important factor ______.A. to be consideredB. being considered C.considered D. considering31. The more exercise you take in your spare time, __________ it will do to you.A. the betterB. the bestC. the more wellD. the more good32. What disappointed Mr. Smith most was ______ to go to Canada with his parents tovisit his grandpa.A. having not been allowedB. his not allowingC. his not having been allowedD. his being not allowed33. ______ you will carry out my instructions or I will offer the job to someone else.A. EitherB. UnlessC. UntilD. Whether34. _____ the earth to be flat, many feared that Columbus would fall off the edge of the world.A. Having believedB. BelievingC. BelievedD. To believe35. They didn’t discover until they happened to enter the back room ________ someonehad stolen the priceless painting.A. thatB. whatC. whichD. when36. I’ve tried very hard to improve my English, but by no means _____ with my progress.A. the teacher is not satisfiedB. is the teacher not satisfiedC. the teacher is satisfiedD. is the teacher satisfied37. The story brought the hours back to me _____ I was taken good care of in that farawayvillage.A. thatB. untilC. whereD. when38. The sale usually takes place in front of the house, with the audience _____ on benches,chairs or boxes.A. having seatedB. seatingC. seatedD. having been seated39. Rather than _____ the vegetables to go bad, he sold them at half price.A. allowB. to allowC. allowingD. allowed40. ________ has recently been done to provide more buses, a shortage of public vehiclesremains a serious problem.A. ThatB. WhatC. In spite of whatD. Though whatSection BDirections: Complete the following passage by using the words in the box. Each word canWhen you watch TV programmes about wild animals. It is amazing to see how an African animal can __41__ a lion’s attack. In the wilderness, ever y one has a stunt (绝技). Even plants have their own ways of fighting off enemies.Over millions of years of __42__, plants have developed a unique defence system. Chemicals are widely used for __43__. By making their leaves, flowers, stems, roots and fruits __44__ or poisonous to animals, plants can fight back.One such plant is the Golden Wattle tree. British __45__ David Cameron has found when an animal eats the tree’s leaves, the amount of poisonous tannin(单宁) increases in theother leaves. ―It’s like the damaged leaves __46__ the others telling them to fight together against the enemy,‖ he said.The tree also sends defence messages to neighboring plants by giving out a special smell. Golden Wattle tree in the __47__ 45 meters will get the message and produce more tannin wit hin 10 minutes. Now, if an animal eats too many of the trees’ leaves, it will die.Every species of plant or tree specializes in the production of a particular set of__48__. A plant-eating animal that can safely eat the leaves of one tree may be poisoned by its neighbor.In this way, plants have developed not only __49__ defence systems, but also shared them with others. This makes it impossible for a single animal to destroy even a small area of forest.III. Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context. Hunting wild birds is illegal in Shanghai – and especially in Chongming County. So is selling birds as pets and __50__ them in restaurants as delicacies.But enforcement (执法) is difficult, and in many cases nonexistent, due to lack of __51__ and staff. A lot of __52__ work is left to volunteers. According to an official of the Shanghai Wild Animal Protection Association, who __53__ to be named, some small restaurants are __54__serving bird dishes, but the __55__ is impossible to stop at this time. ―We have to __56__ cooperation with the city’s __57__ and industry department, the food and drug __58__, the police and many other sectors (部门) of the government,‖ he said.―__59__, there is no law enforcement power to __60__ their business licenses.‖The association lacks enough people to __61__ into the Chongming woods, as the volunteers do, to __62__ nets, which are used to capture birds. The Chongming Woods Protection Team has only six members and five of them have to take care of the __63__ –only one is dedicated to bird protection, according to Jiang Long, our team leader and a member of the non-governmental Shanghai Green Oasis Ecological Conservation and Communication Center. ―What they can do is limited,so volunteers are needed to fill the __64__,‖ Jiang said.50. A. killing B. buying C. serving D. burning51. A. resources B. sources C. guns D. tools52. A. routine B. protection C. difficult D. easy53. A. allowed B. approved C. agreed D. declined54. A. carefully B. illegally C. loyally D. privately55. A. behavior B. law C. practice D. case56. A. seek B. give C. find D. connect57. A. education B. fishing C. animal D. commerce58. A. business B. association C. administration D. institute59. A. Meanwhile B. Therefore C. Otherwise D. Besides60. A. provide B. suspend C. supply D. refuse61 A. intrude B. venture C. flood D. invade62. A. break into B. look for C. turn over D. cut down63. A. birds B. animals C. woods D. beach64 A. gap B. hole C. occupation D. placeSection BDirections:Read the following four passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)She tells us she understands teens. She’s with them at home and she’s with them at school.She plays the piano and the flute (笛子). ―Growing up I was always involved with music. My parents had divorced and I was under a lot of stress, and being around music, I felt peace and happiness. Later I came to realize that, as a music teacher, I could give that gift to kids.‖And she’s an author. She wrote The Unexpected Adventure at East Haddam two years ago when Evens had a brother and a sister in her Chorus class who struggled with her relationship. Each one – mostly the sister –complained about the other to her. ―And I hope the book wi ll show them the importance of their education. It’s so hard for teens to understand the value of what they study in school.‖She’s keenly aware of the challenges today’s youth face. ―As a society, we’ve lowered our standards in many cases. As a kid I watched Happy Day and The Bill Cosby Show, and my parents never had to worry about what would come out of the characters’ mouths. Today there is no show on after 8 p.m. that’s suitable for younger people. It’s hard for kids today because they’re not allowed the innocence we had.‖She’s busy at work on her next book. Evens says writing these books has filled a place inside her that she never thought about, but that needed to be filled. ―I enjoy the process so much. I feel challenged. And I am able to purge(净化) some thoughts that I would like to share, especially with kids.‖“The most important thing for kids today to remember is that every person is valuable and important, and they have to respect their bodies and themselves, and behave in a way that shows t hat.‖65. Evens was fond of music as a child because _____.A. she could find comfort with music at homeB. her gift for music was passed down from her parentsC. her parents gave her a lot of pressure to learn musicD. music could bring peace between fighting parents66. We can infer from Paragraph 4 that _____.A. today the family seldom watches shows togetherB. the standard to choose characters in shows is raisedC. the show after 8 p.m. have a bad influence on teensD. today’s youth are as innocent as those in the past67. What statement may Evens agree to?A. School subjects are too hard for teens to understand.B. It is a challenge to teach children music and writing.C. Teens respect others by behaving themselves well.D. Education is of great value to teens today.68. What might be the most suitable title for the passage?A. A multi-talented teacher understands teens.B. A teacher writes books on teens.C. Teens love multi-talented teachers at school.D. Kids today are no more innocent than ever.(B)Advertisement 1Now available at Franklin Park one block from Indiana University. New unfurnished flat bedroom at $135, two bedrooms at $165, three bedrooms at $195 per month. Utilities (实用设施) include gas, electricity and water. Children and small pets are welcome. One month’s deposit required. Office opens through Saturday nine to five. Welcome for an evening or Sunday appointment.Advertisement 2SHEFFIELDLINCOLN COLLEGE OF ENGLISHClasses for foreign students at all levels3 months, 6 months, 9 months and one year courseOpen all yearSmall class (maximum 12 students)Library, language laboratory and listening centerAccommodation with selected families25 minutes from LondonCourse fees for English for one year are £1, 380with reduction for shorter periods of study.69. From Advertisement 1, we can suppose _____.A. cats and dogs are not permitted in the flatsB. the flats have furniture in themC. the flats are far from Indiana UniversityD. gas and water bills are included in the rent70. Advertisement 1 suggests that persons who are interested in the flats must _____.A. see the flats on Monday or SaturdayB. call for an appointment if they want to see the flats from nine to five Monday throughSaturdayC. see the flats before five o’clock during weekdaysD. call for an appointment if they want to see the flats on Sunday or in the evening71. While you stay in Lincoln College of English, _______ will take care of you.A. the school where you studyB. the family you have chosenC. your classmatesD. your own parents(C)I hear many parents complaining that their teenage children are rebelling. I wish it were so. At your age you ought to be growing away from your parents. You should be learning to stand on your own two feet. But take a good look at the present rebellion. It seems that teenagers are all taking the same way of showing that they disagree with their parents. Instead of striking out boldly(大胆地) on their own, most of them are attempting to seize one another’s hands for reassurance.They claim they want to dress as they please. But they all wear the same clothes. They set off in new directions in music. But somehow they all end up crowded round listening to the same record. Their reason for thinking or acting in thus-and-such a way is that the crowd is doing it. They have come out of their cocoon (蚕茧)— into a larger cocoon.It has become harder and harder for a teenager to stand up against the popularity wave and to go his or her own way. Industry has firmly carved out(创造出) a teenage market. These days every teenager can learn from the advertisements what a teenager should have and be. And many of today’s parents have come to award high marks for the popularity of their children. All this adds up to a great barrier for the teenager who wants to find his or her own path.But the barrier is worth climbing over. The path is worth following. You may want to collect rocks when everyone else is collecting records. You may have some thoughts that you don’t care to share at once with your classmates. Well, go to it. Find yourself. Be yourself. Popularity will come —with the people who respect you for who you are. That’s the only kind of popularity that really counts.72. This passage is meant to ______.A. tell readers how to be popular among people around themB. suggest people how to understand and respect each otherC. encourage teenagers to learn to make their choices and decisionsD. suggest parents how to guide and teach their teenage children73. According to the author, many children are said to be rebelling, but actually most of them ____.A. are very much afraid of being kept aloneB. are not courageous and confident enoughC. are not very popular among their classmatesD. are good at striking out boldly on their own74. The expression ―to award high marks for the popularity of their children‖ can beunderstood as ―______‖.A. to generously reward their children when they do better than othersB. to expect their children to become top students at the teenage marketC. to give prizes to their children when they do well in their testsD. to pay much attention to whether their children are popular75. It can be inferred from the passage that ______.A. advertisements are trying to help teenagers to find themselvesB. most teenagers are actually not rebelling at all in a real senseC. advertisements are always misleading in carving out a teenage marketD. most teenagers manage to become popular by dressing as they pleaseDirections: Read the following text and choose the most suitable heading from A-F forSurfing is one of the fastest developing sports in the world today. It use, d to be practicedSurfing is more of a way of life for some people than simply a sport, and many spend their time travelling around the planet in search of the perfect wave. Typically, the average surfer is a relaxed type of person: they say it’s something about the art of catching waves and being out in the elements that makes you feel very relaxed. Surfers greet each other by saying ―Howzit?‖ (a bit like ―How’s it going?‖) and sometimes call each other ―bru‖ or―brah‖ from the Hawaiian word for brother, ―braddah‖. British surfers travel in WV camperAnywhere that has a coastline with big waves is home to surfers. Half of Australia’s coastline is surfable so there are lots of Australian surfers. Hawaii is where the sport was invented and the current champion is Hawaiian Sunny Garcia. A lot of surfers also come from California and New Zealand. There are even surfers in the UK who hang out on theGet a board. Most surfers start on short boards. Long boards and guns are only for experienced surfers catching huge waves. You also have to be a very strong swimmer:Beach breaks are waves which fall onto sand. They can be big, but are best if you are a beginner. Waves vary in size during different seasons and even at different times of the day, so watch out! Surfing can be dangerous and you need advice from someone experienced. More experienced surfers catch waves at point and reef breaks. They are away from the coast, and the swell comes deep from the ocean. Point breaks are waves bent because of theSurfing is a dangerous sport if you aren’t a strong swimmer or if you try to do too much. The main thing most surfers have to worry about is their own board or other surfers’ boards. Great white sharks, stingrays and deadly jellyfish are also not friendly to surfers, but actually running into one of these is quite rare.Directions: Read the passage carefully. Then answer the questions or complete the statements in the no more than 10 words.Reading to oneself is a modern activity that was almost unknown to the scholars of the classical and medieval(中世纪的)worlds, while during the fifteenth century the term―reading‖ undoubtedly meant reading aloud. Only during nineteenth century did silent reading become common-place.One should be careful, however, of assuming that silent reading came about simply because reading aloud is a distraction to others. Examination of factors related to the historical development of silent reading reveals that it became the usual mode of reading for most adult reading tasks mainly because the tasks themselves changed in character.The last century saw a steady gradual increase in literacy, and thus in the number of readers. As readers increased, so the number of potential listeners declined, and thus there was some reduction in the need to read aloud. As reading for the benefit of listeners grew less common, so came the flourishing(繁荣)of reading as a private activity in such public places as libraries, railway carriages and offices, where reading aloud would cause distraction to other readers.Towards the end of the century there was still considerable argument over whether books should be used for information or treated respectfully, and over whether the reading of material such as newspapers was in some way mentally weakening. Indeed this argument remains with us still in education. However, whatever its virtues, the old shared literacy culture had gone and was replaced by the printed mass media on the one hand and by books and periodicals(期刊)for a specialized readership on the other.By the end of the century students were being recommended to adopt attitudes to books and to use skills in reading them which were inappropriate, if not impossible, for the oral reader. The social, cultural, and technological changes in the century had greatly altered what the term ―reading‖ implied.81. Why was reading aloud common before the nineteenth century?82. The development of silent reading during the nineteenth century indicates that______________.83. People are still arguing about the value of __________________.84. What’s the writer’s purpose in writing this passage?第II卷(共45分)Directions: Translate the following sentences into English, using the words given in the brackets.1. 我们花在作业上的时间很多。
2023学年第二学期学业质量调研高三语文(考试时间150分钟,满分150分。
请将答案填写在答题纸上)一、积累应用10分1.按要求填空。
(5分)(1)明明如月,。
(曹操《短歌行》)(2),内无应门五尺之僮。
(《陈情表》)(3)杜牧《阿房宫赋》一文中以夸张手法描述阿房宫内情形,衬托阿房宫之宏大的诗句有“,”等句。
2.按要求选择。
(5分)(1)将下列编号的语句依次填入语段空白处,语意连贯的一项是()(2分)社会科学要给普通人提供观察世界、为人处世的办法,不是通过简单的道德教化,而是通过分析。
,。
,,。
可能会有大的图景,但没有所谓的规律。
①社会科学告诉你,其实没有什么很强的规律②问题就解决了③都在于自己怎么样去理解这个世界,怎么样主动地采取行动④它不像自然科学,发现自然规律⑤它可能是倒过来A.④⑤①②③B.①④⑤②③C.④②⑤①③D.①②④⑤③(2)小明同学拟就“崇明区清明节文化”展开专题调查,以下是他制订的调查方案,请找出画线部分不适合...的一处,并说明理由。
(3分)崇明区清明节文化调查方案【】处,理由:。
二、阅读70分(一)阅读下列材料,完成第3-7题。
(16分)材料一:①据说学术界有人对“新闻自由”的概念提出质疑,认为我们只能用“出版自由”的提法,不该说“新闻自由”。
在他看来,新闻是个名词,并不表示动作,新闻指的是新近发生的事实,而事实是客观存在的,有什么自由不自由的问题呢?②听到这种“新论”,笔者很有些愕然。
③对于已经约定俗成、广泛使用的概念,并不是不可以重新讨论。
但是像上面提到的那种说法、那种推理....逻辑..,却很让人困惑。
因为循着这一逻辑推论,我们岂不可以对一系列含有“新闻”二字的复合概念提出同样的反问:既然事实是客观存在的,那么有什么讲不讲道德的问题,何来“新闻道德”“新闻伦理”之说?既然事实是客观存在的,它也不会有“律”与“不律”的问题,何来“新闻自律”“新闻他律”的说法?看来问题首先在于整个推理的大前提能否成立,即“新闻”究竟是不是“事实”上。
2011年崇明县初三模拟考试试卷(化学部分)(满分60分)本卷可能用到的相对原子质量:H-1 C-12 O-16 K-39 Mg-24 Al-27 Ca-40 Cl-35.5考生注意:请将答案填写在答题卷上对应的位置 六、单项选择题(共20分)27.下列变化,属于化学变化的是………………………………………………………… ( ) A .冰棒融化 B .木材燃烧 C .香水四溢 D .灯泡发光 28.地壳里含量最多的金属元素是…………………………………………………………( ) A .氧 B .硅 C .铝 D .铁29.下列物质,属于纯净物的是…………………………………………………………( )A .可口可乐B .无尘空气C .氢氧化钙D .含碘食盐 30.下列物质的用途中,主要是利用其化学性质的是……………………………………( )A .用铜丝作导线B .用活性炭作吸附剂C .用镁粉作照明弹D .用金刚石作钻头31.下列物质由原子直接构成的是…………………………………………………………( )A .空气B .水 C.汞 D.氧气32.草木灰是一种常用的农家肥料,其主要成分是………………………………………( )A .KClB .Na 2CO 3C .K 2CO 3D .KCl33.在反应Fe 2O 3+2Al −−→−高温Al 2O 3+2Fe 中,氧化剂是………………………………( )A .Fe 2O 3B .Al C.Al 2O 3 D.Fe34.氮元素的化合价为+5价的物质是…………………………………………………( ) A .N 2 B .N 2O 5 C .N 2O 3 D .NH 3 35.下列实验现象的描述不正确的是……………………………………………………( )A .红磷在空气中燃烧产生大量白雾B .镁条放入盐酸中有大量气泡C .硫在氧气中燃烧产生蓝紫色火焰D .盐酸使紫色石蕊试液变红36.下列物质的水溶液,PH >7的是………………………………………………… ( ) A .Na 2CO 3 B .CuSO 4 C .H 2SO 4 D .NaCl37.按酸、碱、盐、氧化物的分类,下列各组物质属于同一类别的是………………( ) A .烧碱和纯碱 B .氢氧化钠和硝酸钾 C .氯化镁和碳酸钙 D .生石灰和熟石灰38.下列化学方程式中,书写正确的是……………………………………………… ( ) A .2Fe+6HCl 2FeCl 3+3H 2↑ B .Fe + 2O 2 Fe 3O 4C .2H 2O H 2↑+O 2↑D .Na 2CO 3+Ca(OH)2 CaCO 3↓+2NaOH 39.下图装置可以用来测定空气中氧气的体积分数。
2023年上海市崇明区中考化学二模试卷1. 属于金属元素的是( )A. 碳B. 氢C. 氦D. 镁2. 属于化学变化的是( )A. 蜡烛燃烧B. 蔗糖溶解C. 铁丝弯曲D. 湿衣晾干3. 钾肥能增强作物对病虫害和倒伏的抵抗能力。
下列属于钾肥的是( )A. B. C. D.4. 中铁元素的化合价是( )A. B. C. D.5. 互为同素异形体的是( )A. 冰和干冰B. 氢气和液氢C. 红磷和白磷D. 水银和银6. 氧元素以游离态存在的是( )A. 氧气B. 水C. 氢氧化钙D. 二氧化碳7. 喷洒“84”消毒液,能闻到特殊气味,是因为( )A. 分子在不断运动B. 分子质量很小C. 分子间有闻隔D. 分子可以再分8. 有关金刚石和石墨的说法错误的是( )A. 金刚石具有可燃性B. 金刚石硬度很小C. 石墨具有导电性D. 石墨常温下化学性质稳定9. 对实验现象描述错误的是( )A. 打开浓盐酸的瓶塞,瓶口上方出现白雾B. 硫在空气中燃烧,火焰呈明亮的蓝紫色C. 硫酸铜溶液中滴加氢氧化钠溶液,产生蓝色沉淀D. 将明矾加入浑浊的河水中,静置,河水变澄清10. 有关氢氧化钠固体的叙述,错误的是( )A. 俗称烧碱B. 常用于改良酸性土壤C. 应放在烧杯中称量D. 氢氧化钠易溶于水,并放出大量热11. 氧化汞固体加热反应的微观示意图如图。
有关说法错误的是( )A. 氧原子是保持氧气化学性质的最小微粒B. 每216g氧化汞加热生成200g汞和16g氧气C. 反应前后原子的种类和数目没有改变D. 原子、分子均可以构成物质12. 如图是一氧化碳和氧化铜后应制取铜的实验有关说法错误的是( )A. 实验中一氧化碳体现了还原性B. 实验中观察到玻璃管内固体由黑色变为红色C. 酒精灯Ⅱ的作用是处理尾气,防止有毒气体排放D. 实验开始时应先点燃酒精灯Ⅰ,再点燃酒精灯Ⅱ13. 某化合物含两种元素,该化合物说法正确的是( )A. 一定是氧化物B. 可能是混合物C. 可能是盐D. 可能是碱14. 向一定量的氢氧化钠溶液中逐滴加入稀硫酸至过量。
上海市崇明县中考数学二模试卷一、选择题(本大题共6题,每题4分,满分24分)1.(4分)8的相反数是()A.B.8C.D.﹣82.(4分)下列计算正确的是()A.B.a+2a=3a C.(2a)3=2a3D.a6÷a3=a23.(4分)今年3月12日,某学校开展植树活动,某植树小组20名同学的年龄情况如下表:年龄(岁)1213141516人数14375那么这20名同龄的众数和中位数分别是()A.15,14 B.15,15 C.16,14 D.16,154.(4分)某美术社团为练习素描,他们第一次用120元买了若干本相同的画册,第二次用240元在同一家商店买与上一次相同的画册,这次商家每本优惠4元,结果比上次多买了20本.求第一次买了多少本画册?设第一次买了x本画册,列方程正确的是()A.B.C.D.5.(4分)下列图形中,既是轴对称图形又是中心对称图形的是()A.等边三角形B.平行四边形C.菱形D.正五边形6.(4分)已知△ABC中,D、E分别是AB、AC边上的点,DE∥BC,点F是BC 边上一点,联结AF交DE于点G,那么下列结论中一定正确的是()A.B.C.D.二、填空题(本大题共12题,每题4分,满分48分)7.(4分)因式分解:x2﹣9=.8.(4分)不等式组的解集是.9.(4分)函数y=的定义域是.10.(4分)方程的根是x=.11.(4分)已知袋子中的球除颜色外均相同,其中红球有3个,如果从中随机摸得1个红球的概率为,那么袋子中共有个球.12.(4分)如果关于x的方程x2+4x﹣k=0有两个相等的实数根,那么实数k的值是.13.(4分)如果将抛物线y=x2+2x﹣1 向上平移,使它经过点A(1,3),那么所得新抛物线的表达式是.14.(4分)某校组织了主题为“共建生态岛”的电子小报作品征集活动,先从中随机抽取了部分作品,按A,B,C,D 四个等级进行评分,然后根据统计结果绘制了如图两幅不完整的统计图,那么此次抽取的作品中等级为B的作品数为.15.(4分)已知梯形ABCD,AD∥BC,BC=2AD,如果,,那么=(用表示).16.(4分)如图,正六边形ABCDEF 的顶点B、C 分别在正方形AGHI 的边AG、GH 上,如果AB=4,那么CH的长为.17.(4分)在矩形ABCD中,AB=5,BC=12,点E是边AB上一点(不与A、B重合),以点A为圆心,AE为半径作⊙A,如果⊙C与⊙A外切,那么⊙C的半径r 的取值范围是.18.(4分)如图,△ABC 中,∠BAC=90°,AB=6,AC=8,点D是BC的中点,将△ABD,将△ABD沿AD翻折得到△AED,联结CE,那么线段CE的长等于.三、解答题(本大题共7题,满分78分)19.(10分)计算: +(﹣2)2+9﹣(π﹣3.14)020.(10分)解方程组:21.(10分)已知圆O的直径AB=12,点C是圆上一点,且∠ABC=30°,点P是弦BC上一动点,过点P作PD⊥OP交圆O于点D.(1)如图1,当PD∥AB 时,求PD的长;(2)如图2,当BP平分∠OPD时,求PC的长.22.(10分)温度通常有两种表示方法:华氏度(单位:°F)与摄氏度(单位:℃),已知华氏度数y 与摄氏度数x 之间是一次函数关系,下表列出了部分华氏度与摄氏度之间的对应关系:摄氏度数x (℃)…0…35…100…华氏度数y (℉)…32…95…212…(1)选用表格中给出的数据,求y关于x的函数解析式;(2)有一种温度计上有两个刻度,即测量某一温度时左边是摄氏度,右边是华氏度,那么在多少摄氏度时,温度计上右边华氏度的刻度正好比左边摄氏度的刻度大56?23.(12分)如图,AM 是△ABC的中线,点D是线段AM上一点(不与点A 重合).DE∥AB交BC 于点K,CE∥AM,联结AE.(1)求证:;(2)求证:BD=AE.24.(12分)已知抛物线经过点A(0,3)、B(4,1)、C(3,0).(1)求抛物线的解析式;(2)联结AC、BC、AB,求∠BAC的正切值;(3)点P是该抛物线上一点,且在第一象限内,过点P作PG⊥AP交y轴于点G,当点G在点A 的上方,且△APG与△ABC相似时,求点P的坐标.25.(14分)如图,已知△ABC 中,AB=8,BC=10,AC=12,D是AC边上一点,且AB2=AD•AC,联结BD,点E、F分别是BC、AC上两点(点E不与B、C重合),∠AEF=∠C,AE与BD相交于点G.(1)求证:BD平分∠ABC;(2)设BE=x,CF=y,求y与x 之间的函数关系式;(3)联结FG,当△GEF 是等腰三角形时,求BE的长度.上海市崇明县中考数学二模试卷参考答案与试题解析一、选择题(本大题共6题,每题4分,满分24分)1.(4分)8的相反数是()A.B.8 C.D.﹣8【解答】解:8的相反数是﹣8,故选:D.2.(4分)下列计算正确的是()A.B.a+2a=3a C.(2a)3=2a3D.a6÷a3=a2【解答】解:A、+,无法计算,故此选项错误;B、a+2a=3a,正确;C、(2a)3=8a3,故此选项错误;D、a6÷a3=a3,故此选项错误;故选:B.3.(4分)今年3月12日,某学校开展植树活动,某植树小组20名同学的年龄情况如下表:年龄(岁)1213141516人数14375那么这20名同龄的众数和中位数分别是()A.15,14 B.15,15 C.16,14 D.16,15【解答】解:由于15岁出现次数最多,所以众数为15岁,中位数为第10、11个数据的平均数,所以中位数为=15(岁),4.(4分)某美术社团为练习素描,他们第一次用120元买了若干本相同的画册,第二次用240元在同一家商店买与上一次相同的画册,这次商家每本优惠4元,结果比上次多买了20本.求第一次买了多少本画册?设第一次买了x本画册,列方程正确的是()A.B.C.D.【解答】解:设第一次买了x本画册,根据题意可得:,故选:A.5.(4分)下列图形中,既是轴对称图形又是中心对称图形的是()A.等边三角形B.平行四边形C.菱形D.正五边形【解答】解:A、等边三角形不是中心对称图形,是轴对称图形,故本选项错误;B、平行四边形是中心对称图形,不是轴对称图形,故本选项错误;C、菱形是中心对称图形,也是轴对称图形,故本选项正确;D、正五边形是轴对称图形,不是中心对称图形,故本选项错误.故选:C.6.(4分)已知△ABC中,D、E分别是AB、AC边上的点,DE∥BC,点F是BC 边上一点,联结AF交DE于点G,那么下列结论中一定正确的是()A.B.C.D.【解答】解:∵DE∥BC,∴△ADG∽△ABF,△AEG∽△ACF,∴=,∴,二、填空题(本大题共12题,每题4分,满分48分)7.(4分)因式分解:x2﹣9=(x+3)(x﹣3).【解答】解:原式=(x+3)(x﹣3),故答案为:(x+3)(x﹣3).8.(4分)不等式组的解集是﹣3<x<1.【解答】解:,解不等式①得:x<1,解不等式②得:x>﹣3,所以不等式组的解集是﹣3<x<1.故答案为:﹣3<x<1.9.(4分)函数y=的定义域是x≠2.【解答】解:根据题意得:x﹣2≠0解得:x≠2,故答案为:x≠2.10.(4分)方程的根是x=8.【解答】解:方程两边平方得:x+1=9,解得:x=8,经检验:x=8是方程的解.故答案是:8.11.(4分)已知袋子中的球除颜色外均相同,其中红球有3个,如果从中随机摸得1个红球的概率为,那么袋子中共有24个球.【解答】解:设袋子中共有x个球,∵红球有3个,从中随机摸得1个红球的概率为,∴=,解得:x=24(个).故答案为:24.12.(4分)如果关于x的方程x2+4x﹣k=0有两个相等的实数根,那么实数k的值是﹣4.【解答】解:∵关于x的方程x2+4x﹣k=0有两个相等的实数根,∴△=0,即42﹣4(﹣k)=0,解得k=﹣4,故答案为:﹣4.13.(4分)如果将抛物线y=x2+2x﹣1 向上平移,使它经过点A(1,3),那么所得新抛物线的表达式是y=x2+2x.【解答】解:∵将抛物线y=x2+2x﹣1 向上平移,使它经过点A(1,3),∴平移后的解析式为:y=x2+2x﹣1+h,则3=1+2﹣1+h,解得:h=1,故所得新抛物线的表达式是:y=x2+2x.故答案为:y=x2+2x.14.(4分)某校组织了主题为“共建生态岛”的电子小报作品征集活动,先从中随机抽取了部分作品,按A,B,C,D 四个等级进行评分,然后根据统计结果绘制了如图两幅不完整的统计图,那么此次抽取的作品中等级为B的作品数为48.【解答】解:∵30÷25%=120(份),∴一共抽取了120份作品,∴此次抽取的作品中等级为B的作品数120﹣36﹣30﹣6=48份,故答案为:48.15.(4分)已知梯形ABCD,AD∥BC,BC=2AD,如果,,那么=﹣(用表示).【解答】解:∵=,=,∴=﹣=﹣,∵AD∥BC,BC=2AD,∴==(﹣)=﹣.故答案为:﹣.16.(4分)如图,正六边形ABCDEF 的顶点B、C 分别在正方形AGHI 的边AG、GH 上,如果AB=4,那么CH的长为.【解答】解:正六边形的内角的度数==120°,则∠CBG=180°﹣120°=60°,∴∠BCG=30°,∴BG=BC=2,CG=BC=2,∴AG=AB+BG=6,∵四边形AGHI是正方形,∴GH=AG=6,∴CH=HG﹣CG=6﹣2,故答案为:6﹣2.17.(4分)在矩形ABCD中,AB=5,BC=12,点E是边AB上一点(不与A、B重合),以点A为圆心,AE为半径作⊙A,如果⊙C与⊙A外切,那么⊙C的半径r 的取值范围是8<r<13.【解答】解:∵四边形ABCD为矩形,∴∠B=90°,AD=BC=12,在Rt△ABC中,AC==13,∵以点A为圆心,AE为半径作⊙A,如果⊙C与⊙A外切,可得:⊙C的半径r的取值范围是8<r<13.故答案为:8<r<1318.(4分)如图,△ABC 中,∠BAC=90°,AB=6,AC=8,点D是BC的中点,将△ABD,将△ABD沿AD翻折得到△AED,联结CE,那么线段CE的长等于.【解答】解:如图连接BE交AD于O,作AH⊥BC于H.在Rt△ABC中,∵AC=8,AB=6,∴BC==10,∵CD=DB,∴AD=DC=DB=5,∵BC•AH=AB•AC,∴AH=,∵AE=AB,∴点A在BE的垂直平分线上.∵DE=DB=DC,∴点D在BE使得垂直平分线上,△BCE是直角三角形,∴AD垂直平分线段BE,∵AD•BO=BD•AH,∴OB=,∴BE=2OB=,在Rt△BCE中,EC===,故答案为三、解答题(本大题共7题,满分78分)19.(10分)计算: +(﹣2)2+9﹣(π﹣3.14)0【解答】解:原式=3+7﹣4+3﹣1=9﹣.20.(10分)解方程组:【解答】解:由①得:x+3y=0或x﹣3y=0③,由②得:x﹣y=2或x﹣y=﹣2④,由③和④组成方程组,,,,解得:,,,,所以原方程组的解为:,,,.21.(10分)已知圆O的直径AB=12,点C是圆上一点,且∠ABC=30°,点P是弦BC上一动点,过点P作PD⊥OP交圆O于点D.(1)如图1,当PD∥AB 时,求PD的长;(2)如图2,当BP平分∠OPD时,求PC的长.【解答】解:如图1,联结OD∵直径AB=12∴OB=OD=6∵PD⊥OP∴∠DPO=90°∵PD∥AB∴∠DPO+∠POB=180°∴∠POB=90°又∵∠ABC=30°,OB=6∴∵在Rt△POD 中,PO2+PD2=OD2∴∴(2)如图2,过点O 作OH⊥BC,垂足为H ∵OH⊥BC∴∠OHB=∠OHP=90°∵∠ABC=30°,OB=6∴,∵在⊙O 中,OH⊥BC∴∵BP 平分∠OPD∴∴PH=OH•co t45°=3∴.22.(10分)温度通常有两种表示方法:华氏度(单位:°F)与摄氏度(单位:℃),已知华氏度数y 与摄氏度数x 之间是一次函数关系,下表列出了部分华氏度与摄氏度之间的对应关系:摄氏度数x (℃)…0…35…100…华氏度数y (℉)…32…95…212…(1)选用表格中给出的数据,求y关于x的函数解析式;(2)有一种温度计上有两个刻度,即测量某一温度时左边是摄氏度,右边是华氏度,那么在多少摄氏度时,温度计上右边华氏度的刻度正好比左边摄氏度的刻度大56?【解答】(1)解:设y=kx+b(k≠0)把x=0,y=32;x=35,y=95 代入y=kx+b,得,解得∴y 关于x 的函数解析式为(2)由题意得:解得x=30∴在30摄氏度时,温度计右边华氏度的刻度正好比左边摄氏度的刻度大56.23.(12分)如图,AM 是△ABC的中线,点D是线段AM上一点(不与点A 重合).DE∥AB交BC 于点K,CE∥AM,联结AE.(1)求证:;(2)求证:BD=AE.【解答】证明:(1)∵DE∥AB,∴∠ABC=∠EKC.∵CE∥AM,∴∠AMB=∠ECK,∴△ABM∽△EKC,∴=.∵AM是△ABC的中线,∴BM=CM,∴.(2)证明:∵CE∥AM,∴△KDM∽△KEC,∴=,∴,又∵,∴DE=AB.又∵DE∥AB,∴四边形ABDE是平行四边形,∴BD=AE.24.(12分)已知抛物线经过点A(0,3)、B(4,1)、C(3,0).(1)求抛物线的解析式;(2)联结AC、BC、AB,求∠BAC的正切值;(3)点P是该抛物线上一点,且在第一象限内,过点P作PG⊥AP交y轴于点G,当点G在点A 的上方,且△APG与△ABC相似时,求点P的坐标.【解答】解:(1)设所求二次函数的解析式为y=ax2+bx+c(a≠0),将A(0,3)、B(4,1),C(3,0)代入,得:,解得:,所以,这个二次函数的解析式为:;(2)∵A(0,3、B(4,1)、C(3,0 )∴AC=3,BC=,AB=2,∴AC2+BC2=AB2∴∠ACB=90°,∴;(3)过点P作PH⊥y轴,垂足为H设P则H∵A(0,3)∴,PH=x,∵∠ACB=∠APG=90°∴当△APG与△ABC相似时,存在以下两种可能:①∠PAG=∠CAB则tan∠PAG=tan∠CAB=,即∴,解得:x=11,∴点P 的坐标为(11,36);②∠PAG=∠ABC则tan∠PAG=tan∠ABC=3即∴解得:x=,∴点P 的坐标为,综上所述:点P 的坐标为或(11,36).25.(14分)如图,已知△ABC 中,AB=8,BC=10,AC=12,D是AC边上一点,且AB2=AD•AC,联结BD,点E、F分别是BC、AC上两点(点E不与B、C重合),∠AEF=∠C,AE与BD相交于点G.(1)求证:BD平分∠ABC;(2)设BE=x,CF=y,求y与x 之间的函数关系式;(3)联结FG,当△GEF 是等腰三角形时,求BE的长度.【解答】解:(1)∵AB=8,AC=12,又∵AB2=AD•AC,∴,∴,∵AB2=AD•AC,∴,又∵∠BAC是公共角,∴△ADB∽△ABC,∴∠ABD=∠C,,∴,∴BD=CD,∴∠DBC=∠C,∴∠ABD=∠DBC,∴BD平分∠ABC;(2)如图,过点A作AH∥BC,交BD的延长线于点H,∵AH∥BC,∴,∵,AH=8,∴,∴BH=12,∵AH∥BC,∴,∴,∴,∵∠BEF=∠C+∠EFC,∴∠BEA+∠AEF=∠C+∠EFC,∵∠AEF=∠C,∴∠BEA=∠EFC,又∵∠DBC=∠C,∴△BEG∽△CFE,∴,∴,∴;(3)当△GEF是等腰三角形时,存在以下三种情况:1°若GE=GF,则∠GEF=∠GFE=∠C=∠DBC,∴△GEF∽△DBC,∵BC=10,DB=DC=,∴==,又∵△BEG∽△CFE,∴,即,又∵,∴x=BE=4;2°若EG=EF,则△BEG与△CFE全等,∴BE=CF,即x=y,又∵,∴x=;3°若FG=FE,则同理可得==,由△BEG∽△CFE,可得,即,又∵,∴x=.。
2023学年第二学期学业质量调研高三化学考生注意:1.本试卷满分100分,考试时间60分钟。
2.本考试设试卷和答题纸两部分,试卷包括试题与答题要求,所有答案必须涂(选择题)或写(非选择题)在答题纸上,做在试卷上一律不得分。
3.答题前,考生务必在答题纸上用水笔清楚填写姓名、准考证号。
4.本试卷的选择题,没有特别注明,为单选题,只有一个正确选项;若注明双选,有两个正确选项;若注明不定项,有1~2个正确选项,多选、错选不得分,漏选得一半分。
可能用到的原子量:H-1C-12Ti-48Ba-137O-16Mg-24一、碳达峰与碳中和(本题共20分)利用CH4超干重整CO2技术,可以得到富含CO和H2的化工原料气,对碳达峰和碳中和有重要意义,反应如下:CH4(g)+CO2(g)2CO(g)+2H2(g)∆H+247.4kJ·mol−11.反应过程中断裂的化学键属于()A.离子键B.极性共价键C.非极性共价键D.氢键2.该反应的熵变∆S0(填“>”“=”或“<”),需要在条件下进行(填“低温”或“高温”)。
3.CO2的电子式为;CO2分子中碳原子的杂化方式为杂化,1mol CO2中含有molπ键。
4.已知部分化学键的键能如下:共价键C—H H—H C=O键能(1kJ mol-⋅)413436745由此计算断裂1mol CO分子中的共价键需要吸收kJ能量。
燃料燃烧产生的二氧化碳有多种捕捉方式,在自然界中存在着二氧化碳气体与其他物质的反应过程,而实验室中一般使用碱液来吸收二氧化碳气体。
5.(双选题)向500ml2mol·L−1的NaOH溶液中通入一定体积的CO2充分反应,再向所得溶液中逐滴滴加1mol·L−1的稀盐酸。
测得产生CO2的物质的量随加入盐酸的体积变化如图所示。
则下列说法正确的是()A.整个过程中Na+没有参与化学反应,故c(Na)+保持不变B .图中的a=0.4,b=1.0C .稀盐酸滴加在0→0.2L过程中,发生的离子反应是:233CO H HCO --++=D .在A 、B 、C 、D 四处的溶液中,能与大量K +、Ba 2+、NO 3−、OH −共存的只有1处6.Na 2CO 3溶液中各离子浓度关系正确的选项有()A .3[]]Na [HCO [[]H ]OH +--+>>>B .323OH [H ][HCO ][][]H CO -+-=++C .233232[Na ][HCO ][CO ][H CO ]+--=++D .233[Na ][H ][OH ][HCO ]2[CO ]++---+=++7.向饱和Na 2CO 3溶液中通入足量的CO 2气体,会有晶体析出,写出反应的离子方程式,反应后溶液中水的电离程度(填“增大”“不变”或“减小”)。
杨浦区初三数学基础测试卷 2011.4(完卷时间 100分钟 满分 150分)一、 选择题(本大题每小题4分,满分24分)1.两个连续的正整数的积一定是 ( ) (A)素数; (B)合数; (C)偶数; (D)奇数.2.已知实数a 、b 在数轴上的位置如图所示,则下列等式成立的是 ( ) (A)a b a b +=+; (B)a b a b +=-;(C)11b b +=+;(D)11a a +=+.3.下列关于x 的方程一定有实数解的是 ( ) (A)210x ax ++=;(B)1111x x x +=--; (C)32x x m -+-=; (D)210x ax +-=.4.下列图形中,是中心对称图形的是 ( )5.根据下表中关于二次函数c bx ax y ++=2的自变量x 与函数y 的对应值,可判断二次函数的图像与x 轴( )x … -112…y … -1 47--2 47- … (A )只有一个交点; (B )有两个交点,且它们分别在y 轴两侧;(C )有两个交点,且它们均在y 轴同侧; (D )无交点.6.如图,在Rt △ABC 中,∠C =90°,AC =8,BC =6,DE ∥BC ,且AD =2CD ,则以D 为圆心DC 为半径的⊙D 和以E 为圆心EB 为半径的⊙E 的位置关系是 ( )(A )外离;(B )外切;(C )相交; (D )不能确定.二、 填空题(本大题每小题4分,满分48分) 7.用代数式表示“a 的相反数与b 的倒数的和的平方”: . 8.将11032,8,(2)a b c π-=-==-从小到大排列,并用不等号连接: . 9.若最简二次根式22x -与21x +是同类二次根式,则x = .10.如果一个关于x 的一元一次不等式组的解集在数轴上的表示如图所示,那么该不等式组A BC ED (第6题图)O a b 1的解集是 .11.如果点P (m ,1-2m )在第四象限,那么m 的取值 范围是 . 12.若反比例函数(0)ky k x=≠的图像在第二、四象限,则一次函数y kx k =+的图像经过 象限.13.11()A x y ,、22()B x y ,是一次函数2(0)y k x k =+>图象上不同的两点,若1212()()t x x y y =--,则t 0(填“<”或“>”或“≤”或“≥”). 14.正十二边形的中心角等于 度.15.如图,在ABCD 中,已知AB =9㎝,AD =6㎝,BE 平分∠ABC 交DC 边于点E ,则DE 等于 ㎝.16.如图,在ABC ∆中,记b AC a AB ==,,则BC = (用向量a 、b 来表示). 17.如图,在矩形ABCD 中,AD =4,DC =3,将△ADC 绕点A 按逆时针方向旋转到△AEF (点A 、B 、E 在同一直线上),则C 点运动的路线的长度为 . 18.如图,EF 是△ABC 的中位线,将△AEF 沿中线AD 的方向平移到△A 1E 1F 1,使线段E 1F 1落在BC 边上,若△AEF 的面积为7cm 2,则图中阴影部分的面积是 cm 2.三、 解答题(第19~22题每题10分,第23~24题每题12分,第25题14分,满分78分)19.先化简,再求值:223222x x x x x x x x-----+ ,其中3x =20.解方程组:226320x y x xy y +=⎧⎨-+=⎩21.在一次课外实践活动中,同学们要知道校园内A B ,两处的距离,但无法直接测得。
崇明县2011年高考模拟考试试卷高三数学(理科)班级:___________姓名:____________ 考生注意:1. 每位考生应同时领到试卷与答题纸两份材料,所有解答必须写在答题纸上规定位置,写在试卷上或答题纸上非规定位置一律无效;2. 答卷前,考生务必将姓名、准考证号码等相关信息在答题纸上填写清楚;3. 本试卷共23道试题,满分150分,考试时间120分钟。
一、填空题(本大题共14小题,每小题4分,满分56分,只需将结果写在答题纸上) 1、方程2log (34)1x -=的解x = .22、函数44cos sin y x x ππ=-的最小正周期T = .13、已知z 是方程2(1)z i z -=+的复数解,则z =4、若直线l 过点(0,1)P ,且方向向量为(2,1)-,则直线l 的方程为 (用直线方程的一般式表示)220x y +-=5、二项式6(x -的展开式中常数项等于15 .(用数字作答)6、执行右图所示的程序框图,若输入10x =,则输出y 的值等于 114-7、函数11()(1)2f x x xx=≥的值域为 .(,1]-∞8、已知等差数列{}na 的318156,18S S S =--=,则18S = .369、已知直线l 10、若一个无穷等比数列{}na 的前n 项和为nS ,且1lim 2nn S→∞=,则首项1a 取值范围是________.11(0,)(,1)2211、圆柱形容器内部盛有高度为8cm 的水,若放入三个相同的实心铁球(球的半径与圆柱的底面半径相同)后,水恰好淹没最上面的球,则球的半径等于(第6题图)AB CD cm.412、已知双曲线22118x y m m -=+(0)m >的一条渐近线方程为y ,它的一个焦点恰好在抛物 线2y ax =的准线上,则a = .24a =±13、如图:在三角形ABC 中,0BA AD ⋅=,1,AD BC =,则AC AD ⋅=.14、设函数2()1f x x =+,若关于x 的不等式2(4()4()(1)xf f m m f x f x m+≤+-对任意3,2x ⎡⎫∈+∞⎪⎢⎣⎭恒成立,则实数m 的取值范围是.,,22⎛⎫-∞-+∞ ⎪ ⎪⎝⎦⎣⎭二、选择题(本大题共4小题,满分20分,每小题给出四个选项,其中有且只有一个结论是正确的,选对并将答题纸对应题号上的字母涂黑得5分,否则一律得零分)15、从总体中抽取的一个样本中共有五个个体,其值分别为,0,1,2,3a ,若该样本的平均值为1,则总体方差的点估计值等于………………………………………………………………( )A 、52BCD 、216、命题P:“12x-<”,命题Q:“213x x-<-”.则P 是Q的……………………………()A、充分非必要条件B、必要非充分条件C、充要条件D、既非充分又非必要条件17、函数()23xf x x=+的一个零点所在的一个区间是………………………………………()A、(1,2)B、(0,1)C、(1,0)-D、(2,1)--18、一个少年足球爱好者报考某知名足球学校。
参考答案第I卷(共60分)一、单选题(共60分,每小题只有一个正确选项)1 2 3 4 5 6B B BCD A(一)2分题(共21题)7 8 9 10 11 12 13 14 15 16 17A B C D B A C B C B D18 19 20 21 22 23 24 25 26 27B A BCD B A B C D28 29 30 31D C C B第Ⅱ卷(共90分)二、综合分析题(共90分)(四)分析有关微生物的资料,回答问题。
(15分)32.2、3 1 磷脂是生物膜的主要成分,原核生物(细菌)没有具膜细胞器。
33.芽体孢子34.小型环状的DNA分子一部分DNA集中在细胞中央,构成拟核;一部分独立于拟核之外构成质粒(意思对即给分)。
35. 1 抗原多为蛋白质、多糖和脂类,细菌的表面有特殊的糖蛋白和糖脂(答出细菌的表面有特殊的糖蛋白即给分)36.高压灭菌(高压蒸汽灭菌)将未接种的培养基在适宜的温度下放置适宜的时间,观察培养基上是否有菌落产生。
37.碳 6 不加氮源(N)在培养基中加入抗生素(青霉素)(五)有关光合作用和呼吸作用的问题。
(10分)38. 光合 4639.在一定的温度范围内,光合作用强度随着温度的升高而增强 23暗反应过程中的酶的数量和酶的最大活性40.28~34℃曲线(2分,要求:写出净光合速率关键值(如图)1分曲线走势符合1分)41. 在低于P光照强度下B植物光能利用率比A植物的高,在高于P光照强度下A植物光能利用率比B植物的高。
A(六)有关进化问题。
(8分)42. 亲缘关系越近的生物,组成细胞色素C的氨基酸的差别就越小,反之则越大。
胚胎学证据、比较解剖学证据、古生物化学证据。
43.(不答两栖类,不给分)44.基因库遗传45. 突变(变异)自然选择基因交流(七)有关人体内环境与自稳态的问题。
(14分)46.肾脏47. ①甲状腺激素 a48.①大量出汗导致血浆渗透压上升,引起下丘脑神经内分泌细胞大量合成分泌抗利尿激素;抗利尿激素可通过促进B中肾小管和集合管对水分的重吸收而使血浆渗透压下降,尿量减少(2分)。
2024年上海市崇明区中考化学二模试卷相对原子质量:H-1C-12O-16Na-23S-32Cu-64Ca-40 Mg-24K-39一、选择题(共20分)21~34每题只有1个正确选项,每题1分,共14分。
35~37每题有1~2个正确选项,每题2分,共6分。
有2个正确选项的,选对1个得1分,多选或错选得0分。
1.(1分)下列物质的组成中含有原子团的是( )A.Mg B.MgO C.MgCl2D.MgCO32.(1分)属于纯净物的是( )A.食盐水B.红糖水C.蒸馏水D.矿泉水3.(1分)对氯化钠进行焰色反应,火焰呈( )A.紫色B.黄色C.绿色D.蓝色4.(1分)小麦适合在弱酸性土壤中生长,下列土壤的pH最适合小麦生长的是( )A.6.3B.8.5C.9.5D.10.25.(1分)MnO2中锰的化合价是( )A.﹣4B.﹣2C.+2D.+46.(1分)在水中能形成溶液的是( )A.铜粉B.淀粉C.白糖D.麻油7.(1分)以下属于结晶水合物的是( )A.氯化钠B.胆矾C.硝酸钾D.碳酸钙8.(1分)能表示两个氧分子的是( )A.2O B.O2C.2O2D.H2O29.(1分)物质的用途错误的是( )A.氦气可填充飞艇B.烧碱降低土壤酸性C.活性炭吸附异味D.一氧化碳用作燃料10.(1分)用电解水实验探究水的元素组成,有关说法错误的是( )A.a管和b管中气体的体积比约为1:2B.a管中的气体能使燃着的木条燃得更旺C.b管中的电极与电源正极相连D.该实验证明水由氢、氧两种元素组成11.(1分)知识归纳正确的是( )A.使澄清石灰水变浑浊的物质一定是CO2B.保持物质化学性质的微粒一定是分子C.有盐和水生成的反应一定是中和反应D.金属与稀盐酸反应后溶液的质量一定增加12.(1分)使用天然气做饭,点火后,发现炉火火焰呈现黄色,锅底出现黑色,这时需要调大灶具的进风口;使用完毕,关闭开关,火焰熄灭。
有关说法错误的是( )A.天然气属于化石燃料,是不可再生能源B.天然气的主要成分是甲烷,甲烷属于有机物C.调大进风口的目的是提供足够的空气,使燃烧更充分D.关闭开关火焰熄灭,原因是温度降到了着火点以下13.(1分)类似金刚石结构的物质“T﹣碳”(化学式为C),在航空航天材料领域拥有广泛的应用前景。
杨浦区(崇明县)2010学年度第二学期基础测试初三英语练习卷2011.4.8(完卷时间:100分钟,答案一律写在答题纸上)Part 2 Vocabulary and GrammarV. Choose the best answer (选择最恰当的答案):(共26分)31. Kitty is such ______honest student that she is often praised by her teachers.A) a B)an C)the D)/32. My wish is to become a scientist when I grow up. What is______, Betty?A) yours B) your C)you D) yourself33. It's getting warmer and warmer. Do you still get up______6:30 every day?A) on B)in C)at D)by34. I'm afraid this pair of trousers is too small. Would you please show me ______ pair?A) the other B) other C) others D) another35.Since I'm very familiar _____this area, they expect me to show them around.A) from B)to C)with D)for36. The foreign visitor could speak only _____ Chinese, but he managed to communicate with us.A) few B) little C)a few D)a little37. ---You look so happy!---Mary says I'm cool. ______has ever told me that before.A) Somebody B) Anybody C) Nobody D) Everybody38.I telephoned Jane just now, but she wasn't in. I had to leave her a(n)______.A) message B) advice C) information D) paper39.______it is! The government is planning to build more low-cost houses for its people.A) How good news B) What good news-C) How good a news D) What a good news40. It is reported that more than people have been killed in this big earthquake.A) two thousands B) thousands of C) thousand of D) two thousand41. Because of nuclear leakage (核泄漏), people and food arriving in China from Japan _______ receive strict checks for radiation (辐射).A) must B)may C)can D)ought42. The pizza they offered us tasted______, and we all wanted to have some more.A) wet!B) awful C)good D) wonderfully43. In winter the ______it snows, the happier the children will feel.A) heavy B) more heavily C) heavily D) heavier44. When I got to the classroom just now. I found that Tom ______on a math problem.A) worked B) works C) will work D) was working45. A record number of people ______Shanghai An Museum since it charged no entrance fee (费) in early March.A) have visited B) will visit C) had visited D) visited46.---Alice, where did you go last night?---I ______to go to Tom's birthday party.A) asked B) have asked C) have been asked D) was asked47. You had better let John ______milk and bread for breakfast himself. He's ten years old now.A) buys B)buy C) to buy D) buying48.Don't go out, ______you'll be caught in the rain.A) and B) since C)or D) until49- Susan finally became a popular singer after she practiced ______ for years.A) sing B) to sing C)sang D) singing50 If you travel around the world, you will be surprised at_______.A) how different the foreign customs are B) how the foreign customs are differentC) how different are the foreign customs D) how are the foreign customs different51. More and more foreigners are living and working in Shanghai at present. The underlined part means "______".A) at a time ,B) at the moment C) just now D) from time to time52 Father lost temper after he was told her daughter stole a mobile phone from her desk mate. The underlined part means "______”.A) became angry B) held his breath C) went wrong D) ran away53. Many Junior Three students ______their hobbies because of their busy school work.A) stay up B) take up C) give up D) put up54. Mike's parents were worried that he ______too much time chatting online.A) paid B)cost C)took D) spent55. ---Shall I get you some more milk?---______I have had enough.A) No. you needn't B) I'm afraid you can'tC) I'm glad you like it.D) I'm very' happy.56. ---Would you mind my opening the window?---______.A) Never mind.B) Certainly not.C)No. I wouldn't D) Yes. I'd love to.VI. Complete the sentences with the given words in their proper forms (用括号中所给单词的适当形式完成下列句子,每空格限填一词):(共8分)57. It is necessary for everyone to brush his. ________ after each meal. (tooth)58. I have bought a new flat and it's on the ________floor of the building.(eight)59. As middle school students, we should know how to look after________. (us)60. The student missed the ________tour around Sheng Long Agricultural Park. (enjoy)61.We received Peter's _______and went to his birthday party happily, (invite)62. The serious fire _______ destroyed the whole building last November. (complete)63. It was _________for such a little girl to solve this hard problem in ten minutes, (usual)64. Make a plan for your future study, and you will ________in the end. (successful)VII. Rewrite the following sentences as required.(根据所给要求,改写下列句子。
上海市杨浦区2011年第二学期基础考试化学试卷可能用到的相对原子质量:H—1 C—12 N—14 O—16 Na—23 Cl—35.5 Ca—40一、单项选择题(每题只有一个选项符合题意,共24小题,每题1分,共24分)1、下列变化中,属于物理变化的是A.米饭变馊B.火药爆炸C.湿衣晾干D.铁锅生锈2、下列选项中不属于化学研究的是A.研发氢能源B.合成新材料C.编写电脑程序D.用石油生产化工原料3、镁的下列性质中,属于化学性质的是A.导电性B.导热性C.可燃性D.延展性4、下列物质的化学式书写正确的是A.氧化镁:Mg2O B.氢氧化钠:NaOHC.氢氧化钙:Ca(HO)2D.硫酸钾:KSO45、厨房中的下列物质与水充分混合后,不能..形成溶液的是A.花生油B.白糖C.纯碱D.食盐6、据报道,美国宇航局的专家发明了“月球制氧机”,这种“月球制氧机”利用聚焦太阳能产生的高温使月球土壤发生化学反应制取氧气,据此可推测月球土壤中一定含有A.氧元素B.氧气C.水D.氯酸钾7、下列仪器一般需经过磨砂处理的是A.试管B.烧杯C.集气瓶D.量筒8、我国交通法规明确禁止酒后驾车。
交通警察使用的一种酒精检测仪中装有重铬酸钾(K2Cr2O7),它对酒精非常敏感,该化合中铬元素(Cr)的化合价为A.+3 B.+4 C.+5 D.+69、下图所示的实验方法或操作,正确的是10、下图X、Y、Z表示的是水、石灰水、稀盐酸的近似pH。
下列判断错误的是A.X是稀盐酸B.Y是水C.Z是石灰水D.无法确定X、Y、Z 11、用数轴表示某些化学知识直观、简明、易记。
下列数轴表示的化学知识错误的是12、下列物质中,能作磷肥的是A.NH4HCO3B.CO(NH2)2C.K2CO3D.Ca(H2PO4)2 13、根据所学知识,我们可以从“电解水实验”中获得更多的信息和推论。
下列说法中正确的是A.水是由氢分子和氧分子构成的B.水是由氢原子和氧原子直接构成的C.试管a、b中所得气体的质量比约为2:1D.试管a、b中所得气体的体积比约为2:114、实验室有两瓶失去标签的溶液,一瓶是稀盐酸,另一瓶是氢氧化钠溶液,下列试剂中不能将它们鉴别出来的是A.酚酞试液B.镁条C.氯化钾溶液D.氯化铜溶液15、下列对实验现象的描述正确的是A.铜片放入盐酸中有气泡产生B.硫在氧气中燃烧时,发出蓝紫色火焰C.铁在空气中燃烧火星四射D.紫色石蕊试液使盐酸变红16、胆矾是一种蓝色晶体,化学式是CuSO4·5H2O,胆矾受热易失去结晶水,成为白色的无水硫酸铜,工业上精炼铜、镀铜等都要用到胆矾。
上述对胆矾的描述中,没有涉及的是A.物理性质B.制法C.用途D.化学性质17、比较我们学过的化学反应,你认为化学反应前后一定发生改变的是A.物质的种类B.物质的状态C.元素的种类D.元素的化合价18、已知20℃时食盐的溶解度为36g/100g水。
20℃时把20g食盐放入50g水中,充分搅拌后,所得饱和溶液的质量是A.70g B.69g C.68g D.67g19、下列装置能达到对应实验目的的是20、下列金属活动性由强至弱的顺序及元素名称、符号均正确的一组是A.铁Fe>银Ag>铜Cu B.镁Mg>铝Al>锌ZNC.铁Fe>铜Cu>贡Hg D.钙Ca>钠Na>镁Mg21、下列物质露置于空气中,质量不变的是A.石灰水B.浓盐酸C.氯化钠D.生石灰22、某工厂拟选用下列物质处理含硫酸的废水。
A.NaCl B.CaCO3C.Ca(OH)2D.NaOH 23、加热氯酸钾和二氧化锰的混合物制氧气。
下列各图正确的是24、U形管中是滴有酚酞试液的蒸馏水,向左、右两管中分别同时逐滴滴加一定量的氢氧化钠稀溶液和稀盐酸(如右图所示)。
下列说法正确的是A.开始时左边溶液呈蓝色,右边溶液呈红色B.开始时左边溶液呈无色,右边溶液呈红色C.充分反应后U形管中溶液可能呈红色D.充分反应后U形管中溶液一定呈无色二、填空题(本题共41分)25、请按要求选择用化学用语表示或化学式填空:(1)①磷元素 ②3个铝原子 ;(2)空气中体积分数最大的气体 ;(3)可用于人工降雨和灭火的物质 ;(4)可用于制肥皂、造纸等工业的碱 ;(5)能用于金属除锈的重要化工原料 ;(6)用来降低土壤酸性的物质 。
26、用下列序号填空:①烧杯 ②试管 ③胶头滴管 ④燃烧匙 ⑤蒸发 ⑥过滤 ⑦搅拌 ⑧量取,能直接加热的玻璃仪器 ;吸取或滴加少量液体的仪器 ;由食盐水制得食盐晶体的操作 ;取用6.8mL 某溶液的操作 。
27、写出下列反应的化学方程式:(1)木炭在氧气中充分燃烧生成二氧化碳_________________ ;(2)在加热条件下氢气和氧化铜反应生成铜和水_______________ ;(3)稀硫酸和硝酸钡溶液反应_______________ ;(4)用CO 高温下还原赤铁矿(主要成份Fe 2O 3)的化学方程式为;(5)金属镁着火不能用CO 2灭火,请用化学方程式表示其原因 ,反应基本类型是 ;(6)用“ ”表示氢原子,“ ”表示氧原子,则右图所示的化学反应方程式为:;(7)写出用CaCO 3、H 2O 、Na 2CO 3为原料制取NaOH 的各步反应的化学方程式:第一步:分解反应 ;第二步:化合反应 ;第三步:复分解反应 。
28、上海医药商业行业协会发布防治甲型H1N1流感消毒剂中有过氧乙酸。
右图为某市出售的过氧乙酸标签上的部分文字说明,请回答:(1)一瓶这种溶液含过氧乙酸溶质 g 。
(2)过氧乙酸中碳、氢、氧原子个数比是 。
(3)过氧乙酸的摩尔质量为,1 mol过氧乙酸含摩尔氧原子。
(4)该消毒液共有元素。
29、已知X是有毒且不溶于水的气体,Y是不支持燃烧的气体,Z是不溶于水的固体,X、Y、Z之间有如下转化关系。
请回答下列问题。
(1)写出X的化学式,灼热碳层中的碳在化学反应中做剂;(2)写出Z和稀盐酸反应生成Y的化学方程式:;(3)“物质的组成与结构决定物质的性质”是重要的化学思想。
气体X、Y都含有碳元素和氧元素,但它们的物理性质、化学性质都不同。
请举出X、Y性质不同的一个例子。
30、如图是甲、乙两种物质的溶解度曲线,回答下列问题:(1)从甲物质的溶解度曲线可以得到哪些信息(请写出其中的一条)___________________________ 。
(2)t1℃时,甲、乙两种物质的溶解度较大的是___________。
(3)t1℃时,将20g甲物质放入50g水中,充分搅拌能否全部溶解____________(填“能”、“不能”或“无法判断”)。
(4)将一定量t2℃时甲物质的饱和溶液降温到t1℃时,该过程中没有发生改变的是___________(填序号)A.溶质质量B.溶液质量C.溶剂质量D.溶质的质量分数31、现有一包白色粉末,可能由NaCl、Na2SO4、Na2CO3、CuSO4中的一种或几种组成。
现做如下实验:①取少量粉末,加水溶解得无色溶液;②另取少量粉末,滴加稀盐酸,无明显现象。
请回答:(1)由实验①可确定原粉末中一定没有;由实验②可确定原粉末中一定没有。
(2)根据上述实验现象,得出原粉末中可能含有的物质是、。
(3)为进一步确定原粉末的组成,另取少量粉末按如下图所示进行实验:[在AgNO3、Ba(NO3)2、BaCl2溶液中选择两种作为A、B试剂,且A、B中的金属部分不同]原粉末的成分是;试剂A为;试剂B为。
(若有多种情况,只需写出其中一种)三、实验题(本题共30分)32、下图是常见实验仪器或装置。
请回答下列问题:(1)仪器a的名称是。
(2)利用大理石和稀盐酸制取CO2应选仪器(填序号)。
(3)用CO还原铁矿石应选仪器(填序号);加热前应,目的是,然后用酒精灯预热,再对准固体加热;尾气应。
(4)右图为某同学的家庭实验,该装置的右边部分相当于上图中的仪器(填序号)的组合;该实验左边部分在操作上的优点是。
33、请参与某化学学习小组进行研究性学习的过程,并协助完成相关任务:(1)为了验证铜、银、镁、铁的金属活动性顺序,小明同学设计如下实验方案:a.将金属镁和铁分别放入到稀酸溶液中;b.将铜片放入到硝酸银溶液中。
①在步骤a中,所控制的实验条件是。
②小红同学认为,小明同学的实验方案不足以说明铜、银、镁、铁的金属活动性顺序,还需要进行一个实验,该实验的实验步骤是。
(2)小王同学选择“镁丝和硫酸反应的快慢与什么因素有关”的课题开展探究。
下表是他分别用相同质量的镁丝和足量稀硫酸反应的三组实验数据:① 实验Ⅱ和Ⅲ表明:该反应快慢与 有关。
② 能表明硫酸的质量分数对反应快慢有影响的实验编号是: 和 。
③ 如果实验Ⅰ中硫酸的质量分数改为4%,请推出镁丝消失的时间(用t 表示)的取值范围 。
④ 该实验除了用镁丝消失的时间来衡量反应的快慢外,你还能提出新的方法来衡量反应的快慢吗?方法 。
34、用某种粗盐进行提纯实验,步骤如下图所示。
请回答下列问题:(1)步骤①和②的操作名称是 。
(2)步骤④加热蒸发时要用到玻璃棒不断搅拌,这是为了防止 。
(3)猜想和验证:35、某课外兴趣小组设计利用废旧干电池中的锌皮和浓盐酸以及下图所示装置来制取干燥、纯净的氢气,并验证气体中的杂质。
(1)实验中看到B中无水硫酸铜变蓝色,这说明产生的气体中含有杂质(填化学式)。
除此以外,还可能含有的杂质气体是(填名称),为了检验该杂质,可将E装置连接到上述装置中(填序号)之间,气体从(填“a”或“b”)进入装置E,E中所放试剂为,观察到的现象为。
(2)C装置的作用是。
(3)此实验收集氢气的下列方法中,最合理的是(填序号)。
A.向上排空气法B.用干瘪气球收集法C.排水法四、计算题(本题共5分)36、某省生产的某种钙盐的配料表如下:氯化钠、食用碳酸钙、碘酸钾。
为了测定此盐中的钙元素含量,取10g这种盐溶于水,加入足量盐酸,生成0.003moL二氧化碳。
请计算:(1)在盐酸中参加化学反应的溶质HCl的物质的量。
(2)此加钙食盐中钙元素的质量分数。
2011学年度第二学期基础考试初三化学参考答案2011.4一、单项选择题(共24分)二、填空题 (共41分)25、(1) ①P ③3Al(2)H 2 (3)CO 2 (4)NaOH (5))H 2SO 4 (6))Ca(OH )226、 ② ③ ⑤ ⑧27、(1)C+O 2−−→−点燃CO 2 (2)H 2+CuO −−→−加热Cu+H 2O(3)H 2SO 4+Ba(NO 3)2→BaSO 4↓+2H NO 3 (4)Fe 2O 3+3CO −−→−高温2Fe+3CO 2(5) 2Mg + CO 2−−→−点燃2MgO + C (6)2H 2O 2−−−→催化剂2H 2O+O 2↑ (7)① CaCO 3−−→−高温CaO + CO 2↑② CaO+H 2O →Ca(OH)2 ③ Ca(OH)2+Na 2CO 3→2NaOH +CaCO 3↓28、(1) 200 (2)2﹕3:﹕4 (3)76g/moL 3 (4)329、(1)CO(2)CaCO 3+2HCl →CaCl 2+H 2O+ CO 2↑(3)碳(C) 氧(O) CO 有毒,CO :无毒(或其他正确答案)30、(1)甲的溶解度随着温度的升高而变大(其他合理答案也可)(2)乙 (3)不能 (4)C31、(1) CuSO 4 Na 2CO 3 (2)NaCl Na 2SO 4(3)Na 2SO 4 Ba(NO 3)2 AgNO 3三、实验题(共30分)32、(1)长颈漏斗 (2)CF(3)ABG 先通入C0一会儿 排尽玻璃管中的空气 点燃(或用塑料袋收集)(4)BDH 或ABG 可随时停止反应(类似意思只要合理均给分)33、(1)金属的形状和酸的种类、浓度铜放入稀酸中(2)温度①②300<t<500 收集等量氢气所需时间34、(1)过滤(2)溶液局部过热而飞溅(3)猜想l:产生气泡,烧杯内壁有白色固体生成猜想Ⅱ:盐酸或硝酸猜想Ⅱ不成立猜想Ⅲ:加BaCl2或Ba(NO3)2 溶液有白色沉淀生成35、(1)H2O 氯化氢B、C b 硝酸银溶液硝酸银溶液中有白色沉淀生成(2)吸收HCl气体(3)B四、计算题(本题共5分)36、解:设参加反应的HCl物质的量为x(1)CaCO3+2HCl CaCl2+H2O+ CO2↑1 2 1z x 0.003z=0.003moL 1分x=0.003moL 1分m(CaCO3)=0.003×100=0.3g 1分m(Ca)=0.3×40100×100%=0.12g 1分此加钙食盐中钙元素的质量分数=0.1210×100%=1.2%1分。